Difference between revisions of "Quantum Qual Problems"
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* <math> [- \frac{\hbar^2}{2M}\Delta^2 + V]W(x,y,z)=E W(x,y,z) </math><br> | * <math> [- \frac{\hbar^2}{2M}\Delta^2 + V]W(x,y,z)=E W(x,y,z) </math><br> | ||
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* <math>E = \frac{\pi^2 \hbar^2 n^2}{2M^2 a^2}</math>, where <math>n^2=n_x ^2 + n_y ^2 + n_z ^2</math>, n=1,2,3... | * <math>E = \frac{\pi^2 \hbar^2 n^2}{2M^2 a^2}</math>, where <math>n^2=n_x ^2 + n_y ^2 + n_z ^2</math>, n=1,2,3... | ||
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+ | 2.) A system has two energy eigenstate with eigenvalues <math>w_1</math> and <math>w_2</math> |
Revision as of 22:25, 16 August 2007
1.) Given a quantum mechanical particle of mass
confined inside a box of sides . The particle is allowed to move freely between and .- Use the time-independent Schrodinger equation for this problem to obtain the general form for the eigenfunctions of the particle
- Now apply boundary conditions to obtain the specific eigenfunctions and eigenenergies for this specific problem.
- Assume and find the first 6 eigenenergies of the problem in terms of the box side length ( ), the particle mass ( ) and standard constants. What are their quantum number? Make a sketch of the eigenvalue spectrum, a table listing these eigenenergies and the quantum numbers of all the states that correspond to them.
Solution:
In our case, using separation of variables, we will get 3 differential equations for x, y and z. W(x,y,z)=w(x)w(y)w(z)
The same will be for y and z.
Solution of equation (1) is following
- Applying B. C. at x=y=z=0 wave function should be zero, that means B=D=F=0. We have
Also, w(a)=0 which gives
A, C and E are normalization constants
The eigenfunction for each component will be
The eigenenergies
Total energy is sum of these energies.
- , where , n=1,2,3...
2.) A system has two energy eigenstate with eigenvalues
and