Difference between revisions of "Neutron energy resolution in NaI detector"
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− | <math> E_n = \frac{m}{2}\left( \frac{d}{t_n} \right)^2 </math> | + | <math> E_n = \frac{m}{2}\left( \frac{d}{t_n} \right)^2 </math> |
− | <math> \delta E_n | + | <math> \delta E_n = -\frac{2 \sqrt{2}}{\sqrt{m} d}\ E_n^{3/2} \delta t_n </math> |
+ | [[File:Na 22 timing.jpg | 400px]] | ||
− | * | + | * <math> \delta t_n = 15\ ns</math> |
* <math> mc^2 = 938\ MeV </math> | * <math> mc^2 = 938\ MeV </math> | ||
− | <math> d = 0.5 m\: \ \ \ \delta E_n = 0. | + | |
+ | <math> d = 0.5\ m: \ \ \ ( \delta E_n/E_n ) = 0.83\ E_n^{1/2}\ MeV </math> | ||
+ | <math> d = 0.7\ m: \ \ \ ( \delta E_n/E_n ) = 0.59\ E_n^{1/2}\ MeV </math> | ||
+ | <math> d = 1.0\ m: \ \ \ ( \delta E_n/E_n ) = 0.42\ E_n^{1/2}\ MeV </math> | ||
+ | <math> d = 1.5\ m: \ \ \ ( \delta E_n/E_n ) = 0.28\ E_n^{1/2}\ MeV </math> | ||
+ | <math> d = 2.0\ m: \ \ \ ( \delta E_n/E_n ) = 0.21\ E_n^{1/2}\ MeV </math> | ||
+ | |||
+ | [[File:NaI_energy_resolut.png | 450px]] | ||
+ | [[File:NaI_energy_resolut_4.png | 450px]] |