Latest revision as of 17:50, 20 June 2010

general setup

geometry calculation

beam energy	collimator diameter	$\Theta_{critical}$	$\Theta_{kicker}$	$\alpha_{collimator}$	$AC$	$A_1C_1$	$BD$	$B_1D_1$	$FA$	$GH$
25 MeV	$\frac{\Theta_{critical}}{2}$	$1.17^o$	$0.83^o$	$2.03^o$	4.13 cm	6.78 cm	2.92 cm	4.79 cm	75 cm	7.49 cm
25 MeV	$\frac{\Theta_{critical}}{3}$	$1.17^o$	$0.83^o$	$1.63^o$	4.13 cm	6.78 cm	1.95 cm	3.20 cm	111 cm	4.99 cm
25 MeV	$\frac{\Theta_{critical}}{4}$	$1.17^o$	$0.83^o$	$1.43^o$	4.13 cm	6.78 cm	1.46 cm	2.40 cm	136 cm	3.74 cm

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@@ Line 1: / Line 1: @@
 [http://wiki.iac.isu.edu/index.php/PhotoFission_with_Polarized_Photons_from_HRRL Go Back]
-=Minimum accelerator energy to run experiment=
-==condition 1: fitting the collimator size into the hole==
+=general setup=
-[[File:min_energy.png|1500px]]
+[[File:minimum_energy_condition.png]]
-The minimum energy of accelerator (MeV) is limited by fitting the collimator (<math>r_2</math>) into the hole (<math>R = 8.73\ cm</math>)
+=geometry calculation=
- <math>x_2 + r_2 = R</math>
-) Assuming the collimator diameter is <math>\Theta_C</math>:
- <math>\frac{1}{\sqrt{2}}\ (286+183)\ \tan\left(\frac{0.511}{E_{min}}\right) +
-       \frac{1}{2}\ (286+183)\ \tan\left(\frac{0.511}{E_{min}}\right) = 8.73 \Rightarrow E_{min} = 33.1\ MeV  </math>
-) Assuming the collimator diameter is <math>\Theta_C/2</math>:
- <math>\frac{1}{\sqrt{2}}\ (286+183)\ \tan\left(\frac{0.511}{E_{min}}\right) +
-       \frac{1}{2}\ (286+183)\ \tan\left(\frac{1}{2}\ \frac{0.511}{E_{min}}\right) = 8.73 \Rightarrow E_{min} = 26.3\ MeV  </math>
-) Assuming the collimator diameter is <math>\Theta_C/4</math>:
- <math>\frac{1}{\sqrt{2}}\ (286+183)\ \tan\left(\frac{0.511}{E_{min}}\right) +
-       \frac{1}{2}\ (286+183)\ \tan\left(\frac{1}{4}\ \frac{0.511}{E_{min}}\right) = 8.73 \Rightarrow E_{min} = 22.8\ MeV  </math>
-) for arbitrary collimator size:
-[[File:plot_energy_collimatorsize.jpeg]]
-All energy above this line is good to run experiment
-==condition 2: F1A = 286 cm==
-[[File:plot_energy_F1A.jpeg]]
-All energy above this line is good to run experiment
-==both conditions above are together==
-[[File:plot_energy_bothcondition.jpeg]]
-All energy above this lines is good to run experiment
-=25 MeV geometry=
-==geometry calculation==
 {| border="1" cellpadding="20" cellspacing="0"
 |-
+!width=40|beam energy
 !width=40|collimator diameter
 |<math>\Theta_{critical}</math>
@@ Line 59: / Line 20: @@
 |<math>B_1D_1</math>
 |<math>FA</math>
-|<math>F_1F</math>
+|<math>GH</math>
+|-
+|25 MeV||<math>\frac{\Theta_{critical}}{2}</math>||<math>1.17^o</math>||<math>0.83^o</math>||<math>2.03^o</math>
+|4.13 cm||6.78 cm||2.92 cm||4.79 cm||75 cm||7.49 cm
 |-
-|<math>\frac{\Theta_{critical}}{2}</math>||<math>1.17^o</math>||<math>0.83^o</math>||<math>2.03^o</math>
+|25 MeV||<math>\frac{\Theta_{critical}}{3}</math>||<math>1.17^o</math>||<math>0.83^o</math>||<math>1.63^o</math>
-|4.13 cm||6.78 cm||2.92 cm||4.79 cm||75 cm||143 cm
+|4.13 cm||6.78 cm||1.95 cm||3.20 cm||111 cm||4.99 cm
 |-
-|<math>\frac{\Theta_{critical}}{4}</math>||<math>1.17^o</math>||<math>0.83^o</math>||<math>1.43^o</math>
+|25 MeV||<math>\frac{\Theta_{critical}}{4}</math>||<math>1.17^o</math>||<math>0.83^o</math>||<math>1.43^o</math>
-|4.13 cm||6.78 cm||1.46 cm||2.40 cm||136 cm||203 cm
+|4.13 cm||6.78 cm||1.46 cm||2.40 cm||136 cm||3.74 cm
 |-
 |}
-==geometry pictures==
-===how it looks 1 (<math> \Theta_c/2</math>, box 3"x4" and then pipe 4")===
-[[File:vacuum_pipe_collimator_.png]]<br>
-===how it looks 2 (<math> \Theta_c/4</math>, box 3"x4" and then pipe 4")===
-[[File:vacuum_pipe_collimator_.png]]<br>
 [http://wiki.iac.isu.edu/index.php/PhotoFission_with_Polarized_Photons_from_HRRL Go Back]

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Latest revision as of 17:50, 20 June 2010

general setup

geometry calculation

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