Difference between revisions of "Forest He-3 Tubes"

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About 764 keV of energy is liberated in this nuclear reaction and distributed between the final products according to their masses.   
 
About 764 keV of energy is liberated in this nuclear reaction and distributed between the final products according to their masses.   
  
:Cons Momentum <math>\Rightarrow</math>
+
;Cons Momentum <math>\Rightarrow</math>
; <math>m_p v_p = m_{H^3} v_{H^3} \Rightarrow v_p = 3v_{H^3}</math>
+
: <math>m_p v_p = m_{H^3} v_{H^3} \Rightarrow v_p = 3v_{H^3}</math>
  
 
Because the proton is about a factor of 3 lighter than Tritium (H^3) , it will have more kinetic energy by about a factor of 3 (about 573 keV).  This liberated proton can ionize other He-3 atoms via the reaction
 
Because the proton is about a factor of 3 lighter than Tritium (H^3) , it will have more kinetic energy by about a factor of 3 (about 573 keV).  This liberated proton can ionize other He-3 atoms via the reaction
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: <math>\# protons = \sigma \frac{\# incident particles}{Area}</math>
 
: <math>\# protons = \sigma \frac{\# incident particles}{Area}</math>
 
: <math>= \sigma \rho \times L</math>
 
: <math>= \sigma \rho \times L</math>
 
+
: <math>= ( 3 \times 10^{-24} cm^2) (10 Atm) \left ( 2.7 \times 10^{19} \frac{atoms}{cm^3} \right ) (76 cm) = 0.06 partices \Rightarrow \epsilon = 6</math> %
 
where  
 
where  
  

Latest revision as of 23:33, 22 June 2009

Thermal neutron capture of He-3 may be represented by the reaction below

[math]n + He^3 \rightarrow p + H^3[/math]

About 764 keV of energy is liberated in this nuclear reaction and distributed between the final products according to their masses.

Cons Momentum [math]\Rightarrow[/math]
[math]m_p v_p = m_{H^3} v_{H^3} \Rightarrow v_p = 3v_{H^3}[/math]

Because the proton is about a factor of 3 lighter than Tritium (H^3) , it will have more kinetic energy by about a factor of 3 (about 573 keV). This liberated proton can ionize other He-3 atoms via the reaction

[math]p+He^3 \rightarrow p + He^3(+) + e^-[/math]

The same proton will ionize several He-3 atoms when dissipating the 573 keV kinetic energy. Once you have the creation of ions, you can construct detectors to collect and measure the electrons.

The Tritium (H^3) can also ionize the gas but due to its higher mass it does not travel as far (shorter range) as the proton and makes a smaller contribution to the ionization signal. Tritium decays to He-3 after about 12 years ( neutron is converted to proton)

[math]H^3 \rightarrow He^3 + e^- + \bar{\nu_e}[/math]


reference: J. W. Leake, "Nuclear Instruments and Methods", Vol. 63, page 329, 1968).


The probability of neutron capture is measured in terms of a cross section. There is a nuclear data base for neutron capture located at LBL. The "free" neutron thermal total cross section ([math]\sigma[/math]) is [math]3.10 \pm 0.13[/math] barns ( 1 barn = [math]10^{-24} cm^2[/math]).

Total cross section is defined as
[math]\sigma \equiv \frac{\# particles\; scattered} {\frac{ \# incident \; particles}{Area}}[/math]
[math]\# protons = \sigma \frac{\# incident particles}{Area}[/math]
[math]= \sigma \rho \times L[/math]
[math]= ( 3 \times 10^{-24} cm^2) (10 Atm) \left ( 2.7 \times 10^{19} \frac{atoms}{cm^3} \right ) (76 cm) = 0.06 partices \Rightarrow \epsilon = 6[/math] %

where

[math]\rho[/math] = density of the He-3 target
L = length of the target.

10-atm He-3, 2.54 cm diameter tube, 76 cm long, poly moderator, cadmium metal, Boron loaded shielding.

File:He-3Tube DetectorDrawing.jpg

He-3Tube PPND Efficiency.jpg

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