Relativistic Units - Revision history

Vanwdani at 18:46, 15 May 2018

2018-05-15T18:46:27Z

2017-07-01T15:18:04Z

Relativistic Units

2017-07-01T15:01:58Z

Relativistic Units

2017-06-29T16:13:44Z

Relativistic Units

2017-06-29T14:47:07Z

Relativistic Units

2017-06-29T14:40:55Z

Relativistic Units

2017-06-29T14:40:38Z

Relativistic Units

2017-06-29T14:40:08Z

Relativistic Units

2017-06-29T14:01:36Z

2017-06-29T13:57:39Z

@@ Line 1: / Line 1: @@
-<center><math>\textbf{\underline{Navigation}}</math>
+<center><math>\underline{\textbf{Navigation}}</math>
 [[Relativistic_Frames_of_Reference|<math>\vartriangleleft </math>]]
@@ Line 113: / Line 113: @@
-<center><math>\textbf{\underline{Navigation}}</math>
+<center><math>\underline{\textbf{Navigation}}</math>
 [[Relativistic_Frames_of_Reference|<math>\vartriangleleft </math>]]

@@ Line 95: / Line 95: @@
-<center><math>1eV \equiv (1V)(1e^-)= \frac{1J}{1C}(1.6021766208(98)\times 10^{−19} C)=1.6021766208(98)\times 10^{−19} J</math></center>
+<center><math>1eV \equiv (1V)(1e^-)= \frac{1J}{1C}(1.6021766208(98)\times 10^{-19} C)=1.6021766208(98)\times 10^{-19} J</math></center>
-<center><math>\hbar \equiv 1.054571800(13)\times 10^{−34} J \cdot s \qquad c \equiv 2.99792458\frac{m}{s}</math></center>
+<center><math>\hbar \equiv 1.054571800(13)\times 10^{-34} J \cdot s \qquad c \equiv 2.99792458\frac{m}{s}</math></center>
 ----

← Older revision		Revision as of 15:01, 1 July 2017
Line 98:		Line 98:


		+	<center><math>\hbar \equiv 1.054571800(13)\times 10^{−34} J \cdot s \qquad c \equiv 2.99792458\frac{m}{s}</math></center>
		+
		+
		+	<center><math>\hbar c = 3.16152649\times 10^{−26} J\cdot m</math></center>
	----		----

← Older revision		Revision as of 16:13, 29 June 2017
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−	<center><math>\rightarrow mass\ units=\frac{1}{length\ units}=\frac{1}{time\ units}</math></center>	+	<center><math>\rightarrow Energy\ units=mass\ units=momentum\ units=\frac{1}{length\ units}=\frac{1}{time\ units}</math></center>


−
−	~~Since c is already to be defined as equal to zero, this implies unit of mass must also be equal to one. By convention, the mass of the proton is used~~
−
−	~~<center><math>M_{p} \equiv 1.6726219 \times 10^{-27} kg =1</math></center>~~

← Older revision		Revision as of 14:47, 29 June 2017
Line 48:		Line 48:
	<center><math>\therefore\ length\ units=time\ units</math></center>		<center><math>\therefore\ length\ units=time\ units</math></center>

−	This also implies that from the definition of an electromagnetic wave	+
		+	This also implies that from the definition of an electromagnetic wave

← Older revision		Revision as of 14:40, 29 June 2017
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−	<center><math>c \equiv \frac{1}{\sqrt{\epsilon_0 \mu_0} \rightarrow \epsilon_0=\mu_0=1</math></center>	+	<center><math>c \equiv \frac{1}{\sqrt{\epsilon_0 \mu_0}} \rightarrow \epsilon_0=\mu_0=1</math></center>

@@ Line 1: / Line 1: @@
 <center><math>\textbf{\underline{Navigation}}</math>
-[[4-momenta|<math>\vartriangleleft </math>]]
+[[Relativistic_Frames_of_Reference|<math>\vartriangleleft </math>]]
 [[VanWasshenova_Thesis#Moller_Scattering|<math>\triangle </math>]]
-[[Mandelstam_Representation|<math>\vartriangleright </math>]]
+[[4-vectors|<math>\vartriangleright </math>]]
 </center>
@@ Line 103: / Line 103: @@
 <center><math>\textbf{\underline{Navigation}}</math>
-[[4-momenta|<math>\vartriangleleft </math>]]
+[[Relativistic_Frames_of_Reference|<math>\vartriangleleft </math>]]
 [[VanWasshenova_Thesis#Moller_Scattering|<math>\triangle </math>]]
-[[Mandelstam_Representation|<math>\vartriangleright </math>]]
+[[4-vectors|<math>\vartriangleright </math>]]
 </center>

← Older revision		Revision as of 13:57, 29 June 2017
Line 1:		Line 1:
		+	<center><math>\textbf{\underline{Navigation}}</math>
		+
		+	[[4-momenta\|<math>\vartriangleleft </math>]]
		+	[[VanWasshenova_Thesis#Moller_Scattering\|<math>\triangle </math>]]
		+	[[Mandelstam_Representation\|<math>\vartriangleright </math>]]
		+
		+	</center>
		+
	=Relativistic Units=		=Relativistic Units=

Line 87:		Line 95:

	<center><math>1eV \equiv (1V)(1e^-)= \frac{1J}{1C}(1.6021766208(98)\times 10^{−19} C)=1.6021766208(98)\times 10^{−19} J</math></center>		<center><math>1eV \equiv (1V)(1e^-)= \frac{1J}{1C}(1.6021766208(98)\times 10^{−19} C)=1.6021766208(98)\times 10^{−19} J</math></center>
		+
		+
		+	----
		+
		+
		+
		+	<center><math>\textbf{\underline{Navigation}}</math>
		+
		+	[[4-momenta\|<math>\vartriangleleft </math>]]
		+	[[VanWasshenova_Thesis#Moller_Scattering\|<math>\triangle </math>]]
		+	[[Mandelstam_Representation\|<math>\vartriangleright </math>]]
		+
		+	</center>