Difference between revisions of "Initial Lab Frame 4-momentum components"

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| style="background: gray"      | <math>\Longrightarrow E\equiv \sqrt{(11000 MeV)^2+(.511 MeV)^2}+.511MeV\approx 11000.511 MeV</math>
 
| style="background: gray"      | <math>\Longrightarrow E\equiv \sqrt{(11000 MeV)^2+(.511 MeV)^2}+.511MeV\approx 11000.511 MeV</math>
 
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Latest revision as of 18:53, 15 May 2018

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Initial Lab Frame 4-momentum components

Lab.png
Figure 1: Definition of variables in the Lab Frame


Begining with the assumption that the incoming electron, p1, has momentum of 11000 MeV in the positive z direction.


p1(z)p1=11000MeVˆz


We can also assume the Moller electron, p2, is initially at rest


p20


This gives the total energy in this frame as


EE1+E2


where,

Ep2+m2


This gives,

E(p1)2+(m1)2+m2


E(11000MeV)2+(.511MeV)2+.511MeV11000.511MeV




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