Difference between revisions of "Geometry (44 MeV LINAC exit port)"

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   <math>(286 + 183)\ cm \cdot \tan (0.47) = 3.85\ cm</math>  (wall 2)
 
   <math>(286 + 183)\ cm \cdot \tan (0.47) = 3.85\ cm</math>  (wall 2)
  
2) assume diameter is <math>\Theta_crit/2 = 0.67^o/2 = 0.335^o</math>
+
2) assume diameter is <math>\Theta_c/2 = 0.67^o/2 = 0.335^o</math>
 +
 
 +
  <math>286\ cm \cdot \tan (0.47) = 2.35\ cm</math>  (wall 1)
 +
 
 +
  <math>(286 + 183)\ cm \cdot \tan (0.47) = 3.85\ cm</math>  (wall 2)
 +
 
 +
 
  
  

Revision as of 05:10, 25 May 2010

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Some measurements of 90 experimental degree exit port

Exit port1.png


Critical angle and displacement calculations

Θ=mec2Ebeam=0.511 MeV44 MeV=0.67 o


Kicker angle and displacement calculations

1 foot = 30.48 cm

accelerator's side wall

Δ=286 cm  tan(0.67o)=3.34 cm

x2+x2=3.342 cm    x=2.36 cm

Δ=2.36 cm    tan1(2.36286)=0.47 o


detector's side wall

Δ=(286 cm+183 cm)  tan(0.67o)=5.48 cm

Δ=(286 cm+183 cm)  tan(0.47o)=3.85 cm


Off-axis collimation geometry

Beam up down5.png


Vacuum pipe

Collimator location

1) center position

  [math]286\ cm \cdot \tan (0.47) = 2.35\ cm[/math]  (wall 1)
  [math](286 + 183)\ cm \cdot \tan (0.47) = 3.85\ cm[/math]  (wall 2)

2) assume diameter is Θc/2=0.67o/2=0.335o

  [math]286\ cm \cdot \tan (0.47) = 2.35\ cm[/math]  (wall 1)
  [math](286 + 183)\ cm \cdot \tan (0.47) = 3.85\ cm[/math]  (wall 2)




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