Forest UCM NLM BlockOnInclineWfriction: Difference between revisions
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=Step 5: Use Newton's second law= | =Step 5: Use Newton's second law= | ||
Motion in the <math>\hat i</math> direction governed by Netwon's second law is: | |||
:<math>\sum F_{ext} = mg \sin \theta - \mu mg= ma_x = m \frac{dv_x}{dt}</math> | :<math>\sum F_{ext} = mg \sin \theta - \mu mg= ma_x = m \frac{dv_x}{dt}</math> | ||
Revision as of 12:35, 21 August 2014
The problem
Consider a block of mass m sliding down an infinitely long inclined plane shown below with a frictional force that is given by
- [math]\displaystyle{ F_f = \mu mg }[/math]
File:TF UCM InclinedPlaneWfriction.png
Find the blocks speed as a function of time.
Step 1: Identify the system
- The block is the system with the following external forces, A normal force, a gravitational force, and the force of friction.
Step 2: Choose a suitable coordinate system
- A coordinate system with one axis along the direction of motion may make solving the problem easier
Step 3: Draw the Free Body Diagram
File:TF UCM FBD InclinedPlaneWfriction.png
Step 4: Define the Force vectors using the above coordinate system
- [math]\displaystyle{ \vec{N} = \left | \vec{N} \right | \hat{j} }[/math]
- [math]\displaystyle{ \vec{F_g} = \left | \vec{F_g} \right | \left ( \sin \theta \hat{i} - \cos \theta \hat{j} \right )= mg \left ( \sin \theta \hat{i} - \cos \theta \hat{j} \right ) }[/math]
- [math]\displaystyle{ \vec{F_f} = - \mu mg \hat{i} }[/math]
Step 5: Use Newton's second law
Motion in the [math]\displaystyle{ \hat i }[/math] direction governed by Netwon's second law is:
- [math]\displaystyle{ \sum F_{ext} = mg \sin \theta - \mu mg= ma_x = m \frac{dv_x}{dt} }[/math]
- [math]\displaystyle{ \int_0^t g \left ( \sin \theta - \mu \right ) dt = \int_{v_i}^{v} dv }[/math]
- [math]\displaystyle{ v= v_i - g \left ( \mu -\sin \theta \right ) t }[/math]
The amount of time that lapses until the blocks final velocity is zero
[math]\displaystyle{ t= \frac{v_i}{\left ( \mu - \sin \theta \right ) } }[/math]
After the above time the blocks speed is zero. The friction will change from being kinetic to static after the above time interval.
- [math]\displaystyle{ v(t) =\left \{ {v_i - g \left ( \mu -\sin \theta \right ) t \;\;\;\;\;\;\;\; t< \frac{v_i}{\left ( \mu - \sin \theta \right ) } \atop 0\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\; t>= \frac{v_i}{\left ( \mu - \sin \theta \right ) }} \right . }[/math]