Difference between revisions of "AW Singles Prob Y88 2015"

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Line 71: Line 71:
 
| 1836 || 0.8524  || 0.8146
 
| 1836 || 0.8524  || 0.8146
 
|-
 
|-
|  rowspan="2" | 7107 || rowspan="2" | 159 || rowspan="2" | 1.49 || 898 || 0.9576  || 0.8655 || rowspan="2" |  
+
|  rowspan="2" | 7107 || rowspan="2" | 159 || rowspan="2" | 1.49 || 898 || 0.9576  || 0.8655 || rowspan="2" | 0.57
 
|-
 
|-
 
| 1836 || 0.5300  || 0.4922  
 
| 1836 || 0.5300  || 0.4922  
 
|-
 
|-
|  rowspan="2" | 7235 ||rowspan="2" | 245 || rowspan="2" | 2.30 || 898 ||  0.541  || 0.4489 || rowspan="2" |  
+
|  rowspan="2" | 7235 ||rowspan="2" | 245 || rowspan="2" | 2.30 || 898 ||  0.541  || 0.4489 || rowspan="2" | 0.59
 
|-
 
|-
 
| 1836 || 0.3033  || 0.2655  
 
| 1836 || 0.3033  || 0.2655  

Revision as of 16:25, 24 February 2015

Problem description:

The singles spectra production for the initial Y-88 activity is off by a factor of 2.
Right now the high energy line is a factor of 2 higher.


[math]N\left (\frac{1836}{898}\right ) =\frac{\frac{ UN(1836)}{.31}}{ \frac{UN(898)}{.78}}=\frac{5}{2} \frac{UN(1836)}{ UN(898)}=1 =[/math] Ratio


UCR[math]\equiv \frac{UN(1836)}{ UN(898)}=\frac{2}{5} = 0.4=[/math]ratio before efficiency correction

Days [math]T_{1/2}[/math] (898 keV) Raw (1836 keV)Raw UCR (898 keV) Integral Eff Cor (1836 keV) Integral Eff Cor Ratio
108 1.01 1.364 [math]\pm 0.062[/math] Media:Run7022_898_raw.png [math]\pm[/math] 0.048 Media:Run7022_1836_raw1.png 0.62 174.2 [math]\pm[/math] 13.24 269.8 [math]\pm[/math] 30.91 1.55
159 1.49 0.8697 [math]\pm 0.055 [/math] Media:Run7107_898_raw.png [math]\pm[/math] 0.042 Media:Run7107_1836_raw.png 0.58 111.07 [math]\pm[/math] 9.753 160.8 [math]\pm[/math] 20.9 1.45
229 2.15 0.4733[math]\pm 0.058 [/math] Media:Run7203_898_raw_ratio3.png [math]\pm[/math] 0.059 Media:Run7203_1836_raw_nocut.png 0.60 60.45 [math]\pm[/math] 8.272 90.48 [math]\pm[/math] 20.95 1.50
245 2.30 0.5807 [math]\pm 0.049 [/math] Media:Run7235_898_raw.png [math]\pm[/math] 0.032 Media:Run7235_1836_raw.png 0.42 74.16 [math]\pm[/math] 7.718 78.52 [math]\pm[/math] 12.89 1.06


What is the background contribution to the above rates ( Background is all channels with rate < 0.1 Hz)

(Set energy window to [math] \mu \pm 3 \sigma [/math])


Run # Days [math]T_{1/2}[/math] Energy (keV) Raw Integral Background Integral Background (Left) Background (Right) Ratio (Raw/Background) Sub Integral Sub Back (Left) Sub Back (Left) Ratio
7022 108 1.01 898 1.34 0.0891 0.2145 0.3148 15.04 1.252 0.04951 0.08752
1836 0.8524 0.0200 0.02507 0.01393 42.62 0.8325 0.67
7107 159 1.49 898 0.9576 0.1068 0.2332 0.1767 8.966 0.8501 0.03603 0.02687
1836 0.5300 0.0299 0.01413 0.02827 17.73 0.5007 .58
7203 229 2.15 898 0.6682 0.2094 0.3165 0.8652 3.191 0.4589
1836 0.3539 0.0799 0.02119 0.7627 4.429 0.2740 0.59
7235 245 2.30 898 0.541 0.0803 0.2951 0.2459 6.737 0.4595 0.07145 0.0648
1836 0.3033 0.0636 0.01639 0.02869 4.769 0.2414 0.52

7022 7107 overlay.png 7022 7107 overlay left.png 7022 7107 overlay right.png


Averaged Background: 898: 0.0921 +/- 0.0135 1836: 0.0378 +/- 0.0229

Run # Days [math]T_{1/2}[/math] Energy (keV) Raw Integral Sub Integral UCR
7022 108 1.01 898 1.34 1.2479 0.65
1836 0.8524 0.8146
7107 159 1.49 898 0.9576 0.8655 0.57
1836 0.5300 0.4922
7235 245 2.30 898 0.541 0.4489 0.59
1836 0.3033 0.2655


Efficiency corrected plot of the two activities as a function of days

Integral eff boosted.png


Ntuple commands

r7022 (0.002786)
TH1F *r7022=new TH1F("r7022","r7022",2200,0,4400)
ntuple->Draw("ADC7*0.599803-50.9271 >>r7022");
TH1F *N7022=new TH1F("N7022","N7022",2200,0,4400)
N7022->Add(r7022,0.002786);
r7107 (0.003534)
TH1F *r7107=new TH1F("r7107","r7107",2200,0,4400)
ntuple->Draw("ADC7*0.601126-51.3834 >>r7107");
TH1F *N7107=new TH1F("N7107","N7107",2200,0,4400)
N7107->Add(r7107,0.002786);

A_W_thesis#Final_problems_to_sort_out