Lab 23 RS - Revision history

Shaproma: /* Input Impedance */

2011-04-27T14:16:24Z

Input Impedance

2011-04-26T13:55:32Z

Output voltage RMS noise \Delta V_{out}^{RMS}

2011-04-26T13:55:01Z

Output voltage RMS noise \Delta V_{out}^{RMS}

2011-04-26T13:54:01Z

Power Supply Rejection Ratio

2011-04-26T13:53:06Z

Capacitor in parallel with R_2

2011-04-26T13:52:37Z

Capacitor in parallel with R_2

2011-04-26T13:52:09Z

Capacitor in parallel with R_2

2011-04-26T03:58:45Z

Output voltage RMS noise \Delta V_{out}^{RMS}

2011-04-26T03:57:24Z

Power Supply Rejection Ratio

2011-04-26T03:56:06Z

Power Supply Rejection Ratio

@@ Line 73: / Line 73: @@
 #Measure <math>R_{in}</math> for the 10 fold and 100 fold amplifier  at ~100 Hz and 10 kHz frequency.
+I am going to measure the input and output impedance of my total amplifier (because I think it is what was asked) using the following equivalent circuit:
 [[File:Draw01.png | 400px]]

← Older revision		Revision as of 13:55, 26 April 2011
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	<math>\mbox{Noise}_{\mbox{RMS}} = \frac{(6\pm0.5)\ mV}{2\ \sqrt{2}} = (2.12\pm0.18)\ mV</math>		<math>\mbox{Noise}_{\mbox{RMS}} = \frac{(6\pm0.5)\ mV}{2\ \sqrt{2}} = (2.12\pm0.18)\ mV</math>
−

	[https://wiki.iac.isu.edu/index.php/Electronics_RS Go Back to All Lab Reports] [[Forest_Electronic_Instrumentation_and_Measurement]]		[https://wiki.iac.isu.edu/index.php/Electronics_RS Go Back to All Lab Reports] [[Forest_Electronic_Instrumentation_and_Measurement]]

← Older revision		Revision as of 13:55, 26 April 2011
Line 404:		Line 404:

	<math>\mbox{Noise}_{\mbox{RMS}} = \frac{(6\pm0.5)\ mV}{2\ \sqrt{2}} = (2.12\pm0.18)\ mV</math>		<math>\mbox{Noise}_{\mbox{RMS}} = \frac{(6\pm0.5)\ mV}{2\ \sqrt{2}} = (2.12\pm0.18)\ mV</math>
−
−
−
−


	[https://wiki.iac.isu.edu/index.php/Electronics_RS Go Back to All Lab Reports] [[Forest_Electronic_Instrumentation_and_Measurement]]		[https://wiki.iac.isu.edu/index.php/Electronics_RS Go Back to All Lab Reports] [[Forest_Electronic_Instrumentation_and_Measurement]]

← Older revision		Revision as of 13:54, 26 April 2011
Line 359:		Line 359:
	Below is my plot of <math>V_{out}</math> as function <math>V_{cc}</math>:		Below is my plot of <math>V_{out}</math> as function <math>V_{cc}</math>:

−	[[File:Plot PSRR 02.png \| ~~850~~ px]]	+	[[File:Plot PSRR 02.png \| 800 px]]

@@ Line 276: / Line 276: @@
 ) Add the capacitor in parallel to <math>R_2</math> so you have the circuit shown above.
 ) Use a pulse generator to input a sinusoidal voltage <math>V_{in}</math>
 ) Measure the Gain as a function of the <math>V_{in}</math> frequency and plot it.
 Below my measured voltages and gain calculation.
-[[File:Table gain c2 01.png | 950 px]]
+[[File:Table gain c2 01.png | 1000 px]]

← Older revision		Revision as of 13:52, 26 April 2011
Line 283:		Line 283:
	Below my measured voltages and gain calculation.		Below my measured voltages and gain calculation.

−	[[File:Table gain c2 01.png \| ~~1000~~ px]]	+	[[File:Table gain c2 01.png \| 950 px]]

← Older revision		Revision as of 13:52, 26 April 2011
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	4) Measure the Gain as a function of the <math>V_{in}</math> frequency and plot it.		4) Measure the Gain as a function of the <math>V_{in}</math> frequency and plot it.
−

	Below my measured voltages and gain calculation.		Below my measured voltages and gain calculation.

@@ Line 402: / Line 402: @@
 My measured peak-to-peak noise <math>\Delta V_{out}^{RMS}</math> with <math>V_{in}</math> grounded is:
-  <math>\mbox{noise}_{\mbox{peak-to-peak}} = (6\pm0.5)\ mV</math>
+  <math>\mbox{Noise}_{\mbox{peak-to-peak}} = (6\pm0.5)\ mV</math>
 So my RMS noise is:
-  <math>\mbox{noise}_{\mbox{RMS}} = \frac{(6\pm0.5)\ mV}{2\ \sqrt{2}} = (2.12\pm0.18)\ mV</math>
+  <math>\mbox{Noise}_{\mbox{RMS}} = \frac{(6\pm0.5)\ mV}{2\ \sqrt{2}} = (2.12\pm0.18)\ mV</math>

@@ Line 390: / Line 390: @@
 and substituting the corresponding coefficients and evaluating the PSRR at point <math>V_{cc} = 13\ V</math> (the data sheet values of PSRR is given at <math>V_{cc} = \pm 15\ V</math>, but I can not really evaluate my PSRR at this point because my fitting procedure and my measured values are out of this point):
-  <math>PSRR = \frac{1}{(199.6\pm0.1)/(10.06\pm0.01)}((0.5173\pm 0.4342) + 2\ (0.02024\pm 0.05517)\ 13 + 3\ (-0.001992\pm1.002202)\ 13^2)\ \frac{mV}{V}</math>
+  <math>PSRR = \frac{1}{(199.6\pm0.1)/(10.06\pm0.01)}((0.5173\pm 0.4342) + 2 (0.02024\pm 0.05517)\cdot 13 + 3 (-0.001992\pm1.002202)\cdot 13^2)\ \frac{mV}{V}</math>
 By doing math and handling the error propagation we get finally:

@@ Line 371: / Line 371: @@
 where
-  <math>V_{out} \mbox{given}\ \mbox{in}\ \mbox{mV}</math>
+  <math>V_{out}\ \mbox{given}\ \mbox{in}\ \mbox{mV}</math>
-  <math>V_{cc} \mbox{given}\ \mbox{in}\ \mbox{V}</math>
+  <math>V_{cc}\ \mbox{given}\ \mbox{in}\ \mbox{V}</math>
   <math>p_0 = (-5.711\pm 1.063)</math>
   <math>p_1 = (0.5173\pm 0.4342)</math>
@@ Line 381: / Line 381: @@
 The power supply rejection ratio (PSRR) can be calculated by
-  <math>PSRR = \frac{1}{gain}\frac{\Delta V_{out}}{\Delta V_{cc}} = \frac{1}{R_2/R_1}\frac{\partial V_{out}}{\partial V_{cc}} </math>
+  <math>PSRR = \frac{1}{\mbox{Gain}}\frac{\Delta V_{out}}{\Delta V_{cc}} = \frac{1}{R_2/R_1}\frac{\partial V_{out}}{\partial V_{cc}} </math>