Lab 9 RS - Revision history

Shaproma: /* Questions */

2011-03-01T20:15:23Z

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2011-02-27T04:47:51Z

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2011-02-27T04:47:06Z

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Shaproma at 20:24, 25 February 2011

2011-02-25T20:24:56Z

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2011-02-25T20:22:37Z

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2011-02-25T20:20:40Z

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2011-02-25T20:07:16Z

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2011-02-25T20:06:41Z

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2011-02-25T20:03:42Z

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Shaproma: /* Questions */

2011-02-25T20:02:40Z

Questions

← Older revision		Revision as of 20:15, 1 March 2011
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−	1) Let see what happens for the ~~first~~ clipping circuit:	+	1) Let see what happens for the second clipping circuit:

	[[File:cuircuit_2.png \| 300 px]]		[[File:cuircuit_2.png \| 300 px]]

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 [[File:TF_EIM_Lab9.png | 300 px]]
-a) When the input voltage is about 0.1 Volts the diode is below the reverse and forward turn on voltage points. The diode is working as a good isolator and there are no any signal at output because all voltage drop is on the diode.
+a) When the input voltage is about 0.1 Volts the diode is below the reverse and forward turn on voltage points. The diode is working as a good insulator and there are no any signal at output because all voltage drop is on the diode.
 b) When the input voltage is about 1 Volts we are above the forward turn on voltage. So the diode becomes to conduct in forward direction when the voltage drop on diode exceed 0.8 Volts. All input signal that above 0.8 Volts is going through the diode. On the other side we are still bellow 4.7 Volts on the negative side of input signal. So the diode cut all negative signal off.

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 [[File:L8 diod current m1.png | 400 px]]
-The critical parameters here is '''reverse turn on voltage''' and '''forward turn on voltage'''. Reverse turn on voltage for this type of diode equal about 4.7 Volts and forward turn on voltage about 0.9 Volts. When the voltage drop on diode is beyond this two points the diode becomes good conductor with internal resistance about 4-6 <math>\Omega</math>. On the other side when voltage below 0.8 Volts in forward direction or below 4.7 Volts in reverse direction the diode becomes good isolator with current less than 1 mA through the diode. All explanation of the clipping current can be done by using the voltage current diagram above and by using reverse and forward turn on voltage points.
+The critical parameters here is '''reverse turn on voltage''' and '''forward turn on voltage'''. Reverse turn on voltage for this type of diode equal about 4.7 Volts and forward turn on voltage about 0.9 Volts. When the voltage drop on diode is beyond this two points the diode becomes good conductor with internal resistance about 4-6 <math>\Omega</math>. On the other side when voltage below 0.8 Volts in forward direction or below 4.7 Volts in reverse direction the diode becomes good insulator with current less than 1 mA through the diode. All explanation of the clipping current can be done by using the voltage current diagram above and by using reverse and forward turn on voltage points.
 ) Let see what happens for the first clipping circuit:

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 All explanation is based on current voltage diagram for diode used in this laboratory work. I used the ZENER silicon diode type # 1N5230B-T. The diode current vs. diode voltage plot I measured in previous lab (see my pictures below):
-[[File:L8 diod current m1.png | 500 px]]
+[[File:L8 diod current m1.png | 400 px]]
 The critical parameters here is '''reverse turn on voltage''' and '''forward turn on voltage'''. Reverse turn on voltage for this type of diode equal about 4.7 Volts and forward turn on voltage about 0.9 Volts. When the voltage drop on diode is beyond this two points the diode becomes good conductor with internal resistance about 4-6 <math>\Omega</math>. On the other side when voltage below 0.8 Volts in forward direction or below 4.7 Volts in reverse direction the diode becomes good isolator with current less than 1 mA through the diode. All explanation of the clipping current can be done by using the voltage current diagram above and by using reverse and forward turn on voltage points.

← Older revision		Revision as of 20:22, 25 February 2011
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	[[File:cuircuit_2.png \| 300 px]]		[[File:cuircuit_2.png \| 300 px]]

−	Here we shut off the output resistor by diode. So when the output signal through the diode exceeds 0.8 Volts in forward direction and 4.7 Volts in reverse direction the diode becomes to conduct and all output signal is going through the diode to ground. Also note that diode here is actually in ~~reverse~~ direction with respect to ground. So the diode is going to cut off all positive signal that exceed 4.7 Volts and cut off all negative signal that exceed 0.8 Volts.	+	Here we shut off the output resistor by diode. So when the output signal through the diode exceeds 0.8 Volts in forward direction and 4.7 Volts in reverse direction the diode becomes to conduct and all output signal is going through the diode to ground. Also note that diode here is actually in forward direction with respect to ground. So the diode is going to cut off all positive signal that exceed 4.7 Volts and cut off all negative signal that exceed 0.8 Volts.

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 a) When the input voltage is about 0.1 Volts the diode is below the reverse and forward turn on voltage points. The diode is working as a good isolator and there are no any signal at output because all voltage drop is on the diode.
-b) When the input voltage is about 1 Volts we are above the forward turn on voltage. So the diode becomes to conduct in forward direction when the voltage drop on diode exceed 0.8 Volts. On the other side we are still bellow 4.7 Volts on the negative side of input signal. So the diode cut all negative signal off.
+b) When the input voltage is about 1 Volts we are above the forward turn on voltage. So the diode becomes to conduct in forward direction when the voltage drop on diode exceed 0.8 Volts. All input signal that above 0.8 Volts is going through the diode. On the other side we are still bellow 4.7 Volts on the negative side of input signal. So the diode cut all negative signal off.
-c) When the input voltage is about 10 Volts  we are above the forward turn on voltage and we are above the reverse turn on voltage as well. So diode becomes to conduct as soon as the voltage exceed 0.8 Volts in forward direction and as soon as the voltage exceed 4.7 Volts in reverse direction
+c) When the input voltage is about 10 Volts  we are above the forward turn on voltage and we are above the reverse turn on voltage as well. So diode becomes to conduct and all input signal that exceed 0.8 Volts in forward direction and that exceed 4.7 Volts in reverse direction is going through the diode so we can see the output signal.
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 [[File:cuircuit_2.png | 300 px]]

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 When the input voltage is about 0.1 Volts the diode is below the reverse and forward turn on voltage points. The diode is working as a good isolator and there are no any signal at output because all voltage drop is on the diode.
-When the input voltage is about 1 Volts we are above the forward turn on voltage. So the diode becomes conduct in forward direction when the voltage drop on diode exceed 0.9 Volts. On the other side we are still bellow 4.7 Volts on the negative side of input signal. So the diode cut all negative signal off.
+When the input voltage is about 1 Volts we are above the forward turn on voltage. So the diode becomes to conduct in forward direction when the voltage drop on diode exceed 0.9 Volts. On the other side we are still bellow 4.7 Volts on the negative side of input signal. So the diode cut all negative signal off.
-When the input voltage is about 10 Volts  we are above the forward turn on voltage and we are above the reverse turn on voltage as well. So diode becomes to conduct as soon as the voltage exceed 0.9 Volts in forward direction and as soon as the voltage exceed the 4.7 Volts in reverse direction
+When the input voltage is about 10 Volts  we are above the forward turn on voltage and we are above the reverse turn on voltage as well. So diode becomes to conduct as soon as the voltage exceed 0.9 Volts in forward direction and as soon as the voltage exceed 4.7 Volts in reverse direction
 [[Forest_Electronic_Instrumentation_and_Measurement]]
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