Difference between revisions of "Initial Lab Frame 4-momentum components"

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| style="background: gray"      | <math>\Longrightarrow E\equiv \sqrt{(11000 MeV)^2+(.511 MeV)^2}+.511MeV\approx 11000.511 MeV</math>
 
| style="background: gray"      | <math>\Longrightarrow E\equiv \sqrt{(11000 MeV)^2+(.511 MeV)^2}+.511MeV\approx 11000.511 MeV</math>
 
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Latest revision as of 18:53, 15 May 2018

[math]\underline{\textbf{Navigation}}[/math]

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Initial Lab Frame 4-momentum components

Lab.png
Figure 1: Definition of variables in the Lab Frame


Begining with the assumption that the incoming electron, p1, has momentum of 11000 MeV in the positive z direction.


[math]\vec p_{1(z)}\equiv \vec p_{1}=11000 MeV \widehat {z}[/math]


We can also assume the Moller electron, p2, is initially at rest


[math]\vec p_{2}\equiv 0[/math]


This gives the total energy in this frame as


[math]E\equiv E_1+E_2[/math]


where,

[math]E\equiv \sqrt{p^2+m^2}[/math]


This gives,

[math]E\equiv \sqrt{(p_{1})^2+(m_{1})^2}+m_{2}[/math]


[math]\Longrightarrow E\equiv \sqrt{(11000 MeV)^2+(.511 MeV)^2}+.511MeV\approx 11000.511 MeV[/math]



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