Relative efficiency - Revision history

Kosiolek: /* The ratio of the integrated yields */

2014-09-22T15:33:09Z

The ratio of the integrated yields

Kosiolek: /* The ratio of the integrated yields */

2014-09-22T15:32:09Z

The ratio of the integrated yields

Kosiolek: /* The ratio of the integrated yields */

2014-09-22T15:31:46Z

The ratio of the integrated yields

Kosiolek: /* The ratio of the integrated yields */

2014-09-22T15:30:43Z

The ratio of the integrated yields

Kosiolek: /* The ratio of the integrated yields */

2014-09-22T15:30:31Z

The ratio of the integrated yields

Kosiolek: /* The ratio of the integrated yields */

2014-09-22T15:30:11Z

The ratio of the integrated yields

Kosiolek: /* The ratio of the integrated yields */

2014-09-22T15:29:47Z

The ratio of the integrated yields

Kosiolek: /* The ratio of the integrated yields */

2014-09-22T15:29:27Z

The ratio of the integrated yields

Kosiolek: /* The ratio of the integrated yields */

2014-09-22T15:27:05Z

The ratio of the integrated yields

Kosiolek: /* The ratio of the integrated yields */

2014-09-15T14:12:58Z

The ratio of the integrated yields

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 The ratio of the normalized integrated yields of correlated + uncorrelated neutrons per pulse <math>Y^{\text{tot}}=2.2E-5</math>  and calculated yield of uncorrelated neutrons per pulse <math>Y^{\text{2n/fisson}}=6.49E-6</math> gives the following number <math>\frac{Y^{\text{tot}}}{Y^{\text{2 fisson}}}=3.4</math>. If we want to get the ratio of pure yield of correlated neutrons <math>Y^{\text{1n/fission}}</math> over the yield of uncorrelated neutrons <math>Y^{\text{2n/fisson}}</math> we should take the difference <math>Y^{\text{1n/fission}}=Y^{\text{tot}}-Y^{\text{2n/fisson}}</math> and then take the ratio <math>\frac{Y^{\text{1n/fission}}}{Y^{\text{2n/fisson}}} = \frac{(2.2E-5)-(6.49E-6)}{6.49E-6}=2.4</math>
-Poisson distribution <math>P(n)=\frac{\bar{n}^n  e^{-\bar{n}}}{n!}</math> of the number of fission neutrons per fission event if the average number of neutrons emitted in fission event is 2.5 neutrons.
+Poisson distribution <math>P(n)=\frac{\bar{n}^n  e^{-\bar{n}}}{n!}=\frac{(2.5)^ne^{-2.5}}{n!}</math> of the number of fission neutrons per fission event if the average number of neutrons emitted in fission event is 2.5 neutrons.
 [[File:poisson_2_5n_ave.png | 500px]]

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 The ratio of the normalized integrated yields of correlated + uncorrelated neutrons per pulse <math>Y^{\text{tot}}=2.2E-5</math>  and calculated yield of uncorrelated neutrons per pulse <math>Y^{\text{2n/fisson}}=6.49E-6</math> gives the following number <math>\frac{Y^{\text{tot}}}{Y^{\text{2 fisson}}}=3.4</math>. If we want to get the ratio of pure yield of correlated neutrons <math>Y^{\text{1n/fission}}</math> over the yield of uncorrelated neutrons <math>Y^{\text{2n/fisson}}</math> we should take the difference <math>Y^{\text{1n/fission}}=Y^{\text{tot}}-Y^{\text{2n/fisson}}</math> and then take the ratio <math>\frac{Y^{\text{1n/fission}}}{Y^{\text{2n/fisson}}} = \frac{(2.2E-5)-(6.49E-6)}{6.49E-6}=2.4</math>
-Poisson distribution <math>P(n)=\frac{\bar{n}^n  e^{-n}}{}</math> of the number of fission neutrons per fission event if the average number of neutrons emitted in fission event is 2.5 neutrons.
+Poisson distribution <math>P(n)=\frac{\bar{n}^n  e^{-\bar{n}}}{n!}</math> of the number of fission neutrons per fission event if the average number of neutrons emitted in fission event is 2.5 neutrons.
 [[File:poisson_2_5n_ave.png | 500px]]

@@ Line 327: / Line 327: @@
 The ratio of the normalized integrated yields of correlated + uncorrelated neutrons per pulse <math>Y^{\text{tot}}=2.2E-5</math>  and calculated yield of uncorrelated neutrons per pulse <math>Y^{\text{2n/fisson}}=6.49E-6</math> gives the following number <math>\frac{Y^{\text{tot}}}{Y^{\text{2 fisson}}}=3.4</math>. If we want to get the ratio of pure yield of correlated neutrons <math>Y^{\text{1n/fission}}</math> over the yield of uncorrelated neutrons <math>Y^{\text{2n/fisson}}</math> we should take the difference <math>Y^{\text{1n/fission}}=Y^{\text{tot}}-Y^{\text{2n/fisson}}</math> and then take the ratio <math>\frac{Y^{\text{1n/fission}}}{Y^{\text{2n/fisson}}} = \frac{(2.2E-5)-(6.49E-6)}{6.49E-6}=2.4</math>
-Poisson distribution <math>P(n)=\frac{\={n}^n  e^{-n}}{}</math> of the number of fission neutrons per fission event if the average number of neutrons emitted in fission event is 2.5 neutrons.
+Poisson distribution <math>P(n)=\frac{\bar{n}^n  e^{-n}}{}</math> of the number of fission neutrons per fission event if the average number of neutrons emitted in fission event is 2.5 neutrons.
 [[File:poisson_2_5n_ave.png | 500px]]

@@ Line 327: / Line 327: @@
 The ratio of the normalized integrated yields of correlated + uncorrelated neutrons per pulse <math>Y^{\text{tot}}=2.2E-5</math>  and calculated yield of uncorrelated neutrons per pulse <math>Y^{\text{2n/fisson}}=6.49E-6</math> gives the following number <math>\frac{Y^{\text{tot}}}{Y^{\text{2 fisson}}}=3.4</math>. If we want to get the ratio of pure yield of correlated neutrons <math>Y^{\text{1n/fission}}</math> over the yield of uncorrelated neutrons <math>Y^{\text{2n/fisson}}</math> we should take the difference <math>Y^{\text{1n/fission}}=Y^{\text{tot}}-Y^{\text{2n/fisson}}</math> and then take the ratio <math>\frac{Y^{\text{1n/fission}}}{Y^{\text{2n/fisson}}} = \frac{(2.2E-5)-(6.49E-6)}{6.49E-6}=2.4</math>
-Poisson distribution <math>P(n)=\frac{n^n  e^{-n}}{}</math> of the number of fission neutrons per fission event if the average number of neutrons emitted in fission event is 2.5 neutrons.
+Poisson distribution <math>P(n)=\frac{\={n}^n  e^{-n}}{}</math> of the number of fission neutrons per fission event if the average number of neutrons emitted in fission event is 2.5 neutrons.
 [[File:poisson_2_5n_ave.png | 500px]]

@@ Line 327: / Line 327: @@
 The ratio of the normalized integrated yields of correlated + uncorrelated neutrons per pulse <math>Y^{\text{tot}}=2.2E-5</math>  and calculated yield of uncorrelated neutrons per pulse <math>Y^{\text{2n/fisson}}=6.49E-6</math> gives the following number <math>\frac{Y^{\text{tot}}}{Y^{\text{2 fisson}}}=3.4</math>. If we want to get the ratio of pure yield of correlated neutrons <math>Y^{\text{1n/fission}}</math> over the yield of uncorrelated neutrons <math>Y^{\text{2n/fisson}}</math> we should take the difference <math>Y^{\text{1n/fission}}=Y^{\text{tot}}-Y^{\text{2n/fisson}}</math> and then take the ratio <math>\frac{Y^{\text{1n/fission}}}{Y^{\text{2n/fisson}}} = \frac{(2.2E-5)-(6.49E-6)}{6.49E-6}=2.4</math>
-Poisson distribution <math>P(n)=\frac{\={n}^n \cdot e^{-n}}{}</math> of the number of fission neutrons per fission event if the average number of neutrons emitted in fission event is 2.5 neutrons.
+Poisson distribution <math>P(n)=\frac{n^n  e^{-n}}{}</math> of the number of fission neutrons per fission event if the average number of neutrons emitted in fission event is 2.5 neutrons.
 [[File:poisson_2_5n_ave.png | 500px]]

← Older revision		Revision as of 15:27, 22 September 2014
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	The ratio of the normalized integrated yields of correlated + uncorrelated neutrons per pulse <math>Y^{\text{tot}}=2.2E-5</math> and calculated yield of uncorrelated neutrons per pulse <math>Y^{\text{2n/fisson}}=6.49E-6</math> gives the following number <math>\frac{Y^{\text{tot}}}{Y^{\text{2 fisson}}}=3.4</math>. If we want to get the ratio of pure yield of correlated neutrons <math>Y^{\text{1n/fission}}</math> over the yield of uncorrelated neutrons <math>Y^{\text{2n/fisson}}</math> we should take the difference <math>Y^{\text{1n/fission}}=Y^{\text{tot}}-Y^{\text{2n/fisson}}</math> and then take the ratio <math>\frac{Y^{\text{1n/fission}}}{Y^{\text{2n/fisson}}} = \frac{(2.2E-5)-(6.49E-6)}{6.49E-6}=2.4</math>		The ratio of the normalized integrated yields of correlated + uncorrelated neutrons per pulse <math>Y^{\text{tot}}=2.2E-5</math> and calculated yield of uncorrelated neutrons per pulse <math>Y^{\text{2n/fisson}}=6.49E-6</math> gives the following number <math>\frac{Y^{\text{tot}}}{Y^{\text{2 fisson}}}=3.4</math>. If we want to get the ratio of pure yield of correlated neutrons <math>Y^{\text{1n/fission}}</math> over the yield of uncorrelated neutrons <math>Y^{\text{2n/fisson}}</math> we should take the difference <math>Y^{\text{1n/fission}}=Y^{\text{tot}}-Y^{\text{2n/fisson}}</math> and then take the ratio <math>\frac{Y^{\text{1n/fission}}}{Y^{\text{2n/fisson}}} = \frac{(2.2E-5)-(6.49E-6)}{6.49E-6}=2.4</math>

		+	Poisson distribution of the number of fission neutrons per fission event if the average number of neutrons emitted in fission event is 2.5 neutrons.
		+
		+	[[File:poisson_2_5n_ave.png \| 500px]]

	'''Bin-by-bin subtraction'''		'''Bin-by-bin subtraction'''

← Older revision		Revision as of 14:12, 15 September 2014
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	==The ratio of the integrated yields==		==The ratio of the integrated yields==

−	The ratio of the normalized integrated yields of correlated + uncorrelated neutrons <math>Y^{\text{tot}}=2.2E-5</math> ~~per pulse~~ and calculated yield of uncorrelated neutrons <math>Y^{\text{2n/fisson}}=6.49E-6</math> ~~per pulse~~ gives the following number <math>\frac{Y^{\text{tot}}}{Y^{\text{2 fisson}}}=3.4</math>. If we want to get the ratio of pure yield of correlated neutrons <math>Y^{\text{1n/fission}}</math> over the yield of uncorrelated neutrons <math>Y^{\text{2n/fisson}}</math> we should take the difference <math>Y^{\text{1n/fission}}=Y^{\text{tot}}-Y^{\text{2n/fisson}}</math> and then take the ratio <math>\frac{Y^{\text{1n/fission}}}{Y^{\text{2n/fisson}}} = \frac{(2.2E-5)-(6.49E-6)}{6.49E-6}=2.4</math>	+	The ratio of the normalized integrated yields of correlated + uncorrelated neutrons per pulse <math>Y^{\text{tot}}=2.2E-5</math> and calculated yield of uncorrelated neutrons per pulse <math>Y^{\text{2n/fisson}}=6.49E-6</math> gives the following number <math>\frac{Y^{\text{tot}}}{Y^{\text{2 fisson}}}=3.4</math>. If we want to get the ratio of pure yield of correlated neutrons <math>Y^{\text{1n/fission}}</math> over the yield of uncorrelated neutrons <math>Y^{\text{2n/fisson}}</math> we should take the difference <math>Y^{\text{1n/fission}}=Y^{\text{tot}}-Y^{\text{2n/fisson}}</math> and then take the ratio <math>\frac{Y^{\text{1n/fission}}}{Y^{\text{2n/fisson}}} = \frac{(2.2E-5)-(6.49E-6)}{6.49E-6}=2.4</math>