Tamar Electron and Pion Efficiency - Revision history

Didbtama: /* Inclusive and Semi-Inclusive Efficiencies */

2011-08-10T15:01:22Z

Inclusive and Semi-Inclusive Efficiencies

Foretony: /* Inclusive and Semi-Inclusive Efficiencies */

2011-08-10T05:24:30Z

Inclusive and Semi-Inclusive Efficiencies

Didbtama: /* Inclusive and Semi-Inclusive Efficiencies */

2011-08-10T04:08:27Z

Inclusive and Semi-Inclusive Efficiencies

Didbtama: /* Inclusive and Semi-Inclusive Efficiencies */

2011-07-25T22:02:00Z

Inclusive and Semi-Inclusive Efficiencies

Didbtama: /* Inclusive and Semi-Inclusive Efficiencies */

2011-07-20T14:51:49Z

Inclusive and Semi-Inclusive Efficiencies

Foretony: /* Inclusive and Semi-Inclusive Efficiencies */

2011-07-20T13:58:55Z

Inclusive and Semi-Inclusive Efficiencies

Foretony: /* Inclusive and Semi-Inclusive Efficiencies */

2011-07-20T13:57:19Z

Inclusive and Semi-Inclusive Efficiencies

Foretony: /* Inclusive and Semi-Inclusive Efficiencies */

2011-07-20T13:55:19Z

Inclusive and Semi-Inclusive Efficiencies

Foretony: /* Inclusive and Semi-Inclusive Efficiencies */

2011-07-20T13:55:01Z

Inclusive and Semi-Inclusive Efficiencies

Didbtama: /* Inclusive and Semi-Inclusive Efficiencies */

2011-07-20T05:48:23Z

Inclusive and Semi-Inclusive Efficiencies

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 The EG1b data for kinematics chosen above show the same shape as E99-107 data.
-=Inclusive  and Semi-Inclusive Efficiencies=
+=Inclusive  and Exclusive Efficiencies=
 The goal of this thesis is to measure the semi-inclusive asymmetry when an electron and a pion are detected in the final state.   Pions of opposite charge will be observed using the same scintillator by flipping the CLAS Torus magnetic field direction. Although the pions will be detected by the same detector elements, the electrons will intersect different detector elements.  As a result, the electron efficiency will need to be evaluated in terms of the electron rate observed in two different scintillator paddles detecting the same electron kinematics.   Pairs of scintillator paddles  with the highest semi-inclusive rate.

← Older revision		Revision as of 05:24, 10 August 2011
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	The electron efficiency of individual scintillator detectors using the 4.2 GeV data for ND3 and NH3 targets is investigated below. Only the electron is detection in the final state (inclusive case). The pion contamination in the electron sample was removed by the applying cuts described above. The electron paddle number 10 (B<0) and 5 (B>0) were chosen respectively because they contained the most electron events in a first pass semi-inclusive pion analysis of the data set. The electron kinematics(Momentum, scattering angle and invariant mass) for these scintillators is shown on Fig. 3.1.		The electron efficiency of individual scintillator detectors using the 4.2 GeV data for ND3 and NH3 targets is investigated below. Only the electron is detection in the final state (inclusive case). The pion contamination in the electron sample was removed by the applying cuts described above. The electron paddle number 10 (B<0) and 5 (B>0) were chosen respectively because they contained the most electron events in a first pass semi-inclusive pion analysis of the data set. The electron kinematics(Momentum, scattering angle and invariant mass) for these scintillators is shown on Fig. 3.1.
		+
		+	FC is not a unit, you need to use the calibration to convert FC counts to nC

	{\| border="1" \|cellpadding="20" cellspacing="0		{\| border="1" \|cellpadding="20" cellspacing="0

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 After applying correction coefficients from inclusive cases, the ratios have been compared to the results from MAID2007.
-[[File:black_red_maid_inclusiveerror.png|350px]] [[File:green_blue_inclusiveerror.png|350px]]
+[[File:negativepionND3beforecorrection.png|350px]] [[File:negativepionND3aftercorrection.png|350px]]
-'''Figure 3.3.  Pion paddle number vs Ratio after correction.'''
+[[File:positivepionND3beforecorrection.png|350px]] [[File:positivepionND3aftercorrection.png|350px]]
 Applied corrections are following:

@@ Line 51: / Line 51: @@
 {| border="1"  |cellpadding="20" cellspacing="0
 |-
-|[[File:EmomInclusiveoverlay4-2GeV.gif|300px]] ||[[File:EthetaInclusiveoverlay4-2GeV.gif|300px]] || [[File:WInclusiveoverlay4-2GeV.gif|300px]]
+|[[File:EmomInclusiveoverlay4-2GeVfcup.gif|300px]] ||[[File:EthetaInclusiveoverlay4-2GeVfcup.gif|300px]] || [[File:WInclusiveoverlay4-2GeVfcup.gif|300px]]
 |-
 | Electron Momentum((NH3,B>0),  (NH3,B<0), (ND3,B>0) && (ND3,B<0))|| Electron Scattering Angle <math>\theta</math>((NH3,B>0),  (NH3,B<0), (ND3,B>0) && (ND3,B<0))|| W Invariant mass((NH3,B>0),  (NH3,B<0), (ND3,B>0) && (ND3,B<0))

← Older revision		Revision as of 14:51, 20 July 2011
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−	Notice the ratio is statistically the same if the NH3 and ND3 targets are used for this ratio in a manner which will be similar ~~for~~ the semi-inclusive analysis.	+	Notice the ratio is statistically the same if the NH3 and ND3 targets are used for this ratio in a manner which will be similar to the semi-inclusive analysis.

	<math>\frac{ND3,B>0, PaddleNumber^{e^-}=5}{NH3,B<0, PaddleNumber^{e^-}=10}=1.55 \pm 0.15</math>		<math>\frac{ND3,B>0, PaddleNumber^{e^-}=5}{NH3,B<0, PaddleNumber^{e^-}=10}=1.55 \pm 0.15</math>

← Older revision		Revision as of 13:58, 20 July 2011
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−	To be able to compare our results to the MAID 2007, the ratio of the number of electrons were taken for different types of target for inbending and outbending cases. The Faraday cup normalized ratios are shown below.	+	The ratio of the pions detected in the scintillator paddles, located between the Cherenkov counter and electromagnetic calorimeter, is shown on Fig. 3.2. The ratios were taken for four different cases. Assuming that, for the inbending case positive pions and for the outbending case negative pions have the same trajectories(the same kinematics) and vice versa((the inbending,negative pion) and (the outbending, positive pions)).<br>
−
−	~~<math>\frac{ND3,B>0, PaddleNumber^{e^-}=5}{NH3,B<0, PaddleNumber^{e^-}=10}=1.55 \pm 0.15</math>~~
−
−	~~<math>\frac{ND3,B<0, PaddleNumber^{e^-}=10}{NH3,B>0, PaddleNumber^{e^-}=5}=0.55 \pm 0.06</math>~~
−
−	In order to make detector efficiency the same for electrons, the ratios need to be adjusted so that it equals to one. Each of the two cases are multiplied by a correction coefficient determined from the inclusive electron rates. The correction coefficient for the case <math>\frac{ND3,B>0,E_{PaddleNumber}=5}{NH3,B<0,E_{PaddleNumber}=10}</math> is <math>0.645</math> and for the <math>\frac{ND3,B<0,E_{PaddleNumber}=10}{NH3,B>0,E_{PaddleNumber}=5}</math> it is <math>1.82</math>.
−
−
−
−	~~In this chapter we discuss the pion efficiency in semi-inclusive case.~~ The ratio of the pions detected in the scintillator paddles, located between the Cherenkov counter and electromagnetic calorimeter, is shown on Fig. 3.2. The ratios were taken for four different cases. Assuming that, for the inbending case positive pions and for the outbending case negative pions have the same trajectories(the same kinematics) and vice versa((the inbending,negative pion) and (the outbending, positive pions)).<br>

	[[File:paddenumbvsratio.jpg\|500px]]<br>		[[File:paddenumbvsratio.jpg\|500px]]<br>

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-The above ratios, which have been observed to be ammonia target independent, indicate a difference in electron detector efficiency when the Torus polarity is flipped.  The above ratios appear to be inverses of each other.  The ratio of inbending electrons hitting paddle 5 to the outbending hitting paddle 10 is the inverse of the inbending. In order to make detector efficiency the same for electrons, the ratios need to be adjusted so that it equals to one. Each of the two cases are multiplied by so called "correction coefficient". The "correction coefficient" for the case <math>\frac{ND3,B>0,E_{PaddleNumber}=5}{NH3,B<0,E_{PaddleNumber}=10}</math> is <math>0.645</math> and for the <math>\frac{ND3,B<0,E_{PaddleNumber}=10}{NH3,B>0,E_{PaddleNumber}=5}</math> it is <math>1.82</math>.
+The above ratios, which have been observed to be ammonia target independent, indicate a difference in electron detector efficiency when the Torus polarity is flipped.  In order to make detector efficiency the same for electrons, the ratios were used as a "correction coefficient".   The "correction coefficient" for the case <math>\frac{ND3,B>0,E_{PaddleNumber}=5}{NH3,B<0,E_{PaddleNumber}=10}</math> is <math>0.645</math> and for the <math>\frac{ND3,B<0,E_{PaddleNumber}=10}{NH3,B>0,E_{PaddleNumber}=5}</math> it is <math>1.82</math>.
-The measured single pion electroproduction rate was compared to the MAID 2007 unitary model that has been developed using the world data of pion photo and electroproduction. The model is well adopted for predictions of the observables for pion production, like five fold cross section, total cross secton and etc.
+The measured single pion electroproduction rate was compared to the MAID 2007 unitary model that has been developed using the world data of pion photo and electro-production to determine the impact of using the above "correction coefficient". The model is well adopted for predictions of the observables for pion production, like five fold cross section, total cross secton and etc.
 The MAID 2007 model has predictions of the total cross section for the following two cases, that are related to our work:<br>

← Older revision		Revision as of 13:55, 20 July 2011
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−	The above ratios, which have been observed to be target independent, indicate a difference in electron detector efficiency when the Torus polarity is flipped. The above ratios appear to be inverses of each other. The ratio of inbending electrons hitting paddle 5 to the outbending hitting paddle 10 is the inverse of the inbending. In order to make detector efficiency the same for electrons, the ratios need to be adjusted so that it equals to one. Each of the two cases are multiplied by so called "correction coefficient". The "correction coefficient" for the case <math>\frac{ND3,B>0,E_{PaddleNumber}=5}{NH3,B<0,E_{PaddleNumber}=10}</math> is <math>0.645</math> and for the <math>\frac{ND3,B<0,E_{PaddleNumber}=10}{NH3,B>0,E_{PaddleNumber}=5}</math> it is <math>1.82</math>.	+	The above ratios, which have been observed to be ammonia target independent, indicate a difference in electron detector efficiency when the Torus polarity is flipped. The above ratios appear to be inverses of each other. The ratio of inbending electrons hitting paddle 5 to the outbending hitting paddle 10 is the inverse of the inbending. In order to make detector efficiency the same for electrons, the ratios need to be adjusted so that it equals to one. Each of the two cases are multiplied by so called "correction coefficient". The "correction coefficient" for the case <math>\frac{ND3,B>0,E_{PaddleNumber}=5}{NH3,B<0,E_{PaddleNumber}=10}</math> is <math>0.645</math> and for the <math>\frac{ND3,B<0,E_{PaddleNumber}=10}{NH3,B>0,E_{PaddleNumber}=5}</math> it is <math>1.82</math>.

@@ Line 60: / Line 60: @@
 Ratios of the inclusive electron rate, normalized using the FC, of scintillator paddles 5 and 10 were measured.   The two ratios are designed to measure the CLAS detectors ability to observed the same electron kinematics using different detector elements positioned for opposite Torus polarities.
 <math>\frac{ND3,B>0, PaddleNumber^{e^-}=5}{NH3,B<0, PaddleNumber^{e^-}=10}=1.55 \pm 0.15</math>
-<math>\frac{ND3,B<0, PaddleNumber^{e^-}=10}{NH3,B>0, PaddleNumber^{e^-}=5}=0.55 \pm 0.06</math>
 The above ratios, which have been observed to be target independent, indicate a difference in electron detector efficiency when the Torus polarity is flipped.  The above ratios appear to be inverses of each other.  The ratio of inbending electrons hitting paddle 5 to the outbending hitting paddle 10 is the inverse of the inbending. In order to make detector efficiency the same for electrons, the ratios need to be adjusted so that it equals to one. Each of the two cases are multiplied by so called "correction coefficient". The "correction coefficient" for the case <math>\frac{ND3,B>0,E_{PaddleNumber}=5}{NH3,B<0,E_{PaddleNumber}=10}</math> is <math>0.645</math> and for the <math>\frac{ND3,B<0,E_{PaddleNumber}=10}{NH3,B>0,E_{PaddleNumber}=5}</math> it is <math>1.82</math>.

@@ Line 65: / Line 65: @@
 <math>\frac{ND3,B<0, PaddleNumber^{e^-}=10}{NH3,B>0, PaddleNumber^{e^-}=5}=0.55 \pm 0.06</math>
-The above ratios, which have been observed to be target independent, indicate a difference in electron detector efficiency when the Torus polarity is flipped.  The above ratios appear to be inverses of each other.  The ratio of inbending electrons hitting paddle 5 to the outbending hitting paddle 10 is the inverse of the inbenIn order to make detector efficiency the same for electrons, the ratios need to be adjusted so that it equals to one. Each of the two cases are multiplied by so called "correction coefficient".
+The above ratios, which have been observed to be target independent, indicate a difference in electron detector efficiency when the Torus polarity is flipped.  The above ratios appear to be inverses of each other.  The ratio of inbending electrons hitting paddle 5 to the outbending hitting paddle 10 is the inverse of the inbending. In order to make detector efficiency the same for electrons, the ratios need to be adjusted so that it equals to one. Each of the two cases are multiplied by so called "correction coefficient". The "correction coefficient" for the case <math>\frac{ND3,B>0,E_{PaddleNumber}=5}{NH3,B<0,E_{PaddleNumber}=10}</math> is <math>0.645</math> and for the <math>\frac{ND3,B<0,E_{PaddleNumber}=10}{NH3,B>0,E_{PaddleNumber}=5}</math> it is <math>1.82</math>.
@@ Line 85: / Line 86: @@
 <math>\frac{ND3,B<0, PaddleNumber^{e^-}=10}{NH3,B>0, PaddleNumber^{e^-}=5}=0.55 \pm 0.06</math>
-In order to make detector efficiency the same for electrons, the ratios need to be adjusted so that it equals to one. Each of the two cases are multiplied by a correction coefficient determined from the inclusive electron rates.
+In order to make detector efficiency the same for electrons, the ratios need to be adjusted so that it equals to one. Each of the two cases are multiplied by a correction coefficient determined from the inclusive electron rates. The correction coefficient for the case <math>\frac{ND3,B>0,E_{PaddleNumber}=5}{NH3,B<0,E_{PaddleNumber}=10}</math> is <math>0.645</math> and for the <math>\frac{ND3,B<0,E_{PaddleNumber}=10}{NH3,B>0,E_{PaddleNumber}=5}</math> it is <math>1.82</math>.