|
|
(619 intermediate revisions by the same user not shown) |
Line 1: |
Line 1: |
− | <center>[[File:DC_stereo.png]]</center>
| |
| | | |
− |
| |
− |
| |
− | Using Mathematica, we can produce a 3D rendering of how the sectors for Level 1 would have to interact with a steady angle theta with respect to the beam line, as angle phi is rotated through 360 degrees.
| |
− | <center>[[File:PhiCone.png]]</center>
| |
− |
| |
− |
| |
− |
| |
− | Looking just at sector 1, we can see that the intersection of level 1 and the cone of constant angle theta forms a conic section.
| |
− | <center>[[File:Projection_side_view.png]]</center>
| |
− |
| |
− |
| |
− | <center>[[File:Projection_Rear_view.png]]</center>
| |
− |
| |
− |
| |
− | Following the rules of conic sections we know that the eccentricity of the conic is given by:
| |
− |
| |
− | <center><math>\e=\frac{\sin [\beta]}{\sin[\alpha]}</math></center>
| |
− |
| |
− |
| |
− | Where β is the angle of the plane, and α is the slant of the cone.
| |
− |
| |
− | If the conic is an circle, e=0
| |
− |
| |
− | If the conic is an parabola, e=1
| |
− |
| |
− | If the conic is an ellipse, <math>e=\sqrt{1-\frac{b^2}{a^2}}</math>
| |
− |
| |
− | <center>[[File:Conic_section.png.png]]</center>
| |