Rotating Tungsten Target System - Revision history

Setisadi: /* Test */

2012-09-29T00:03:15Z

Test

2012-09-29T00:02:15Z

Test

2012-09-28T23:48:17Z

Test

2012-09-28T23:42:45Z

Test

2012-09-28T23:28:05Z

Test

2012-09-28T23:17:11Z

W disk inertia calculation

2012-09-28T23:12:45Z

W disk inertia calculation

2012-09-28T23:11:23Z

W disk inertia calculation

2012-09-28T23:10:51Z

W disk inertia calculation

2012-09-28T23:10:05Z

W disk inertia calculation

@@ Line 118: / Line 118: @@
 Weight of the Al slab is 235 and 240 grams. Their center of mass are 13 +- 1 cm from the center of disk.
 Inertia Solid cuboid of height h, width w, and depth d, and mass m: <math>I_h~=~\frac{1}{12}m(w^2+d^2)</math>
@@ Line 129: / Line 127: @@
 I was able to rotate these two slabs with with maximum frequencies from the pulser

← Older revision		Revision as of 00:02, 29 September 2012
Line 124:		Line 124:

	<math>I_h~=~\frac{1}{12}0.2375(0.126^2+0.72^2) =\frac{1}{12} 0.2375 \times 0.534276 =\frac{1}{12} 0.12689055 = 0.0106</math>		<math>I_h~=~\frac{1}{12}0.2375(0.126^2+0.72^2) =\frac{1}{12} 0.2375 \times 0.534276 =\frac{1}{12} 0.12689055 = 0.0106</math>
		+
		+
		+	<math>I_d = I_h + md^2 = 0.0106 + 0.2375 \times 0.13^2 = 0.0106 + 0.00401375 = 0.01461375 </math>

← Older revision		Revision as of 23:48, 28 September 2012
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	rough estimate: <math>2I =2 \frac{ml^2}{2} =2 \frac{0.2375~kg \times (0.13~m)^2}{2} =2 \times 0.002 ~ kg m^2 = 0.004 ~ kg m^2</math>		rough estimate: <math>2I =2 \frac{ml^2}{2} =2 \frac{0.2375~kg \times (0.13~m)^2}{2} =2 \times 0.002 ~ kg m^2 = 0.004 ~ kg m^2</math>

−	Inertia Solid cuboid of height h, width w, and depth d, and mass m: <math>I_h~=~\frac{1}{12}m(w^2+d^2)</math>	+	Inertia Solid cuboid of height h, width w, and depth d, and mass m: <math>I_h~=~\frac{1}{12}m(w^2+d^2)</math>
		+
		+	<math>I_h~=~\frac{1}{12}0.2375(0.126^2+0.72^2) =\frac{1}{12} 0.2375 \times 0.534276 =\frac{1}{12} 0.12689055 = 0.0106</math>

← Older revision		Revision as of 23:42, 28 September 2012
Line 119:		Line 119:
	Weight of the Al slab is 235 and 240 grams. Their center of mass are 13 +- 1 cm from the center of disk.		Weight of the Al slab is 235 and 240 grams. Their center of mass are 13 +- 1 cm from the center of disk.

−	<math>2I =2 \frac{ml^2}{2} =2 \frac{0.2375~kg \times (0.13~m)^2}{2} =2 \times 0.002 ~ kg m^2 = 0.004 ~ kg m^2</math>	+	rough estimate: <math>2I =2 \frac{ml^2}{2} =2 \frac{0.2375~kg \times (0.13~m)^2}{2} =2 \times 0.002 ~ kg m^2 = 0.004 ~ kg m^2</math>
		+
		+	Inertia Solid cuboid of height h, width w, and depth d, and mass m: <math>I_h~=~\frac{1}{12}m(w^2+d^2)</math>

@@ Line 119: / Line 119: @@
 Weight of the Al slab is 235 and 240 grams. Their center of mass are 13 +- 1 cm from the center of disk.
-<math>I = \frac{ml^2}{2} = \frac{0.2375~kg \times (0.13~m)^2}{2} = 0.002 ~ kg m^2 </math>
+<math>2I =2 \frac{ml^2}{2} =2 \frac{0.2375~kg \times (0.13~m)^2}{2} =2 \times 0.002 ~ kg m^2  = 0.004 ~ kg m^2</math>
 I was able to rotate these two slabs with with maximum frequencies from the pulser

@@ Line 141: / Line 141: @@
-<math>I_z~=~\frac{1}{2} \pi \rho h (r_2^4 - r_1^4) = 0.5~\times~3.14~\times~19.25~\times~10^3~kg·m^{-1}~1.016~\times10^{-3}~\times~((0.3683~m)^4 - (0.14605~m)^4) </math>
+<math>I_z~=~\frac{1}{2} \pi \rho h (r_2^4 - r_1^4) = 0.5~\times~3.14~\times~19.25~\times~10^3~kg·m^{-1}~1.016~\times10^{-3}~\times~((0.3683/2~m)^4 - (0.14605/2~m)^4) </math>
-<math>I_z = 0.5*3.14*19.25*10^3*1.016*10^{-3}*(0.3683^4 - 0.14605^4)</math>
+<math>I_z = 0.5*3.14*19.25*10^3*1.016*10^{-3}*((0.3683/2)^4 - (0.14605/2)^4)</math>
-<math>I_z = 30.70606* (0.0179445) = 0.551 </math>
+<math>I_z = 30.70606* (0.00112153384) = 0.0344 </math>

@@ Line 143: / Line 143: @@
 <math>I_z~=~\frac{1}{2} \pi \rho h (r_2^4 - r_1^4) = 0.5~\times~3.14~\times~19.25~\times~10^3~kg·m^{-1}~1.016~\times10^{-3}~\times~((0.3683~m)^4 - (0.14605~m)^4) </math>
-<math>I_z = 0.5*3.14*19.25*10^3*1.016*10^{-3}*((0.3683)^4 - (0.14605)^4)</math>
+<math>I_z = 0.5*3.14*19.25*10^3*1.016*10^{-3}*(0.3683^4 - 0.14605^4)</math>
 <math>I_z = 0.5*3.14*19.25*1.016*((0.3683)^4 - (0.14605)^4) = 0.551 </math>