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| z | | z |
| \end{bmatrix}</math></center> | | \end{bmatrix}</math></center> |
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| | We can express the space time interval using the index notation |
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| | <center><math>(ds)^2\equiv c^2 dt^{'2}-dx^{'2}-dy^{'2}-dz^{'2}= c^2 dt^{2}-dx^2-dy^2-dz^2</math></center> |
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| | <center><math>(ds)^2\equiv (dx^0)^{'2}-(dx^1)^{'2}-(dx^2)^{'2}-(dx^3)^{'2}= (dx^0)^{2}-(dx^1)^2-(dx^2)^2-(dx^3)^2</math></center> |
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| | <center>Since <math>ds^2 </math> is nothing more than a dot product of a vector with itself, we should expect the components of the indices to follow a similar relationship.</center> |
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| | <center><math>(ds)^2\equiv |
| | \begin{bmatrix} |
| | dx_0 & -dx_1 & -dx_2 & -dx_3 |
| | \end{bmatrix} \cdot |
| | \begin{bmatrix} |
| | dx^0 \\ |
| | dx^1 \\ |
| | dx^2 \\ |
| | dx^3 |
| | \end{bmatrix}= (dx^0)^{2}-(dx^1)^2-(dx^2)^2-(dx^3)^2=(dx^0)^{'2}-(dx^1)^{'2}-(dx^2)^{'2}-(dx^3)^{'2}</math></center> |
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| We can express the space time interval using the index notation
| |
|
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| <center><math>(ds)^2\equiv c^2 dt^{'2}-dx^{'2}-dy^{'2}-dz^{'2}= c^2 dt^{2}-dx^2-dy^2-dz^2</math></center>
| |
|
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|
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|
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| <center><math>(ds)^2\equiv (dx^0)^{'2}-(dx^1)^{'2}-(dx^2)^{'2}-(dx^3)^{'2}= (dx^0)^{2}-(dx^1)^2-(dx^2)^2-(dx^3)^2</math></center>
| |
|
| |
|
| |
|
| |
| <center>Since <math>ds^2 </math> is nothing more than a dot product of a vector with itself, we should expect the components of the indices to follow a similar relationship.
| |
|
| |
|
| |
|
| |
| <center><math>(ds)^2\equiv
| |
| \begin{bmatrix}
| |
| dx_0 & -dx_1 & -dx_2 & -dx_3
| |
| \end{bmatrix} \cdot
| |
| \begin{bmatrix}
| |
| dx^0 \\
| |
| dx^1 \\
| |
| dx^2 \\
| |
| dx^3
| |
| \end{bmatrix}= (dx^0)^{2}-(dx^1)^2-(dx^2)^2-(dx^3)^2=(dx^0)^{'2}-(dx^1)^{'2}-(dx^2)^{'2}-(dx^3)^{'2}</math></center>
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|
| ---- | | ---- |
Revision as of 02:11, 6 June 2017
[math]\displaystyle{ \textbf{\underline{Navigation}} }[/math]
[math]\displaystyle{ \vartriangleleft }[/math]
[math]\displaystyle{ \triangle }[/math]
[math]\displaystyle{ \vartriangleright }[/math]
4-vectors
Using index notation, the time and space coordinates can be combined into a single "4-vector" [math]\displaystyle{ x^{\mu},\ \mu=0,\ 1,\ 2,\ 3 }[/math], that has units of length, i.e. ct is a distance.
[math]\displaystyle{ \begin{bmatrix}
x^0 \\
x^1 \\
x^2 \\
x^3
\end{bmatrix}=
\begin{bmatrix}
ct \\
x \\
y \\
z
\end{bmatrix} }[/math]
We can express the space time interval using the index notation
[math]\displaystyle{ (ds)^2\equiv c^2 dt^{'2}-dx^{'2}-dy^{'2}-dz^{'2}= c^2 dt^{2}-dx^2-dy^2-dz^2 }[/math]
[math]\displaystyle{ (ds)^2\equiv (dx^0)^{'2}-(dx^1)^{'2}-(dx^2)^{'2}-(dx^3)^{'2}= (dx^0)^{2}-(dx^1)^2-(dx^2)^2-(dx^3)^2 }[/math]
Since [math]\displaystyle{ ds^2 }[/math] is nothing more than a dot product of a vector with itself, we should expect the components of the indices to follow a similar relationship.
[math]\displaystyle{ (ds)^2\equiv
\begin{bmatrix}
dx_0 & -dx_1 & -dx_2 & -dx_3
\end{bmatrix} \cdot
\begin{bmatrix}
dx^0 \\
dx^1 \\
dx^2 \\
dx^3
\end{bmatrix}= (dx^0)^{2}-(dx^1)^2-(dx^2)^2-(dx^3)^2=(dx^0)^{'2}-(dx^1)^{'2}-(dx^2)^{'2}-(dx^3)^{'2} }[/math]
Using the Lorentz transformations and the index notation,
[math]\displaystyle{
\begin{cases}
t'=\gamma (t-vz/c^2) \\
x'=x' \\
y'=y' \\
z'=\gamma (z-vt)
\end{cases}
}[/math]
[math]\displaystyle{ \begin{bmatrix}
x'^0 \\
x'^1 \\
x'^2\\
x'^3
\end{bmatrix}=
\begin{bmatrix}
\gamma (x^0-vx^3/c) \\
x^1 \\
x^2 \\
\gamma (x^3-vx^0)
\end{bmatrix}
=
\begin{bmatrix}
\gamma (x^0-\beta x^3) \\
x^1 \\
x^2 \\
\gamma (x^3-vx^0)
\end{bmatrix} }[/math]
Where [math]\displaystyle{ \beta \equiv \frac{v}{c} }[/math]
This can be expressed in matrix form as
[math]\displaystyle{ \begin{bmatrix}
x'^0 \\
x'^1 \\
x'^2\\
x'^3
\end{bmatrix}=
\begin{bmatrix}
\gamma & 0 & 0 & -\gamma \beta \\
0 & 1 & 0 & 0 \\
0 & 0 & 1 & 0 \\
-\gamma \beta & 0 & 0 & \gamma
\end{bmatrix}
\cdot
\begin{bmatrix}
x^0 \\
x^1 \\
x^2 \\
x^3
\end{bmatrix} }[/math]
Letting the indices run from 0 to 3, we can write
[math]\displaystyle{ x'^{\mu}=\sum_{\nu=0}^3 (\Lambda_{\nu}^{\mu})x^{\nu} }[/math]
Where [math]\displaystyle{ \Lambda }[/math] is the Lorentz transformation matrix for motion in the z direction.
[math]\displaystyle{ \textbf{\underline{Navigation}} }[/math]
[math]\displaystyle{ \vartriangleleft }[/math]
[math]\displaystyle{ \triangle }[/math]
[math]\displaystyle{ \vartriangleright }[/math]