Notes from July 2nd, 2008 Meeting - Revision history

Oborn at 06:26, 5 February 2009

2009-02-05T06:26:57Z

Oborn at 14:15, 3 July 2008

2008-07-03T14:15:35Z

Oborn at 14:11, 3 July 2008

2008-07-03T14:11:47Z

Oborn at 14:00, 3 July 2008

2008-07-03T14:00:27Z

Oborn at 13:53, 3 July 2008

2008-07-03T13:53:46Z

Oborn at 13:40, 3 July 2008

2008-07-03T13:40:54Z

Oborn at 13:28, 3 July 2008

2008-07-03T13:28:08Z

Oborn at 12:17, 3 July 2008

2008-07-03T12:17:08Z

New page

Numbers for rate of Brems intensity spectrum:

<math>\frac{e^{-}}{sec}</math> = <math>30 \cdot 10^{-3} \frac{Coulomb}{sec} \times \frac{50 \cdot 10^{-9} sec}{10^{-3} sec} \times \frac{1 \cdot e^{-}}{1.6 \cdot 10^{-19}Coulomb} => 9.4 \cdot 10^{12} \frac{e^{-}}{sec}
</math>

<math>10^{-3} \frac{\frac{\gamma 's}{MeV}}{\frac{e^{-}}{radiation lengths}} \times 2 \cdot 10^{-4} radiation lengths \times 15 MeV \times 9.4 \cdot 10^{12} \frac{e^{-}}{sec}=2.8 \cdot 10^{7} \frac{\gamma}{sec}</math>

← Older revision		Revision as of 06:26, 5 February 2009
Line 33:		Line 33:

	'''Therefore, this experiment is do able.'''		'''Therefore, this experiment is do able.'''
		+
		+	[http://wiki.iac.isu.edu/index.php/PhotoFission_with_Polarized_Photons_from_HRRL Go Back]

← Older revision		Revision as of 14:15, 3 July 2008
Line 31:		Line 31:
	::::6 hours for 4%		::::6 hours for 4%

−	Therefore, this experiment is do able.	+
		+	'''Therefore, this experiment is do able.'''

@@ Line 24: / Line 24: @@
 fractional solid angle = <math>\frac{\pi * (1 cm)^{2}}{4 \pi (100cm^{2}} = \frac{1}{4} \times 10^{-4}</math> <= geometrical acceptance
-\degree efficient of n \degree detection
+° efficient of n° detection
 <math> 10^{4} \frac{photodisintegrations}{sec} \times \frac{1}{4} \cdot 10^{-4} \times 10^{-1} = .025 \frac{events}{sec}</math>
 time for <math>10^{4}</math> events = 100 hours for 1%

@@ Line 27: / Line 27: @@
 <math> 10^{4} \frac{photodisintegrations}{sec} \times \frac{1}{4} \cdot 10^{-4} \times 10^{-1} = .025 \frac{events}{sec}</math>
-::::::::::::::::::<math>\uparrow</math><math>\uparrow</math>
+::::::::::::::::::<math>\uparrow</math>   <math>\uparrow</math>
-:::::::::::::::::geometry[[User:Daq|Daq]] 07:53, 3 July 2008 (MDT)efficiency
+:::::::::::::::::geometry   efficiency

@@ Line 27: / Line 27: @@
 <math> 10^{4} \frac{photodisintegrations}{sec} \times \frac{1}{4} \cdot 10^{-4} \times 10^{-1} = .025 \frac{events}{sec}</math>
-                                  ^           ^
+::::::::::::::::::<math>\uparrow</math><math>\uparrow</math>
-time for 10,sup>4</sup> events = 100 hours for 1%
-hours for 2%
+time for <math>10^{4}</math> events = 100 hours for 1%
-hours for 4%
+::::24 hours for 2%
 Therefore, this experiment is do able.

← Older revision		Revision as of 13:40, 3 July 2008
Line 13:		Line 13:

	target thickness in <math>\frac{Dnuclei}{cm^{2}} \times \sigma in cm^{2}</math>		target thickness in <math>\frac{Dnuclei}{cm^{2}} \times \sigma in cm^{2}</math>
		+
		+	==Worst Case Isotropic Neutrons==
		+
		+	Let's say we have:
		+
		+	radius detector = 1 cm
		+
		+	1 meter away
		+
		+	fractional solid angle = <math>\frac{\pi * (1 cm)^{2}}{4 \pi (100cm^{2}} = \frac{1}{4} \times 10^{-4}</math> <= geometrical acceptance
		+
		+	10 \degree efficient of n \degree detection
		+	<math> 10^{4} \frac{photodisintegrations}{sec} \times \frac{1}{4} \cdot 10^{-4} \times 10^{-1} = .025 \frac{events}{sec}</math>
		+
		+	^ ^
		+	\| \|
		+	geometry efficiency
		+
		+
		+	time for 10,sup>4</sup> events = 100 hours for 1%
		+	24 hours for 2%
		+	6 hours for 4%
		+
		+	Therefore, this experiment is do able.

← Older revision		Revision as of 13:28, 3 July 2008
Line 5:		Line 5:

	<math>10^{-3} \frac{\frac{\gamma 's}{MeV}}{\frac{e^{-}}{radiation lengths}} \times 2 \cdot 10^{-4} radiation lengths \times 15 MeV \times 9.4 \cdot 10^{12} \frac{e^{-}}{sec}=2.8 \cdot 10^{7} \frac{\gamma}{sec}</math>		<math>10^{-3} \frac{\frac{\gamma 's}{MeV}}{\frac{e^{-}}{radiation lengths}} \times 2 \cdot 10^{-4} radiation lengths \times 15 MeV \times 9.4 \cdot 10^{12} \frac{e^{-}}{sec}=2.8 \cdot 10^{7} \frac{\gamma}{sec}</math>
		+
		+	==Number of ɣ + d -> n + p events/sec==
		+
		+	<math>2.8 \cdot 10^{7} \frac{\gamma}{sec} \times 4 \cdot 10^{-4} = 10^{4}</math>
		+
		+	==Probability of Photodisintegration Event==
		+
		+	target thickness in <math>\frac{Dnuclei}{cm^{2}} \times \sigma in cm^{2}</math>