Difference between revisions of "LB SageBrushWork PostDefense"
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==10% Sample== | ==10% Sample== | ||
− | {| | + | {|border = 5" |
|| Selenium Target (10% Sagebrush Se Mix) || Mass (g) | || Selenium Target (10% Sagebrush Se Mix) || Mass (g) | ||
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Revision as of 17:16, 29 August 2018
Mass Information
The target masses are as follows
50% Se/Sage Sample
Selenium Target (50% Sagebrush Se Mix) | Mass (g) |
Outer Front Ni Foil | 0.6948 |
Se Mass | 0.51 |
Outer Se Mass | 0.1 |
Sagebrush Leaves Mass | 0.4969 |
10% Sample
Selenium Target (10% Sagebrush Se Mix) | Mass (g) |
Outer Front Ni Foil | 0.2783 |
Se Mass | 0.0523 |
Outer Se Mass | 0.0971 |
Sagebrush Leaves Mass | 0.5111 |
0.1% Se/Sage Sample
Selenium Target (0.1% Sagebrush Se Mix) | Mass (g) |
Outer Front Ni Foil | 1.1437 |
Se Mass | 0.0559 |
Outer Se Mass | 0.1118 |
Sagebrush Leaves Mass | 50.1080 |
Time Cuts
The first step in the PAA process is to identify the time cuts used for the split run. This must be done for all samples (50%,10%,0.1%, and 0.04%).
50% Sage/Se Mixture Time Cuts
The 50% Se/Sage mixture was measure on Detector B (unshielded, so watch the SNR) on 5/24/17 for a total of 2130.540 seconds. The outer pure witness Se was measure first, and sub-run was roughly 300 seconds for the samples of interest, and 60 seconds for the Co-60 flag. The root command used to draw the timing information was
TTree* tree = MPA;
MPA->Draw("evt.Chan:evt.Sec>>hist2","evt.ADCid == 1");
which produced the histogram below
This seems a little sloppy, lets try a 1D histogram instead to see if the cuts are more clear
ROOT Command: MPA->Draw("evt.Sec>>hist","ADCid==1","");
This produced the histogram below
This seems much cleaner and clearly shows the time cuts
The time cuts are
0-300 (Pure Se)
375-440 (Co-60)
450-700 (Mixture)
715-780 (Co-60)
800-1010 (Pure Se)
1055-1150 (Co-60)
1160-1420 (Mixture)
1425-1495 (Co-60)
1500-1800 (Pure Se)
1810-1870 (Co-60)
1880-2100 (Mixture)
10% Sage/Se Mixture Time Cuts
The 10% Se/Sage mixture was measured on Detector A (shielded) on 5/25/17 for a total of 5136.343 seconds. The mixture was measured first, and a sub-run was roughly 300 seconds for the Se samples and 60 seconds for the Co-60 flag. The root commands used were
TTree* tree = MPA;
MPA->Draw("evt.Chan:evt.Sec>>hist2","evt.ADCid == 0");
The time cut information is as follows
0-300 (Mixture)
300-360 (Co-60)
400-640 ( Pure Se)
680-710 (Co-60)
730-1020 (Mixture)
1030-1080 (Co-60)
1100-1360 ( Pure Se)
1400-1440 (Co-60)
1480-1775 (Mixture)
1800-1840 (Co-60)
1875-2150 (Pure Se)
2190-2220 (Co-60)
2250-2550 (Mixture)
2590-2620 (Co-60)
2650-2930 (Pure Se)
2950-3000 (Co-60)
3050-3300 (Mixture)
3390-3350 (Co-60)
3400-3690 (Pure Se)
3700-3750 (Co-60)
3775-4050 (Mixture)
4060-4100 (Co-60)
4120-4400 (Pure Se)
4420-4470 (Co-60)
4480-4770 (Mixture)
4790-4820 (Co-60)
4840-5130 (Pure Se)
0.1% Sage/Se Mixture Time Cuts
The 0.1% Se/Sage mixture was measured on Detector A (shielded) on 5/24/17 for a total of 2130.540 seconds. The mixture was measured first, and a sub-run was roughly 300 seconds for the Se samples and 60 seconds for the Co-60 flag. The root commands used were
TTree* tree = MPA;
MPA->Draw("evt.Chan:evt.Sec>>hist2","evt.ADCid == 0");
which produced the histogram below
This seems a little sloppy, so let's repeat the procedure for the 50% sample
ROOT Command:ROOT Command: MPA->Draw("evt.Sec>>hist","ADCid==0","");
This produced the histogram below
This is again much better than the 2D histogram.
The time cuts are
0-300 (Mixture)
306-340 (Co-60)
376-640 (Pure Se)
650-720 (Co-60)
730-1010 (Mixture)
1020-1050 (Co-60)
1100-1350 (Pure Se)
1400-1460 (Co-60)
1470-1730 (Mixture)
1735-1800 (Co-60)
1804-2140 (Pure Se)