Ni-08-22-13 - Revision history

Foretony: /* Extracting Photon flux using Nickel Foil */

2014-11-16T21:59:57Z

Extracting Photon flux using Nickel Foil

2014-11-16T21:54:13Z

Extracting Photon flux using Nickel Foil

2014-11-16T21:53:06Z

Extracting Photon flux using Nickel Foil

2014-11-16T21:47:15Z

Extracting Photon flux using Nickel Foil

2014-11-16T21:40:25Z

Extracting Photon flux using Nickel Foil

2014-11-16T21:35:27Z

Extracting Photon flux using Nickel Foil

2014-11-16T21:32:46Z

Extracting Photon flux using Nickel Foil

2014-11-16T21:32:36Z

Extracting Photon flux using Nickel Foil

2014-11-16T21:28:55Z

Extracting Photon flux using Nickel Foil

2014-11-16T21:27:17Z

@@ Line 55: / Line 55: @@
 =<math>S_n = B({58 \atop 28} Ni_{76})-B({{56} \atop 28} X_{74})= 506,453.842 - 483,987.827 = 22,466.015 keV = 22.466015 MeV </math>
+Unfortunately the electron beam energy may have been 22 MeV thereby forbidding two neutron knockout.
 [[PAA_8-22-13#Nickel_normalization_foils]]
 [[A_W_thesis]]

← Older revision		Revision as of 21:54, 16 November 2014
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−	;<math>{58 \atop 28 }Ni_{76}(\gamma,n){57 \atop 28 }Ni_{75}</math> 35.6 hour half life with high intensity lines at 511 (87%) and 1377.63 (81.7%)	+	:<math>{58 \atop 28 }Ni_{76}(\gamma,n){57 \atop 28 }Ni_{75}</math>
		+	Ni-57 has a 35.6 hour half life with high intensity lines at 511 (87%) and 1377.63 (81.7%)

−	;<math>{58 \atop 28 }Ni_{76}(\gamma,2n){56 \atop 28 }Ni_{74}</math> 6 day half life with intensity lines at 158 (87%) and 811 (81.7%)	+	:<math>{58 \atop 28 }Ni_{76}(\gamma,2n){56 \atop 28 }Ni_{74}</math>
		+	Ni-56 has a day half life with intensity lines at 158 (87%) and 811 (81.7%)

← Older revision		Revision as of 21:53, 16 November 2014
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−	;<math>{58 \atop 28 }Ni_{76}(\gamma,n){57 \atop 28 }Ni_{75}</math>	+	;<math>{58 \atop 28 }Ni_{76}(\gamma,n){57 \atop 28 }Ni_{75}</math> 35.6 hour half life with high intensity lines at 511 (87%) and 1377.63 (81.7%)

−	;<math>{58 \atop 28 }Ni_{76}(\gamma,2n){56 \atop 28 }Ni_{74}</math>	+	;<math>{58 \atop 28 }Ni_{76}(\gamma,2n){56 \atop 28 }Ni_{74}</math> 6 day half life with intensity lines at 158 (87%) and 811 (81.7%)

← Older revision		Revision as of 21:47, 16 November 2014
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	Neutron Separation Energy=<math>S_n = B({A \atop Z} X_{N})-B({{A-1} \atop Z} X_{N-1})</math>		Neutron Separation Energy=<math>S_n = B({A \atop Z} X_{N})-B({{A-1} \atop Z} X_{N-1})</math>
		+
		+	<math>B({58 \atop28} Ni_{76}) = 506,453.842 keV</math>
		+	<math>B({57 \atop28} Ni_{75}) = 494,234.980 keV</math>
		+	<math>B({56 \atop28} Ni_{74}) = 483,987.827 keV</math>
		+
		+
		+	Neutron Separation Energy for <math>{58 \atop 28 }Ni_{76}(\gamma,n){57 \atop 28 }Ni_{75}</math>
		+
		+	=<math>S_n = B({58 \atop 28} Ni_{76})-B({{57} \atop 28} X_{75})= 506,453.842 - 506,453.842 = 12218.862 keV = 12.218862 MeV </math>
		+
		+
		+	2 Neutron Separation Energy for <math>{58 \atop 28 }Ni_{76}(\gamma,2n){56 \atop 28 }Ni_{74}</math>
		+
		+	=<math>S_n = B({58 \atop 28} Ni_{76})-B({{56} \atop 28} X_{74})= 506,453.842 - 483,987.827 = 22,466.015 keV = 22.466015 MeV </math>

← Older revision		Revision as of 21:40, 16 November 2014
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	Since the two neutron knockout reaction requires a higher photon energy one may be able to estimate the bremmsstrahlung distribution by requiring that the ratio of the integral for photon energies allowing single neutron knockout to the integral for two neutron knockout match the observed counting rate that has included cross -section		Since the two neutron knockout reaction requires a higher photon energy one may be able to estimate the bremmsstrahlung distribution by requiring that the ratio of the integral for photon energies allowing single neutron knockout to the integral for two neutron knockout match the observed counting rate that has included cross -section
		+
		+	Energy needed to liberate a neutron from the Nucleus
		+
		+	Neutron Separation Energy=<math>S_n = B({A \atop Z} X_{N})-B({{A-1} \atop Z} X_{N-1})</math>
		+

← Older revision	Revision as of 21:35, 16 November 2014
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−	+	Since the two neutron knockout reaction requires a higher photon energy one may be able to estimate the bremmsstrahlung distribution by requiring that the ratio of the integral for photon energies allowing single neutron knockout to the integral for two neutron knockout match the observed counting rate that has included cross -section

← Older revision		Revision as of 21:32, 16 November 2014
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−	;<math>{58 \atop 28 }Ni_{76}(\~~gamm~~,n){57 \atop 28 }Ni_{75}</math>	+	;<math>{58 \atop 28 }Ni_{76}(\gamma,n){57 \atop 28 }Ni_{75}</math>

−	;<math>{58 \atop 28 }Ni_{76}(\~~gamm~~,2n){56 \atop 28 }Ni_{74}</math>	+	;<math>{58 \atop 28 }Ni_{76}(\gamma,2n){56 \atop 28 }Ni_{74}</math>

@@ Line 25: / Line 25: @@
 == Extracting  Photon flux using Nickel Foil==
-;example:
+The two reactions below can be used to extrapolate the photon flux
-;<math>{58 \atop 82 }Ni_{126}</math>
-;example:
-;<math>{58 \atop\; }Ni ={208 \atop 82 }Pb_{126}</math>
+;<math>{58 \atop 28 }Ni_{76}(\gamm,n){57 \atop 28 }Ni_{75}</math>

← Older revision		Revision as of 21:28, 16 November 2014
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	== Extracting Photon flux using Nickel Foil==		== Extracting Photon flux using Nickel Foil==
		+
		+	;example:
		+	;<math>{58 \atop 82 }Ni_{126}</math>
		+	;example:
		+	;<math>{58 \atop\; }Ni ={208 \atop 82 }Pb_{126}</math>
		+
		+

← Older revision		Revision as of 21:27, 16 November 2014
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	Ni-58->Co-56 :847, 1238, 511, 2599, 1771, 1038, half life = 77 days		Ni-58->Co-56 :847, 1238, 511, 2599, 1771, 1038, half life = 77 days
		+
		+
		+	== Extracting Photon flux using Nickel Foil==