TF EIMLab9 Writeup: Difference between revisions

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[[File:TF_EIM_Lab9.png | 200 px]]
[[File:TF_EIM_Lab9.png | 200 px]]


Using Diode
Using Diode 1N5230B


And
And
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3.)Based on your observations using a oscilloscope, sketch the voltages <math>V_{in}</math> and <math>V_{out}</math> as a function of time.
3.)Based on your observations using a oscilloscope, sketch the voltages <math>V_{in}</math> and <math>V_{out}</math> as a function of time.


Outoput for several input voltages near the bias point


{| border="3"  cellpadding="20" cellspacing="0"
| V_{in} = 0.5V ||  V_{in} = 0.6 V||  V_{in} = 0.75 V||  V_{in} = 0.8 V||  V_{in} = 1.0 V
|-
|[[File:TF_EIM_Lab9_P1_0.5V.png | 100 px]] ||[[File: TF_EIM_Lab9_P1_0.6V.png | 100 px]]||[[File: TF_EIM_Lab9_P1_0.75V.png | 100 px]]||[[File: TF_EIM_Lab9_P1_0.8V.png | 100 px]]||[[File: TF_EIM_Lab9_P1_1.0V.png | 100 px]]
|-
|}


4.)Do another sketch for<math> V_0</math> = 1.0 V and another for 10.0 V (DONT LET ANY SMOKE OUT!). (20 pnts)
4.)Do another sketch for<math> V_0</math> = 1.0 V and another for 10.0 V (DONT LET ANY SMOKE OUT!). (20 pnts)
{| border="3"  cellpadding="20" cellspacing="0"
| V_{in} = 1 V ||  V_{in} = 10 V
|-
|[[File:TF_EIM_Lab9_P1_1V.png | 200 px]] ||[[File: TF_EIM_Lab9_P1_10V.png | 200 px]]
|-
|}


= Differentiating Circuit with clipping=
= Differentiating Circuit with clipping=
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<math>R_2 = 10 k \Omega</math>
<math>R_2 = 10 k \Omega</math>


3.)Select a capacitor <math>(C)</math>and a pulse width <math>\tau</math>  to form a differentiating circuit for the pulse from the signal generator.  Hint: <math>R_{12}C \ll \tau</math>.  
3.)Select a capacitor <math>(C)</math>and a pulse width <math>\tau</math>  to form a differentiating circuit for the pulse from the signal generator.  Hint: <math>R_{12}C \ll \tau</math>.  
<math>C = 10.5 nF</math>


4.)plot <math>V_{in}</math> and <math>V_{out}</math>  as a function of time using your scope observations. (20 pnts)
4.)plot <math>V_{in}</math> and <math>V_{out}</math>  as a function of time using your scope observations. (20 pnts)
{| border="3"  cellpadding="20" cellspacing="0"
| Signal setup||  RC fall time
|-
|[[File:TF_EIM_Lab9_P2_5V_Signal.png | 200 px]] ||[[File: TF_EIM_Lab9_P2_RCfallTime.png | 200 px]]
|-
|}


5.) Now add the diode circuit from part 1 to prevent <math>V_{out}</math> from rising above +5 V.  Sketch the new circuit below.
5.) Now add the diode circuit from part 1 to prevent <math>V_{out}</math> from rising above +5 V.  Sketch the new circuit below.


6.)plot <math>V_{in}</math> and <math>V_{out}</math>  as a function of time with the diode circuit you added using your scope observations. (the diode should clip off positive spikes)(20 pnts)
6.)plot <math>V_{in}</math> and <math>V_{out}</math>  as a function of time with the diode circuit you added using your scope observations. (the diode should clip off positive spikes)(20 pnts)
Notice the output pulse does not increase when V_{in} is increased
{| border="3"  cellpadding="20" cellspacing="0"
| V_{in} = 4 V ||  V_{in} = 7 V||  V_{in} =9V
|-
|[[File:TF_EIM_Lab9_P2_Vin4V.png | 200 px]] ||[[File: TF_EIM_Lab9_P2_Vin7V.png | 200 px]]||[[File: TF_EIM_Lab9_P2_Vin9V.png | 200 px]]
|-
|}


=Questions=
=Questions=


#Explain your results in parts 1 & 2 in terms of the diode turn-on voltage. (20 pnts)
#Explain your results in parts 1 & 2 in terms of the diode turn-on voltage. (20 pnts)

Latest revision as of 18:18, 4 March 2011

Lab 9: Diode Circuits

Clipping Circuit

1.) Construct the circuit shown below using a silicon diode.

Using Diode 1N5230B

And

R= 9.6k[math]\displaystyle{ \Omega }[/math]

2.) Use a sine wave generator to drive the circuit so [math]\displaystyle{ V_{in} = V_0 \cos(2 \pi \nu t) }[/math] where [math]\displaystyle{ V_0 = 0.1 }[/math] V and [math]\displaystyle{ \nu }[/math] = 1kHz. (20 pnts)


3.)Based on your observations using a oscilloscope, sketch the voltages [math]\displaystyle{ V_{in} }[/math] and [math]\displaystyle{ V_{out} }[/math] as a function of time.

Outoput for several input voltages near the bias point

V_{in} = 0.5V V_{in} = 0.6 V V_{in} = 0.75 V V_{in} = 0.8 V V_{in} = 1.0 V

4.)Do another sketch for[math]\displaystyle{ V_0 }[/math] = 1.0 V and another for 10.0 V (DONT LET ANY SMOKE OUT!). (20 pnts)

V_{in} = 1 V V_{in} = 10 V

Differentiating Circuit with clipping

1.)Construct the circuit below.

2.)Select [math]\displaystyle{ R_1 }[/math] and [math]\displaystyle{ R_2 }[/math] such that the current from the +5V DC source is less than 1.0 mA and the DC voltage at [math]\displaystyle{ V_{out} }[/math] is 3 V when there is no input pulse.

[math]\displaystyle{ R_1= 15 k\Omega }[/math]

[math]\displaystyle{ R_2 = 10 k \Omega }[/math]


3.)Select a capacitor [math]\displaystyle{ (C) }[/math]and a pulse width [math]\displaystyle{ \tau }[/math] to form a differentiating circuit for the pulse from the signal generator. Hint: [math]\displaystyle{ R_{12}C \ll \tau }[/math].


[math]\displaystyle{ C = 10.5 nF }[/math]

4.)plot [math]\displaystyle{ V_{in} }[/math] and [math]\displaystyle{ V_{out} }[/math] as a function of time using your scope observations. (20 pnts)


Signal setup RC fall time

5.) Now add the diode circuit from part 1 to prevent [math]\displaystyle{ V_{out} }[/math] from rising above +5 V. Sketch the new circuit below.



6.)plot [math]\displaystyle{ V_{in} }[/math] and [math]\displaystyle{ V_{out} }[/math] as a function of time with the diode circuit you added using your scope observations. (the diode should clip off positive spikes)(20 pnts)


Notice the output pulse does not increase when V_{in} is increased

V_{in} = 4 V V_{in} = 7 V V_{in} =9V

Questions

  1. Explain your results in parts 1 & 2 in terms of the diode turn-on voltage. (20 pnts)