TF EIMLab9 Writeup: Difference between revisions
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Notice the output pulse does not increase when V_{in} is increased | |||
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| V_{in} = | | V_{in} = 4 V || V_{in} = 7 V|| V_{in} =9V | ||
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|[[File: | |[[File:TF_EIM_Lab9_P2_Vin4V.png | 200 px]] ||[[File: TF_EIM_Lab9_P2_Vin7V.png | 200 px]]||[[File: TF_EIM_Lab9_P2_Vin9V.png | 200 px]] | ||
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Latest revision as of 18:18, 4 March 2011
Lab 9: Diode Circuits
Clipping Circuit
1.) Construct the circuit shown below using a silicon diode.
Using Diode 1N5230B
And
R= 9.6k[math]\displaystyle{ \Omega }[/math]
2.) Use a sine wave generator to drive the circuit so [math]\displaystyle{ V_{in} = V_0 \cos(2 \pi \nu t) }[/math] where [math]\displaystyle{ V_0 = 0.1 }[/math] V and [math]\displaystyle{ \nu }[/math] = 1kHz. (20 pnts)
3.)Based on your observations using a oscilloscope, sketch the voltages [math]\displaystyle{ V_{in} }[/math] and [math]\displaystyle{ V_{out} }[/math] as a function of time.
Outoput for several input voltages near the bias point
| V_{in} = 0.5V | V_{in} = 0.6 V | V_{in} = 0.75 V | V_{in} = 0.8 V | V_{in} = 1.0 V |
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4.)Do another sketch for[math]\displaystyle{ V_0 }[/math] = 1.0 V and another for 10.0 V (DONT LET ANY SMOKE OUT!). (20 pnts)
| V_{in} = 1 V | V_{in} = 10 V |
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Differentiating Circuit with clipping
1.)Construct the circuit below.
2.)Select [math]\displaystyle{ R_1 }[/math] and [math]\displaystyle{ R_2 }[/math] such that the current from the +5V DC source is less than 1.0 mA and the DC voltage at [math]\displaystyle{ V_{out} }[/math] is 3 V when there is no input pulse.
[math]\displaystyle{ R_1= 15 k\Omega }[/math]
[math]\displaystyle{ R_2 = 10 k \Omega }[/math]
3.)Select a capacitor [math]\displaystyle{ (C) }[/math]and a pulse width [math]\displaystyle{ \tau }[/math] to form a differentiating circuit for the pulse from the signal generator. Hint: [math]\displaystyle{ R_{12}C \ll \tau }[/math].
[math]\displaystyle{ C = 10.5 nF }[/math]
4.)plot [math]\displaystyle{ V_{in} }[/math] and [math]\displaystyle{ V_{out} }[/math] as a function of time using your scope observations. (20 pnts)
| Signal setup | RC fall time |
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5.) Now add the diode circuit from part 1 to prevent [math]\displaystyle{ V_{out} }[/math] from rising above +5 V. Sketch the new circuit below.
6.)plot [math]\displaystyle{ V_{in} }[/math] and [math]\displaystyle{ V_{out} }[/math] as a function of time with the diode circuit you added using your scope observations. (the diode should clip off positive spikes)(20 pnts)
Notice the output pulse does not increase when V_{in} is increased
| V_{in} = 4 V | V_{in} = 7 V | V_{in} =9V |
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Questions
- Explain your results in parts 1 & 2 in terms of the diode turn-on voltage. (20 pnts)