Pair Production Rate Calculation - Revision history

Shaproma at 19:04, 24 May 2012

2012-05-24T19:04:00Z

2011-03-01T06:26:17Z

Conversion factor from Ti to Al

2011-03-01T06:25:33Z

Conversion factor from Ti to Al

2011-02-02T21:14:41Z

1 m of air vs. l = 3.0\ \mu m of Al converter

2011-02-02T21:13:54Z

Pair production rate

2011-02-02T04:55:13Z

Conversion factor from Ti to Al

2011-02-02T04:53:24Z

1/2 mil of Al

2011-02-02T04:51:13Z

1/2 mil of Al

2011-02-02T04:49:46Z

1/2 mil of Ti

2011-02-02T04:49:26Z

1/2 mil of Ti

← Older revision		Revision as of 19:04, 24 May 2012
Line 1:		Line 1:
−	[~~http~~://wiki.iac.isu.edu/index.php/~~PhotoFission_with_Polarized_Photons_from_HRRL~~ Go Back]	+	[https://wiki.iac.isu.edu/index.php/Roman_calculation Go Back]

	==LINAC parameters used in calculations==		==LINAC parameters used in calculations==

@@ Line 47: / Line 47: @@
 All my following calculation for pair production rate are based on (1/2) mil of Ti radiator. If we want to recalculate for (1/2) mil of Al converter we need to use the conversion factor:
-  <math>\frac{0.45 (1/2 mil of Al)}{1.12 (1/2 mil of Ti)} = 0.40 </math>
+  <math>\frac{0.45\ (1/2\ mil\ of\ Al)}{1.12\ (1/2\ mil\ of\ Ti)} = 0.40 </math>
 ===Appendix===

@@ Line 47: / Line 47: @@
 All my following calculation for pair production rate are based on (1/2) mil of Ti radiator. If we want to recalculate for (1/2) mil of Al converter we need to use the conversion factor:
-  <math>\frac{0.45}{1.12} = 0.40 </math>
+  <math>\frac{0.45 (1/2 mil of Al)}{1.12 (1/2 mil of Ti)} = 0.40 </math>
 ===Appendix===

@@ Line 80: / Line 80: @@
   <math>\frac {1.12 \cdot 10^{8}\ \frac{\gamma}{sec} \times \sigma_{\mbox{pairs}} \times N_{\mbox{Nitrogen}}} {f} = 300\ \frac{\mbox{pairs}}{\mbox{pulse}} </math>
-===1 m of air vs. <math>l = 3.0\ \mu m</math> of Al converter===
+===1 m of air vs. 3.0 um of Al converter===
   <math>\frac{300\ \frac{\mbox{pairs}}{\mbox{pulse}}} {3.38\ \frac{\mbox{pairs}}{\mbox{pulse}}} = 88.8\ \mbox{times!}</math>

← Older revision		Revision as of 21:13, 2 February 2011
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	<math>\frac {1.12 \cdot 10^{8}\ \frac{\gamma}{sec} \times \sigma_{\mbox{pairs}} \times N_{\mbox{Nitrogen}}} {f} = 300\ \frac{\mbox{pairs}}{\mbox{pulse}} </math>		<math>\frac {1.12 \cdot 10^{8}\ \frac{\gamma}{sec} \times \sigma_{\mbox{pairs}} \times N_{\mbox{Nitrogen}}} {f} = 300\ \frac{\mbox{pairs}}{\mbox{pulse}} </math>
		+
		+	===1 m of air vs. <math>l = 3.0\ \mu m</math> of Al converter===
		+
		+	<math>\frac{300\ \frac{\mbox{pairs}}{\mbox{pulse}}} {3.38\ \frac{\mbox{pairs}}{\mbox{pulse}}} = 88.8\ \mbox{times!}</math>

	===Appendix===		===Appendix===

@@ Line 41: / Line 41: @@
 '''Alex factor is 6.85 %'''
-  <math>xxx \cdot 10^{9} \frac{\gamma}{sec} \cdot 6.85\ % = xxx \cdot 10^{8} \frac{\gamma}{sec}</math><br><br>
+  <math>0.66 \cdot 10^{9} \frac{\gamma}{sec} \cdot 6.85\ % = 0.45 \cdot 10^{8} \frac{\gamma}{sec}</math><br><br>
 ===Conversion factor from Ti to Al===

@@ Line 37: / Line 37: @@
   <math>\frac{12.5\ \mu m}{8.89\ cm} = 1.41 \cdot 10^{-4}\ r.l.</math><br>
-  <math>0.47 \cdot 10^{13}\ \frac{e^-}{sec} \times 0.1\ \frac{\gamma 's}{(e^- \cdot MeV \cdot r.l.)} \times 1.41 \cdot 10^{-4}\ r.l. \times 10\ MeV =xxx \cdot 10^{9} \frac{\gamma}{sec}</math><br><br>
+  <math>0.47 \cdot 10^{13}\ \frac{e^-}{sec} \times 0.1\ \frac{\gamma 's}{(e^- \cdot MeV \cdot r.l.)} \times 1.41 \cdot 10^{-4}\ r.l. \times 10\ MeV =0.66 \cdot 10^{9} \frac{\gamma}{sec}</math><br><br>
 '''Alex factor is 6.85 %'''

@@ Line 15: / Line 15: @@
 ===1/2 mil of Ti===
-#<math>\sigma_{\mbox{brems}}=0.1\ \mbox{photons/electrons/MeV/r.l}</math>
+#<math>\sigma_{brems}=0.1\ \mbox{photons/electrons/MeV/r.l}</math>
 #<math>\mbox{r.l.(Ti)} = 3.59\ \mbox{cm}</math>
 #<math>\mbox{radiator}\ \mbox{thickness} = 12.5\ \mu m</math>