05/11/2011: Difference between revisions
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Created page with 'Below my calibration line for n's detector with HAMAMATSU PMT (-1500 V): 100 px' |
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[https://wiki.iac.isu.edu/index.php/N%27s_detector_calibration Go Back] | |||
[[File:Det1 callibration.png | | |||
Because is something wrong I decided to measure the counts rate as function of threshold energy. Maybe my threshold was incorrect. | |||
Below are my results for n's detector with HAMAMATSU PMT (-1500 V): | |||
[[File:Det1 callibration.png | 1000 px]] | |||
So it looks like my previous threshold value (-500 mV) was not good. Let's set it up the -200 mV. And let's see does the n's detector sensitive to the source. The same set up and distances as before. | |||
{| border="1" cellspacing="0" style="text-align: center; width: 800px; height: 100px;" | |||
! scope="col" width="50" | | |||
! scope="col" width="50" | counts/sec (5 min test), no source | |||
! scope="col" width="50" | counts/sec (5 min test), with source on the top of PS1 | |||
|- | |||
!n's | |||
|19.89<math>\pm</math>0.26 (total 5966 cnts) || 58.84<math>\pm</math>0.29 (total 17652 cnts) | |||
|} | |||
So now we see the source. The ratio are: | |||
<math>\frac{Rate_{source}}{Rate_{w/source}} = \frac{58.84}{19.89} = 2.96 </math> | |||
Latest revision as of 04:59, 12 May 2011
Because is something wrong I decided to measure the counts rate as function of threshold energy. Maybe my threshold was incorrect.
Below are my results for n's detector with HAMAMATSU PMT (-1500 V):
So it looks like my previous threshold value (-500 mV) was not good. Let's set it up the -200 mV. And let's see does the n's detector sensitive to the source. The same set up and distances as before.
| counts/sec (5 min test), no source | counts/sec (5 min test), with source on the top of PS1 | |
|---|---|---|
| n's | 19.89[math]\displaystyle{ \pm }[/math]0.26 (total 5966 cnts) | 58.84[math]\displaystyle{ \pm }[/math]0.29 (total 17652 cnts) |
So now we see the source. The ratio are:
[math]\displaystyle{ \frac{Rate_{source}}{Rate_{w/source}} = \frac{58.84}{19.89} = 2.96 }[/math]