B-field calculation: Difference between revisions
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<math>B(T) = \frac{4.67\cdot 10^{-2}\cdot sin(\kappa)}{a(m)}</math> | <math>B(T) = \frac{4.67\cdot 10^{-2}\cdot sin(\kappa)}{a(m)}</math> | ||
If <math>\kappa = 2^0</math> then | If <math>\kappa = 2^0</math> then <math>sin(\kappa) = 0.0348995</math> | ||
Revision as of 16:56, 3 February 2009
[math]\displaystyle{ 1 MeV = 1.6\cdot 10^{-13} J = 1.6\cdot 10^{-13} \frac{m^2\cdot kg}{s^2} }[/math]
[math]\displaystyle{ c = 2.998 \cdot 10^8 \frac{m}{s} }[/math]
[math]\displaystyle{ p_e = 14 \frac{MeV}{c} = 7.47 \cdot 10^{-21} \frac{m\cdot kg}{s} }[/math]
[math]\displaystyle{ B = \frac{p_e}{q_e \cdot R} }[/math]
[math]\displaystyle{ 1T=\frac{kg}{C\cdot s} }[/math], [math]\displaystyle{ q_e = 1.6\cdot 10^{-19} C }[/math]
[math]\displaystyle{ B(T) = \frac{4.67\cdot 10^{-2}}{R(m)} }[/math]
[math]\displaystyle{ 180^0 = \kappa + 90^0 + \beta }[/math]
[math]\displaystyle{ 180^0 = \gamma + 90^0+ \beta }[/math]
[math]\displaystyle{ \kappa = \gamma }[/math]
[math]\displaystyle{ R = \frac{a}{cos(\beta)} = \frac{a}{cos(90^0 - \kappa)} = \frac{a}{sin(\kappa)} }[/math]
[math]\displaystyle{ d = R \cdot (1 - cos(\kappa)) = \frac{a \cdot (1 - cos(\kappa))}{sin(\kappa)} }[/math]
[math]\displaystyle{ B(T) = \frac{4.67\cdot 10^{-2}\cdot sin(\kappa)}{a(m)} }[/math]
If [math]\displaystyle{ \kappa = 2^0 }[/math] then [math]\displaystyle{ sin(\kappa) = 0.0348995 }[/math]