T-Channel - Revision history

Vanwdani at 18:49, 15 May 2018

2018-05-15T18:49:00Z

2017-06-12T22:58:16Z

t Channel

2017-06-09T23:31:11Z

t Channel

2017-06-09T23:20:00Z

t Channel

2017-06-09T23:19:38Z

t Channel

2017-06-09T23:18:59Z

t Channel

2017-06-09T23:07:56Z

t Channel

2017-06-09T23:05:36Z

t Channel

2017-06-09T22:22:54Z

t Channel

2017-06-09T22:16:47Z

t Channel

@@ Line 1: / Line 1: @@
-<center><math>\textbf{\underline{Navigation}}</math>
+<center><math>\underline{\textbf{Navigation}}</math>
 [[S-Channel|<math>\vartriangleleft </math>]]
@@ Line 58: / Line 58: @@
-<center><math>\textbf{\underline{Navigation}}</math>
+<center><math>\underline{\textbf{Navigation}}</math>
 [[S-Channel|<math>\vartriangleleft </math>]]

@@ Line 11: / Line 11: @@
 The t quantity is known as the square of the 4-momentum transfer
-<center><math>t \equiv \left({\mathbf P_1^*}- {\mathbf P_1^{'*}}\right)^2=\left({\mathbf P_2^{*}}+ {\mathbf P_2^{'*}}\right)^2</math></center>
+<center><math>t \equiv \left({\mathbf P_1^*}- {\mathbf P_1^{'*}}\right)^2=\left({\mathbf P_2^{*}}- {\mathbf P_2^{'*}}\right)^2</math></center>
 <center>[[File:400px-CMcopy.png]]</center>

← Older revision		Revision as of 23:31, 9 June 2017
Line 52:		Line 52:


−	<center><math>t \equiv -2 p \ _1^{*2}(1-cos\ \theta)</math></center>	+	<center><math>t \equiv -2 p \ ^{*2}(1-cos\ \theta)</math></center>

← Older revision		Revision as of 23:20, 9 June 2017
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−	and <math>\theta_1</math> is the angle between <math>\vec p \ _1^* <\math> and <math> \vec p \ _1^{'*}</math>	+	and <math>\theta_1</math> is the angle between <math>\vec p \ _1^* </math> and <math> \vec p \ _1^{'*}</math>

← Older revision		Revision as of 23:19, 9 June 2017
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−	and <math>\theta_1</math> is the angle between <math>\vec p \ _1^* and \vec p \ _1^{'*}</math>	+	and <math>\theta_1</math> is the angle between <math>\vec p \ _1^* <\math> and <math> \vec p \ _1^{'*}</math>

← Older revision		Revision as of 23:18, 9 June 2017
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−	<center><math>\|p^\| \equiv \vec p \ _1^\|=\| \vec p \ _1^{'}\| = \vec p \ _2^\|=\| \vec p \ _2^{'*}\|</math></center>	+	<center><math>\|p^\| \equiv \| \vec p \ _1^\|=\| \vec p \ _1^{'}\| =\| \vec p \ _2^\|=\| \vec p \ _2^{'*}\|</math></center>
		+
		+
		+	and <math>\theta_1</math> is the angle between <math>\vec p \ _1^* and \vec p \ _1^{'*}</math>

@@ Line 29: / Line 29: @@
 In the center of mass frame of reference,
-<center><math> E_1^*=E_1^{'*} \quad E_2^*=E_2^{'*} \quad E_1^*=E_2^*</math></center>
+<center><math> E^* \equiv E_1^*=E_1^{'*} = E_2^*=E_2^{'*} = E_1^*=E_2^*</math></center>
@@ Line 35: / Line 35: @@
-<center><math>| \vec p \ _1^*|=| \vec p \ _1^{'*}| \quad | \vec p \ _2^*|=| \vec p \ _2^{'*}|</math></center>
+<center><math>|p^*| \equiv \vec p \ _1^*|=| \vec p \ _1^{'*}| = \vec p \ _2^*|=| \vec p \ _2^{'*}|</math></center>
-<center><math>t \equiv 2m_1^*-2E_1^{*2}+2  p \ _1^{*2}cos\ \theta</math></center>
+<center><math>t \equiv 2m_1^*-2E_1^{*2}+2   |p |^{*2}cos\ \theta</math></center>

← Older revision		Revision as of 23:05, 9 June 2017
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−	~~<center><math>t \equiv 2m_1^-2E_1^{2}+2 \vec p \ _1^{*2}cos\ \theta</math></center>~~

		+	In the center of mass frame of reference,

−	<center><math>t \equiv -2 \vec p \ _1^{*2}(1-cos\ \theta)</math></center>	+	<center><math> E_1^=E_1^{'} \quad E_2^=E_2^{'} \quad E_1^=E_2^</math></center>
		+
		+
		+	and
		+
		+
		+	<center><math>\| \vec p \ _1^\|=\| \vec p \ _1^{'}\| \quad \| \vec p \ _2^\|=\| \vec p \ _2^{'}\|</math></center>
		+
		+
		+
		+	<center><math>t \equiv 2m_1^-2E_1^{2}+2 p \ _1^{*2}cos\ \theta</math></center>
		+
		+
		+	Using the relativistic term for Energy
		+
		+
		+	<center><math>E^2=\vec p \ ^2+m^2</math></center>
		+
		+
		+
		+	<center><math>t \equiv -2 p \ _1^{*2}(1-cos\ \theta)</math></center>

@@ Line 23: / Line 23: @@
-<center><math>t \equiv 2m_1^2-2E_1^*E_1^{'*}+2p_1^*p_1^{'*}</math></center>
+<center><math>t \equiv 2m_1^2-2E_1^*E_1^{'*}+2 \vec p \ _1^* \vec p \ _1^{'*}</math></center>
-<center><math>t \equiv 2m_1^*-2E_1^{*2}+2p_1^{*2}cos\ \theta</math></center>
+<center><math>t \equiv 2m_1^*-2E_1^{*2}+2 \vec  p \ _1^{*2}cos\ \theta</math></center>
-<center><math>t \equiv -2p_1^{*2}(1-cos\ \theta)</math></center>
+<center><math>t \equiv -2 \vec p \ _1^{*2}(1-cos\ \theta)</math></center>

← Older revision		Revision as of 22:16, 9 June 2017
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−	<center><math>t \equiv P_1^{2}-~~2P_1~~^P_1^{'}+P_1^{'2}</math></center>	+	<center><math>t \equiv \mathbf P_1^{2}-2 \mathbf P_1^ \mathbf P_1^{'}+ \mathbf P_1^{'2}</math></center>