GEANT Moller Simulations Comparison - Revision history

Vanwdani at 14:22, 29 March 2018

2018-03-29T14:22:35Z

2018-03-28T18:04:10Z

2018-03-26T16:23:49Z

2018-03-26T16:22:50Z

2018-03-26T16:21:53Z

2018-03-26T16:19:38Z

2018-03-26T15:54:29Z

2018-03-26T15:46:19Z

2018-03-26T15:43:25Z

2018-03-26T15:41:41Z

@@ Line 34: / Line 34: @@
 <center><math>\rho_{target}\times l_{target}=\frac{70.85 kg}{1 m^3}\times \frac{1 mole}{2.02 g} \times \frac{1000g}{1 kg} \times \frac{6\times10^{23} molecule}{1 mole} \times \frac{2\ atoms}{molecule}\times \frac{1m^3}{(100 cm)^3} \times \frac{5 cm}{ } \times \frac{1 \times 10^{-24} cm^{2}}{barn} =.21 barns^{-1}</math></center>
 For 1 cm length of a LH2 target:
@@ Line 49: / Line 51: @@
 <center>[[File:4e7_5cm_LH2_MolThetaLab.png]][[File:4e7_5cm_LH2_MolThetaLab_Detector.png]]</center>
 For 4e7 incident electrons:
@@ Line 74: / Line 78: @@
 <center><math>t=1.3\times 10^{-5}\ s</math></center>
 For 4e8 incident electrons:
@@ Line 99: / Line 105: @@
 <center><math>t=1.3\times 10^{-4}\ s</math></center>
 For 6e7 incident electrons with a 5cm long LH2 target:
@@ Line 124: / Line 132: @@
 <center><math>t=9.62\times 10^{-5}\ s</math></center>

@@ Line 115: / Line 115: @@
 <center><math>\mathcal{L} \cdot t_{simulated}=\frac{N_{events}}{\sigma}</math></center>
-For a Luminosity of <math>\mathcal{L}=\frac{1.3\times 10^{11}}{barn\cdot s}</math>
+For a Luminosity of <math>\mathcal{L}=\frac{1.32\times 10^{11}}{barn\cdot s}</math>
-<center><math>\frac{1.3\times 10^{11}}{barn\cdot s} \cdot t_{simulated}=\frac{4584834}{.361\ barn}</math></center>
+<center><math>\frac{1.32\times 10^{11}}{barn\cdot s} \cdot t_{simulated}=\frac{4584834}{.361\ barn}</math></center>
-<center><math>t=9.8\times 10^{-4}\ s</math></center>
+<center><math>t=9.62\times 10^{-5}\ s</math></center>

@@ Line 37: / Line 37: @@
 For 1 cm length of a LH2 target:
-<center><math>\rho_{target}\times l_{target}=\frac{70.85 kg}{1 m^3}\times \frac{1 mole}{2.02 g} \times \frac{1000g}{1 kg} \times \frac{6\times10^{23} molecule}{1 mole} \times \frac{2\ atoms}{molecule}\times \frac{1m^3}{(100 cm)^3} \times \frac{1 cm}{ } \times \frac{1 \times 10^{-24} cm^{2}}{barn} =.42 barns^{-2}</math></center>
+<center><math>\rho_{target}\times l_{target}=\frac{70.85 kg}{1 m^3}\times \frac{1 mole}{2.02 g} \times \frac{1000g}{1 kg} \times \frac{6\times10^{23} molecule}{1 mole} \times \frac{2\ atoms}{molecule}\times \frac{1m^3}{(100 cm)^3} \times \frac{1 cm}{ } \times \frac{1 \times 10^{-24} cm^{2}}{barn} =.042 barns^{-1}</math></center>
 From earlier simulations for random angle Phi, we know that the full range of Theta is limited depending on the target material.

← Older revision		Revision as of 16:22, 26 March 2018
Line 123:		Line 123:


−	<center><math>t=2.2\times 10^{-3}\ s</math></center>	+	<center><math>t=9.8\times 10^{-4}\ s</math></center>

@@ Line 101: / Line 101: @@
 For 6e7 incident electrons with a 5cm long LH2 target:
-<center><math>\sigma = \frac{N_{events}}{N_{incident}\ \rho\ \ell}=\frac{4584834}{60000000\  \cdot .21barns^{-1}}=\frac{0.076}{.21 barns^{-1}}=3.61 barns</math></center>
+<center><math>\sigma = \frac{N_{events}}{N_{incident}\ \rho\ \ell}=\frac{4584834}{60000000\  \cdot .21barns^{-1}}=\frac{0.076}{.21 barns^{-1}}=.361 barns</math></center>
@@ Line 119: / Line 119: @@
-<center><math>\frac{1.3\times 10^{11}}{barn\cdot s} \cdot t_{simulated}=\frac{4584834}{.016\ barn}</math></center>
+<center><math>\frac{1.3\times 10^{11}}{barn\cdot s} \cdot t_{simulated}=\frac{4584834}{.361\ barn}</math></center>
 <center><math>t=2.2\times 10^{-3}\ s</math></center>

← Older revision		Revision as of 16:19, 26 March 2018
Line 101:		Line 101:

	For 6e7 incident electrons with a 5cm long LH2 target:		For 6e7 incident electrons with a 5cm long LH2 target:
−	<center><math>\sigma = \frac{N_{events}}{N_{incident}\ \rho\ \ell}=\frac{4584834}{60000000\ \cdot .21barns^{-1}}=\frac{0.076}{.21 barns^{-1}}=0.~~016~~ barns</math></center>	+	<center><math>\sigma = \frac{N_{events}}{N_{incident}\ \rho\ \ell}=\frac{4584834}{60000000\ \cdot .21barns^{-1}}=\frac{0.076}{.21 barns^{-1}}=3.61 barns</math></center>

← Older revision		Revision as of 15:54, 26 March 2018
Line 119:		Line 119:


−	<center><math>\frac{1.3\times 10^{11}}{barn\cdot s} \cdot t_{simulated}=\frac{~~9757288~~}{.58\ barn}</math></center>	+	<center><math>\frac{1.3\times 10^{11}}{barn\cdot s} \cdot t_{simulated}=\frac{4584834}{.016\ barn}</math></center>



−	<center><math>t=9.7\times 10^{-5}\ s</math></center>	+	<center><math>t=2.2\times 10^{-3}\ s</math></center>

@@ Line 28: / Line 28: @@
 While this expression has no explicit dependancies on energy, the ratio is a function of the energy, as well as the physical makeup of the target.
-This gives, for LH2:
+This gives,
 <center><math>\rho_{target}\times l_{target}=\frac{70.85 kg}{1 m^3}\times \frac{1 mole}{2.02 g} \times \frac{1000g}{1 kg} \times \frac{6\times10^{23} molecule}{1 mole} \times \frac{2\ atoms}{molecule}\times \frac{1m^3}{(100 cm)^3} \times \frac{5 cm}{ } \times \frac{1 \times 10^{-24} cm^{2}}{barn} =.21 barns^{-1}</math></center>
 From earlier simulations for random angle Phi, we know that the full range of Theta is limited depending on the target material.

← Older revision		Revision as of 15:43, 26 March 2018
Line 43:		Line 43:


−	<center>[[File:4e7_5cm_LH2_MolThetaLab.png]][[File:~~MolThetaLab4e8LH211GeVDetector~~.png]]</center>	+	<center>[[File:4e7_5cm_LH2_MolThetaLab.png]][[File:4e7_5cm_LH2_MolThetaLab_Detector.png]]</center>

	For 4e7 incident electrons:		For 4e7 incident electrons:

← Older revision		Revision as of 15:41, 26 March 2018
Line 43:		Line 43:


−	<center>[[File:~~MolThetaLab4e8LH211GeV~~.png]][[File:MolThetaLab4e8LH211GeVDetector.png]]</center>	+	<center>[[File:4e7_5cm_LH2_MolThetaLab.png]][[File:MolThetaLab4e8LH211GeVDetector.png]]</center>

	For 4e7 incident electrons:		For 4e7 incident electrons: