Difference between revisions of "Counts Rate (44 MeV LINAC)"
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<math>8.2 \cdot 10^{7} \frac{\gamma}{sec} \times 130\ mb \times 0.48\cdot 10^{23}\ \frac{atoms}{cm^2} \times 2.4 = 1.2 \cdot 10^{6}\ \frac{neutrons}{sec}</math> | <math>8.2 \cdot 10^{7} \frac{\gamma}{sec} \times 130\ mb \times 0.48\cdot 10^{23}\ \frac{atoms}{cm^2} \times 2.4 = 1.2 \cdot 10^{6}\ \frac{neutrons}{sec}</math> | ||
+ | =Worst Case Isotropic Neutrons= | ||
+ | Let's say we have: | ||
− | =geometrical | + | radius detector = 1 cm |
+ | |||
+ | 1 meter away | ||
+ | |||
+ | fractional solid angle = <math>\frac{\pi * (1 cm)^{2}}{4 \pi (100cm^{2}} = \frac{1}{4} \times 10^{-4}</math> <= geometrical acceptance |
Revision as of 21:51, 17 May 2010
LINAC parameters used in calculations
1) pulse width 50 ns
2) pulse current 50 A
3) repetition rate 300 Hz
4) energy 44 MeV
Number of electrons/sec on radiator
Number of photons/sec from radiator
bremsstrahlung
plot from Dale
from plot above in (10,20) MeV region we have about
0.1 photons/electrons/MeV/r.l
radiation length
radiation length of Ti(Z=22) is 3.59 cm
Assume the radiator thickness is
steps together...
Collimation factor
We take 4-6 % of total number of photons going through collimator (Alex, GEANT calculation)
So, the flux incident on target is
Number of neutrons/sec (yields)
cross section
plot from Berman
From plot above the average cross section for in (10,20) MeV region is:
130 mb
target thickness,
Assume the target thickness is 1 cm ->
neutrons per fission
2.4 neutrons/fission
steps together...
Worst Case Isotropic Neutrons
Let's say we have:
radius detector = 1 cm
1 meter away
fractional solid angle =
<= geometrical acceptance