Difference between revisions of "Counts Rate (44 MeV LINAC)"
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=number of electrons/sec on radiator= | =number of electrons/sec on radiator= | ||
+ | |||
<math> 50ps \times 50A \times 300Hz \times \frac{1\cdot e^-}{1.6\cdot 10^{-19}C} = 0.47 \cdot 10^{13} \frac{e^-}{sec}</math><br><br> | <math> 50ps \times 50A \times 300Hz \times \frac{1\cdot e^-}{1.6\cdot 10^{-19}C} = 0.47 \cdot 10^{13} \frac{e^-}{sec}</math><br><br> | ||
=number of photons/sec from radiator= | =number of photons/sec from radiator= | ||
+ | |||
==Bremsstrahlung== | ==Bremsstrahlung== | ||
from plot above we have about 0.1 photons/electrons/MeV/r.l from 10 MeV to 20 MeV region | from plot above we have about 0.1 photons/electrons/MeV/r.l from 10 MeV to 20 MeV region | ||
+ | |||
==Radiation length== | ==Radiation length== | ||
radiation length of Ti(Z=22)is 3.59 cm<br> | radiation length of Ti(Z=22)is 3.59 cm<br> | ||
Assume the radiator thickness is <math>12.5 \mu m</math><br><br> | Assume the radiator thickness is <math>12.5 \mu m</math><br><br> | ||
− | + | <math>3.59 cm/12.5\mu m = 3.48 \cdot 10^{-4} \ r.l.</math><br> | |
Revision as of 20:45, 17 May 2010
LINAC parameters used in calculations
1) pulse width 50 ns
2) pulse current 50 A
3) repetition rate 300 Hz
4) energy 44 MeV
number of electrons/sec on radiator
number of photons/sec from radiator
Bremsstrahlung
from plot above we have about 0.1 photons/electrons/MeV/r.l from 10 MeV to 20 MeV region
Radiation length
radiation length of Ti(Z=22)is 3.59 cm
Assume the radiator thickness is