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Construct a Schmitt Trigger using the 741 Op Amp
 
Construct a Schmitt Trigger using the 741 Op Amp
  
==Draw the Schmitt Trigger circuit you constructed.  Identify the values of all components==
+
=Draw the Schmitt Trigger circuit you constructed.  Identify the values of all components=
  
 
[[File:Schmitt trigger 01.png | 450 px]]
 
[[File:Schmitt trigger 01.png | 450 px]]
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# <math>R_1 = (1.01\pm0.01)\ k\Omega</math>
 
# <math>R_1 = (1.01\pm0.01)\ k\Omega</math>
 
# <math>R_2 = (1.01\pm0.01)\ k\Omega</math>
 
# <math>R_2 = (1.01\pm0.01)\ k\Omega</math>
# <math>R_3 = (5.10\pm0.01)\ k\Omega</math>
+
# <math>R_3 = (5.10\pm0.05)\ k\Omega</math>
 
# <math>\mbox{OP}\ \mbox{AMP}\ 741</math>
 
# <math>\mbox{OP}\ \mbox{AMP}\ 741</math>
 
# <math>V_{ref} = (+11.90\pm0.01)\ V</math>
 
# <math>V_{ref} = (+11.90\pm0.01)\ V</math>
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# <math>V_{ee} =  (-12.11\pm0.01)\ V</math>
 
# <math>V_{ee} =  (-12.11\pm0.01)\ V</math>
  
==Graph <math>V_{out}</math> as a function of <math>V_{in}</math>.  Is there a hysteresis loop?==
+
=Graph <math>V_{out}</math> as a function of <math>V_{in}</math>.  Is there a hysteresis loop?=
  
 
If the input voltage goes up my measured output voltages are:
 
If the input voltage goes up my measured output voltages are:
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In the plot below I overplay the output voltages vs. input voltages for both cases as input voltage goes up (black line) and down (red line):
 
In the plot below I overplay the output voltages vs. input voltages for both cases as input voltage goes up (black line) and down (red line):
  
[[File:Plot hysteresis.png | 800px]]
+
[[File:Plot hysteresis 01.png | 800px]]
  
  
 
As we can clearly see there is the hysteresis loop. The reason for this loop is because the threshold voltages depends from output voltage. If the output voltage is high the threshold voltage is higher than for the case if output voltage is low.
 
As we can clearly see there is the hysteresis loop. The reason for this loop is because the threshold voltages depends from output voltage. If the output voltage is high the threshold voltage is higher than for the case if output voltage is low.
  
==Identify the input voltage threshold levels at which a <math> V_{in}</math> will produce <math>V_{out} \approx V_{cc}</math>==
+
=Identify the input voltage threshold levels at which a <math> V_{in}</math> will produce <math>V_{out} \approx V_{cc}</math>=
  
==Compare the threshold values to what is expected.==
+
From my measurements above:
  
The theory does say (ch. 10.19 The Schmitt Trigger R. Simpson "Introductory electronics for scientists and engineers"):
+
1) if the output voltage is high (<math>(11.06\pm 0.01)\ V</math>) my threshold voltage is:
 +
 
 +
<math>V = (6.38\pm 0.01)\ V</math>
 +
 
 +
2) if the output voltage is low (<math>(10.53\pm 0.01)\ V</math>) my threshold voltage is:
 +
 
 +
<math>V^' = (4.48\pm 0.01)\ V</math>
 +
 
 +
=Compare the threshold values to what is expected.=
 +
 
 +
The theory does say (ch. 10.19 The Schmitt Trigger of R. Simpson "Introductory electronics for scientists and engineers"):
  
 
  <math>V_2 = \frac{R_{123}}{R_2}V_{ref} + \frac{R_{123}}{R_3}V_{out}</math>
 
  <math>V_2 = \frac{R_{123}}{R_2}V_{ref} + \frac{R_{123}}{R_3}V_{out}</math>
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# <math>V_{out_1} =  (+11.06\pm0.01)\ V</math>
 
# <math>V_{out_1} =  (+11.06\pm0.01)\ V</math>
# <math>V_{out_2} =  (-10.54\pm0.01)\ V</math>
+
# <math>V_{out_2} =  (-10.53\pm0.01)\ V</math>
  
 
Substituting all quantities in the formulas above:
 
Substituting all quantities in the formulas above:
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  <math>V_2 = \frac{(0.459\pm 0.003)\ k\Omega}{(1.01\pm 0.01)\ k\Omega}(11.90\pm 0.01)\ V + \frac{(0.459\pm 0.003)\ k\Omega}{(5.10\pm 0.05)\ k\Omega}(11.06\pm 0.01)\ V</math>
 
  <math>V_2 = \frac{(0.459\pm 0.003)\ k\Omega}{(1.01\pm 0.01)\ k\Omega}(11.90\pm 0.01)\ V + \frac{(0.459\pm 0.003)\ k\Omega}{(5.10\pm 0.05)\ k\Omega}(11.06\pm 0.01)\ V</math>
  
  <math>V_2^' = \frac{(0.459\pm 0.003)\ k\Omega}{(1.01\pm 0.01)\ k\Omega}(11.90\pm 0.01)\ V - \frac{(0.459\pm 0.003)\ k\Omega}{(5.10\pm 0.05)\ k\Omega}(10.54\pm0.01)\ V</math>
+
  <math>V_2^' = \frac{(0.459\pm 0.003)\ k\Omega}{(1.01\pm 0.01)\ k\Omega}(11.90\pm 0.01)\ V - \frac{(0.459\pm 0.003)\ k\Omega}{(5.10\pm 0.05)\ k\Omega}(10.53\pm0.01)\ V</math>
  
 
and doing math and propagating errors we end up with the following predicted threshold voltages:
 
and doing math and propagating errors we end up with the following predicted threshold voltages:
  
1) If the output voltage is high the threshold voltage are:  
+
<math>V_2(\mbox{theory}) = (6.41\pm 0.07)\ V\ \ (\mbox{if}\ \mbox{the}\ \mbox{output}\ \mbox{is}\ \mbox{high})</math>
 +
 
 +
<math>V_2^'(\mbox{theory}) = (4.47\pm 0.06)\ V\ \ (\mbox{if}\ \mbox{the}\ \mbox{output}\ \mbox{is}\ \mbox{low})</math>
 +
 
 +
 
 +
They are in total agreement with measured ones within the calculated error above:
 +
 
 +
<math>V(\mbox{measured}) = (6.38\pm 0.01)\ V\ \ (\mbox{if}\ \mbox{the}\ \mbox{output}\ \mbox{is}\ \mbox{high})</math>
 +
 
 +
<math>V^'(\mbox{measured}) = (4.48\pm 0.01)\ V\ \ (\mbox{if}\ \mbox{the}\ \mbox{output}\ \mbox{is}\ \mbox{low})</math>
 +
 
 +
=low-frequency input=
 +
 
 +
Below my digital scope picture of how the Schmitt Trigger output signal behaves with respect to low frequency input signal.
 +
 
 +
[[File:Tek00047.png | 700px]]
  
<math>V_2 = (6.41\pm 0.07)\ V </math>
 
  
1) If the output voltage is low the threshold voltage are:
+
As we can see it flips perfectly up and down if the input signal exceeds the calculated above threshold values.
  
<math>V_2 = (4.46\pm 0.06)\ V </math>
 
  
  

Latest revision as of 06:09, 28 April 2011

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Construct a Schmitt Trigger using the 741 Op Amp

Draw the Schmitt Trigger circuit you constructed. Identify the values of all components

Schmitt trigger 01.png

To construct the circuit above I am going to use the following components and voltages:

  1. [math]R_1 = (1.01\pm0.01)\ k\Omega[/math]
  2. [math]R_2 = (1.01\pm0.01)\ k\Omega[/math]
  3. [math]R_3 = (5.10\pm0.05)\ k\Omega[/math]
  4. [math]\mbox{OP}\ \mbox{AMP}\ 741[/math]
  5. [math]V_{ref} = (+11.90\pm0.01)\ V[/math]
  6. [math]V_{cc} = (+11.90\pm0.01)\ V[/math]
  7. [math]V_{ee} = (-12.11\pm0.01)\ V[/math]

Graph [math]V_{out}[/math] as a function of [math]V_{in}[/math]. Is there a hysteresis loop?

If the input voltage goes up my measured output voltages are:

Table input up.png

If the input voltage goes down my measured output voltages are:

Table input down.png


In the plot below I overplay the output voltages vs. input voltages for both cases as input voltage goes up (black line) and down (red line):

Plot hysteresis 01.png


As we can clearly see there is the hysteresis loop. The reason for this loop is because the threshold voltages depends from output voltage. If the output voltage is high the threshold voltage is higher than for the case if output voltage is low.

Identify the input voltage threshold levels at which a [math] V_{in}[/math] will produce [math]V_{out} \approx V_{cc}[/math]

From my measurements above:

1) if the output voltage is high ([math](11.06\pm 0.01)\ V[/math]) my threshold voltage is:

[math]V = (6.38\pm 0.01)\ V[/math]

2) if the output voltage is low ([math](10.53\pm 0.01)\ V[/math]) my threshold voltage is:

[math]V^' = (4.48\pm 0.01)\ V[/math]

Compare the threshold values to what is expected.

The theory does say (ch. 10.19 The Schmitt Trigger of R. Simpson "Introductory electronics for scientists and engineers"):

[math]V_2 = \frac{R_{123}}{R_2}V_{ref} + \frac{R_{123}}{R_3}V_{out}[/math]

1) if the output is high:

[math]V_2 = \frac{R_{123}}{R_2}V_{ref} + \frac{R_{123}}{R_3}V_{out_1}[/math]

2) if the output is low:

[math]V_2^' = \frac{R_{123}}{R_2}V_{ref} - \frac{R_{123}}{R_3}V_{out_1}[/math]

where

[math]R_{123} = (R_1 || R_2 || R_3) = \frac{R_1 R_2 R_3}{R_1+R_2+R_3}[/math]

and [math]V_{out_1}[/math] and [math]V_{out_2}[/math] approximately equal to supply voltage [math]V_{cc}[/math]


The actual measured values of high and low output voltages (they do not really equal to [math]\pm V_{cc}[/math]) are:

  1. [math]V_{out_1} = (+11.06\pm0.01)\ V[/math]
  2. [math]V_{out_2} = (-10.53\pm0.01)\ V[/math]

Substituting all quantities in the formulas above:

[math]R_{123} = (1.01\pm 0.01)\ k\Omega\ ||\ (1.01\pm 0.01)\ k\Omega\ ||\ (5.10\pm 0.05)\ k\Omega = (0.459\pm 0.003)\ k\Omega[/math]
[math]V_2 = \frac{(0.459\pm 0.003)\ k\Omega}{(1.01\pm 0.01)\ k\Omega}(11.90\pm 0.01)\ V + \frac{(0.459\pm 0.003)\ k\Omega}{(5.10\pm 0.05)\ k\Omega}(11.06\pm 0.01)\ V[/math]
[math]V_2^' = \frac{(0.459\pm 0.003)\ k\Omega}{(1.01\pm 0.01)\ k\Omega}(11.90\pm 0.01)\ V - \frac{(0.459\pm 0.003)\ k\Omega}{(5.10\pm 0.05)\ k\Omega}(10.53\pm0.01)\ V[/math]

and doing math and propagating errors we end up with the following predicted threshold voltages:

[math]V_2(\mbox{theory}) = (6.41\pm 0.07)\ V\ \ (\mbox{if}\ \mbox{the}\ \mbox{output}\ \mbox{is}\ \mbox{high})[/math]
[math]V_2^'(\mbox{theory}) = (4.47\pm 0.06)\ V\ \ (\mbox{if}\ \mbox{the}\ \mbox{output}\ \mbox{is}\ \mbox{low})[/math]


They are in total agreement with measured ones within the calculated error above:

[math]V(\mbox{measured}) = (6.38\pm 0.01)\ V\ \ (\mbox{if}\ \mbox{the}\ \mbox{output}\ \mbox{is}\ \mbox{high})[/math]
[math]V^'(\mbox{measured}) = (4.48\pm 0.01)\ V\ \ (\mbox{if}\ \mbox{the}\ \mbox{output}\ \mbox{is}\ \mbox{low})[/math]

low-frequency input

Below my digital scope picture of how the Schmitt Trigger output signal behaves with respect to low frequency input signal.

Tek00047.png


As we can see it flips perfectly up and down if the input signal exceeds the calculated above threshold values.



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