Difference between revisions of "Forest UCM Osc Damped"
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:<math> \left ( O^2 + 2 \beta O + \omega^2_0 \right ) x = 0 \;\;\;\;\;\; O \equiv \frac{d}{dt}</math> | :<math> \left ( O^2 + 2 \beta O + \omega^2_0 \right ) x = 0 \;\;\;\;\;\; O \equiv \frac{d}{dt}</math> | ||
− | + | Setting the term in parentheses to zero and using the quadratic formula | |
: <math>O = \frac{- 2\beta \pm \sqrt{(2\beta)^2 -4\omega}}{2} = - \beta \pm \sqrt{\beta^2 -\omega}</math> | : <math>O = \frac{- 2\beta \pm \sqrt{(2\beta)^2 -4\omega}}{2} = - \beta \pm \sqrt{\beta^2 -\omega}</math> | ||
[[Forest_UCM_Osc#Damped_Oscillations]] | [[Forest_UCM_Osc#Damped_Oscillations]] |
Revision as of 12:50, 5 October 2014
1-D Damped Oscillaions
Equation of Motion
As in the case of air resistance, assume there is frictional force proportional to the velocity of the oscillation body.
- : in 1-D
or
or
let
- undamped oscillation frequency
- damping constant
then
As see in section Forest_UCM_Osc_SHM#Equation_of_motion, you can determine solutions to the above
by writing the analogous auxilary equation:
Setting the term in parentheses to zero and using the quadratic formula