Forest UCM Osc SHM: Difference between revisions

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==Equation of motion==
In solving the differential equation
:<math> m\ddot x =-kx  </math>energy is constant with time
and observe that the above differential equation is a special case of the more general differential equation
:<math> m\ddot x + c \dot x  =-kx  </math>energy is constant with time
one could rewrite the above as
:<math> \left ( \frac{d}{dt}\frac{d}{dt} +\frac{d}{dt} + k \right ) x = 0  </math>
One could cast the above differential equation into an analogous quadratic equation if you
let
:<math>O = \frac{d}{dt}</math>
then the analogous equation becomes
:<math> \left ( mO^2 + aO + k \right ) x = 0  </math>
where m, a, and k are constants
factoring this quadratic you would have
:<math> \left ( O - \gamma \right )\left ( O - \beta \right ) x = 0  </math>
where a non-trivial solution would exist if one of the terms in the parentheses were zero
this basically reduces our 2nd order differential equation down to two first order differential equations
:<math> \left ( \frac{d}{dt}  - \gamma \right )  \left ( \frac{d}{dt}  + \beta \right ) x = 0  </math>
one of the solutions would be
:<math> \frac{d}{dt} x - \gamma x= 0  </math>
:<math> \frac{dx}{x} =  \gamma dt  </math>
:<math> x =  Ae^{\gamma t}  </math>
:<math> x =  Ae^{\gamma t}  +  Be^{\beta t}  </math>
For the special case where there isn't a first derivative term (a=0)
You simply have
:<math> \left ( m\frac{d}{dt}\frac{d}{dt}  + k \right ) x = 0  </math>
or
:<math> \left ( mO^2  + k \right ) x = 0  </math>
:<math> O= \pm \sqrt{-\frac{k}{m}}  = \pm i  \sqrt{-\frac{k}{m}}</math>
:<math> \gamma \equiv +i\sqrt{\frac{k}{m}} = i \omega</math>
:<math> \beta = -i\sqrt{\frac{k}{m}} = -i \omega</math>
then you have
:<math> x =  Ae^{\gamma t}  +  Be^{\beta t}  </math>
::<math>  =  Ae^{i \omega t}  +  Be^{-i\omega t}  </math>




[[Forest_UCM_Osc#Simple_Harmonic_Motion_.28SHM.29]]
[[Forest_UCM_Osc#Simple_Harmonic_Motion_.28SHM.29]]

Revision as of 14:27, 4 October 2014


Equation of motion

In solving the differential equation

[math]\displaystyle{ m\ddot x =-kx }[/math]energy is constant with time


and observe that the above differential equation is a special case of the more general differential equation

[math]\displaystyle{ m\ddot x + c \dot x =-kx }[/math]energy is constant with time

one could rewrite the above as

[math]\displaystyle{ \left ( \frac{d}{dt}\frac{d}{dt} +\frac{d}{dt} + k \right ) x = 0 }[/math]

One could cast the above differential equation into an analogous quadratic equation if you

let

[math]\displaystyle{ O = \frac{d}{dt} }[/math]


then the analogous equation becomes

[math]\displaystyle{ \left ( mO^2 + aO + k \right ) x = 0 }[/math]

where m, a, and k are constants

factoring this quadratic you would have

[math]\displaystyle{ \left ( O - \gamma \right )\left ( O - \beta \right ) x = 0 }[/math]

where a non-trivial solution would exist if one of the terms in the parentheses were zero

this basically reduces our 2nd order differential equation down to two first order differential equations

[math]\displaystyle{ \left ( \frac{d}{dt} - \gamma \right ) \left ( \frac{d}{dt} + \beta \right ) x = 0 }[/math]

one of the solutions would be

[math]\displaystyle{ \frac{d}{dt} x - \gamma x= 0 }[/math]
[math]\displaystyle{ \frac{dx}{x} = \gamma dt }[/math]
[math]\displaystyle{ x = Ae^{\gamma t} }[/math]


[math]\displaystyle{ x = Ae^{\gamma t} + Be^{\beta t} }[/math]


For the special case where there isn't a first derivative term (a=0)

You simply have

[math]\displaystyle{ \left ( m\frac{d}{dt}\frac{d}{dt} + k \right ) x = 0 }[/math]

or

[math]\displaystyle{ \left ( mO^2 + k \right ) x = 0 }[/math]
[math]\displaystyle{ O= \pm \sqrt{-\frac{k}{m}} = \pm i \sqrt{-\frac{k}{m}} }[/math]
[math]\displaystyle{ \gamma \equiv +i\sqrt{\frac{k}{m}} = i \omega }[/math]
[math]\displaystyle{ \beta = -i\sqrt{\frac{k}{m}} = -i \omega }[/math]

then you have

[math]\displaystyle{ x = Ae^{\gamma t} + Be^{\beta t} }[/math]
[math]\displaystyle{ = Ae^{i \omega t} + Be^{-i\omega t} }[/math]


Forest_UCM_Osc#Simple_Harmonic_Motion_.28SHM.29