Difference between revisions of "Notes for the July 11th, 2008 Meeting"

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[[Image:com_and_lab_frame.jpg|left]]
 
[[Image:com_and_lab_frame.jpg|left]]
  
−
2 * p <sub>n</sub> cos θ = 15 MeV
+
<math>2 \cdot p _n cos \theta = 15 MeV</math>
  
−
2 * sqrt(p<sub>n</sub> <sup>2</sup> + m <sub>n</sub> <sup>2</sup>) = 15 MeV = m <sub>d</sub>
+
<math>2 \cdot \sqrt{p_n ^2 + m _n ^2} = 15 MeV = m _d
 +
</math>

Revision as of 16:52, 15 July 2008

Setup07.11.08.jpg

[math]\frac {m}{e}[/math] = we'll have 2.5"

[math]\frac {2.5}{x}[/math] = tan(1.95)

radiator distance - collimator

x = 73.4" = 186.5 cm

radiator is 73.4" - 48" upstream of the wall


Something someone needs to do:

Look up which has the highest neutron production energy thresh hold: Cu, Zn, Ni


Com and lab frame.jpg

[math]2 \cdot p _n cos \theta = 15 MeV[/math]

[math]2 \cdot \sqrt{p_n ^2 + m _n ^2} = 15 MeV = m _d [/math]

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