Revision as of 04:29, 24 June 2007

Theory of Dopler Broadening

= amount of energy the gamma ray was shifted by

where $E_{photon}$ is the Doppler-shifted $\gamma$ -ray energy which was measured

$cos\theta_{photon1}$ =- $cos\theta_{1}$ for an excited fragment in det-1
$cos\theta_{photon2}$ =- $cos\theta_{2}$ for an excited fragment in det-2

$\theta_i$ is the polar emission angle of excited fragment and $\beta_i$ the fragment velocity

$\beta_i$ =0.04634 $\frac{\sqrt{E_i[MeV]}}{A_i[u]}$

@@ Line 13: / Line 13: @@
 <math>\theta_i</math> is the polar emission angle of excited fragment and <math>\beta_i</math> the fragment velocity<br>
-<math>\frac{\sqrt{E_i[MeV]}}{A_i[u]}</math>
+<math>\beta_i</math>=0.04634<math>\frac{\sqrt{E_i[MeV]}}{A_i[u]}</math>
 == Photon emission off fission fragment velocity axis==