Two bricks x-pinch driver notes - Revision history

Shaproma: Blanked the page

2014-10-30T20:51:13Z

Blanked the page

Shaproma: /* Minimum operating current */

2014-02-07T03:34:49Z

Minimum operating current

Shaproma at 03:34, 7 February 2014

2014-02-07T03:34:09Z

Shaproma: /* Minimum operating current */

2014-02-07T03:33:57Z

Minimum operating current

Shaproma: Created page with "[https://wiki.iac.isu.edu/index.php/RS#Compact_and_Portable_X-Pinch_Driver go back] =Minimum operating current= *There is a minimum operating current due to need to work in t…"

2014-02-07T03:33:15Z

Created page with "[https://wiki.iac.isu.edu/index.php/RS#Compact_and_Portable_X-Pinch_Driver go back] =Minimum operating current= *There is a minimum operating current due to need to work in t…"

New page

[https://wiki.iac.isu.edu/index.php/RS#Compact_and_Portable_X-Pinch_Driver go back]

=Minimum operating current=

*There is a minimum operating current due to need to work in the magnetic self-isolating regime [L. E. Aranchuk, A. S. Chuvatin, and J. Larour, Rev. Sci. Instrum. 75, 69 (2004)]

*For our geometry (6 mm gam, 2.5" anode and 2" cathode) and taking min voltage 50 kV, the minimum operating current will be

<math> I = 0.64 \sqrt(V) \ (\ln(R_a/R_c) ) </math> = 22 kA

← Older revision		Revision as of 20:51, 30 October 2014
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−	~~[https://wiki.iac.isu.edu/index.php/RS#Compact_and_Portable_X-Pinch_Driver go back]~~

−
−
−	~~=Minimum operating current=~~
−
−	*There is a minimum operating current due to need to work in the magnetic self-isolating regime [L. E. Aranchuk, A. S. Chuvatin, and J. Larour, Rev. Sci. Instrum. 75, 69 (2004)]
−
−	*For our geometry (6 mm gam, 2.5" anode and 2" cathode) and taking min voltage 60 kV, the minimum operating current will be
−
−	~~<math> I = 0.64 \sqrt{V} \ \ln{R_a/R_c} = 22 kA</math>~~

@@ Line 7: / Line 7: @@
 *There is a minimum operating current due to need to work in the magnetic self-isolating regime [L. E. Aranchuk, A. S. Chuvatin, and J. Larour, Rev. Sci. Instrum. 75, 69 (2004)]
-*For our geometry (6 mm gam, 2.5" anode and 2" cathode) and taking min voltage 50 kV, the minimum operating current will be
+*For our geometry (6 mm gam, 2.5" anode and 2" cathode) and taking min voltage 60 kV, the minimum operating current will be
 <math>  I = 0.64 \sqrt{V} \ \ln{R_a/R_c} = 22 kA</math>

← Older revision		Revision as of 03:34, 7 February 2014
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	*For our geometry (6 mm gam, 2.5" anode and 2" cathode) and taking min voltage 50 kV, the minimum operating current will be		*For our geometry (6 mm gam, 2.5" anode and 2" cathode) and taking min voltage 50 kV, the minimum operating current will be

−	<math> I = 0.64 \sqrt{V} \ (\ln{R_a/R_c} = 22 kA</math>	+	<math> I = 0.64 \sqrt{V} \ \ln{R_a/R_c} = 22 kA</math>

← Older revision		Revision as of 03:33, 7 February 2014
Line 9:		Line 9:
	*For our geometry (6 mm gam, 2.5" anode and 2" cathode) and taking min voltage 50 kV, the minimum operating current will be		*For our geometry (6 mm gam, 2.5" anode and 2" cathode) and taking min voltage 50 kV, the minimum operating current will be

−	<math> I = 0.64 \sqrt(V) \ (\ln(R_a/R_c~~) )~~ </math> ~~= 22 kA~~	+	<math> I = 0.64 \sqrt{V} \ (\ln{R_a/R_c} = 22 kA</math>