Difference between revisions of "Notes from July 2nd, 2008 Meeting"
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fractional solid angle = <math>\frac{\pi * (1 cm)^{2}}{4 \pi (100cm^{2}} = \frac{1}{4} \times 10^{-4}</math> <= geometrical acceptance | fractional solid angle = <math>\frac{\pi * (1 cm)^{2}}{4 \pi (100cm^{2}} = \frac{1}{4} \times 10^{-4}</math> <= geometrical acceptance | ||
− | + | 10° efficient of n° detection | |
<math> 10^{4} \frac{photodisintegrations}{sec} \times \frac{1}{4} \cdot 10^{-4} \times 10^{-1} = .025 \frac{events}{sec}</math> | <math> 10^{4} \frac{photodisintegrations}{sec} \times \frac{1}{4} \cdot 10^{-4} \times 10^{-1} = .025 \frac{events}{sec}</math> | ||
− | + | time for <math>10^{4}</math> events = 100 hours for 1% | |
− | + | ::::24 hours for 2% | |
− | + | ::::6 hours for 4% | |
− | + | '''Therefore, this experiment is do able.''' | |
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− | + | [http://wiki.iac.isu.edu/index.php/PhotoFission_with_Polarized_Photons_from_HRRL Go Back] |
Latest revision as of 06:26, 5 February 2009
Numbers for rate of Brems intensity spectrum:
=
Number of ɣ + d -> n + p events/sec
Probability of Photodisintegration Event
target thickness in
Worst Case Isotropic Neutrons
Let's say we have:
radius detector = 1 cm
1 meter away
fractional solid angle =
<= geometrical acceptance10° efficient of n° detection
time for
events = 100 hours for 1%- 24 hours for 2%
- 6 hours for 4%
Therefore, this experiment is do able.