Difference between revisions of "Absorbed Dose Information"

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- Shultis, Faw, Fundamentals of Nuclear Science and Engineering, 3rd Edition, pg 274.
 
- Shultis, Faw, Fundamentals of Nuclear Science and Engineering, 3rd Edition, pg 274.
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[[Thesis]]
 
  
[[Linac Run Plan April 2018, Dr. McNulty]]
 
  
  
  
  
<math> 20MeV*0.05\mu A = 20eV*0.05A = 1 eV*A</math>
 
  
<math>= 1.6*10^{-19}J*A = 1.6*10^{-19}J*\frac{C}{s}</math>
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[[Thesis]]
  
<math>1.6*10^{-19}\frac{J\ C}{s} * \frac{1 \ e-}{1.6*10^{-19}C} = 1 Watt\ e-</math>
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[[Linac Run Plan April 2018, Dr. McNulty]]

Latest revision as of 18:01, 16 April 2018

[math]D \equiv \lim_{_{_{ \! \!\! \! \! \! \! Δ m \rightarrow 0}}}{\frac{Δ \bar ε}{Δ m}}[/math]

"The absorbed dose is the quotient of the mean energy imparted [math]\bar ε[/math] to matter of mass [math]Δ m[/math], in the limit as the mass approaches zero."

"Here [math]\bar ε[/math] is the expected energy imparted to the medium averaged over all stochastic fluctuations"

Stochastic fluctuations -> (random processes)

[math] 1 rad = 100 \frac{ergs}{gram} = 0.01 Gy[/math]

[math] 1 Gy = 1 \frac{joule}{kilogram}[/math]


- Shultis, Faw, Fundamentals of Nuclear Science and Engineering, 3rd Edition, pg 274.





Thesis

Linac Run Plan April 2018, Dr. McNulty