Forest UCM Homework - Revision history

Foretony: /* Chapt 4 */

2014-08-17T22:06:31Z

Chapt 4

2014-08-17T22:04:22Z

Chapt 3

2014-08-17T21:48:13Z

Chapter 2

2014-08-17T00:04:59Z

Chapt 1

2014-08-16T04:44:54Z

Chapt 1

2014-08-16T04:43:52Z

Chapt 1

2014-08-16T04:41:42Z

Chapt 1

2014-08-16T04:38:24Z

Chapt 1

2014-08-16T04:36:01Z

Chapt 1

2014-08-16T04:31:51Z

Chapt 1

← Older revision		Revision as of 22:06, 17 August 2014
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	4.2, 4.4, 4.8, 4.17, 4,20, 4.23, 4.25, 4.28, 4.31, 4.35, 4.36, 4.46, 4.48, 4.53?		4.2, 4.4, 4.8, 4.17, 4,20, 4.23, 4.25, 4.28, 4.31, 4.35, 4.36, 4.46, 4.48, 4.53?
		+
		+	=Chapt 5=
		+
		+	5.3, 5.5,

	[[Forest_Ugrad_ClassicalMechanics#Homework_Assignments]]		[[Forest_Ugrad_ClassicalMechanics#Homework_Assignments]]

← Older revision		Revision as of 22:04, 17 August 2014
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	3.1,3.2, 3.8, 3.11,3.14, 3.21, 3.25, 3.27, 3.31, 3.23, 3.23, 3.34, 3.35,		3.1,3.2, 3.8, 3.11,3.14, 3.21, 3.25, 3.27, 3.31, 3.23, 3.23, 3.34, 3.35,

		+	=Chapt 4=
		+
		+	4.2, 4.4, 4.8, 4.17, 4,20, 4.23, 4.25, 4.28, 4.31, 4.35, 4.36, 4.46, 4.48, 4.53?

	[[Forest_Ugrad_ClassicalMechanics#Homework_Assignments]]		[[Forest_Ugrad_ClassicalMechanics#Homework_Assignments]]

← Older revision		Revision as of 21:48, 17 August 2014
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		+	=Chapt 3=
		+
		+	3.1,3.2, 3.8, 3.11,3.14, 3.21, 3.25, 3.27, 3.31, 3.23, 3.23, 3.34, 3.35,


	[[Forest_Ugrad_ClassicalMechanics#Homework_Assignments]]		[[Forest_Ugrad_ClassicalMechanics#Homework_Assignments]]

← Older revision		Revision as of 00:04, 17 August 2014
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	1.37.) A student kicks a frictionless puck with initial speed v_0, so that it slides staight up a plane that is inclined at an angle \theta above the horizontal. (a) Write down Newton's second law for the puck and solve to give its position as a function of time.(b) How long will the puck take to return to its starting point?		1.37.) A student kicks a frictionless puck with initial speed v_0, so that it slides staight up a plane that is inclined at an angle \theta above the horizontal. (a) Write down Newton's second law for the puck and solve to give its position as a function of time.(b) How long will the puck take to return to its starting point?
		+
		+
		+	=Chapter 2 =
		+
		+	2.5, 2.6, 2.9,2.13, 2.14, 2.15,2.16, 2.18, 2.21, 2.23, 2.25, 2.27, 2.38, 2.39, 2.53,
		+

← Older revision		Revision as of 04:44, 16 August 2014
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−
−
−	~~1.26, 1.35, 1.36, 1.37, 1.38, 1.46~~
−
−	~~1.26,1.27,1.35,1.36,1.37,~~


	[[Forest_Ugrad_ClassicalMechanics#Homework_Assignments]]		[[Forest_Ugrad_ClassicalMechanics#Homework_Assignments]]

@@ Line 28: / Line 28: @@
 .21.) A parallelepiped has one corner at the origin O and the three edges that emanate from O defined by vectors<math> \vec a</math> , <math>\vec b</math> , <math>\vec c</math>.  Show that the volume of the parallelepiped is <math>\left | \vec a \cdot \left ( \vec b \times \vec c\right )\right |</math>
-.24
+.24.) Find the general solution to the first-order differantial equation
-.26)
 .35.)A golf ball is hit from ground level with speed v_0 in a direction that is due east and at an angle of \theta above the horizontal.  Neglecting air resistance, use Newton's second law to find the position as a finction of tme, using coordiates with x measured east, y nore, and z vertiaclly up.  Find the time for the golf ball to return to the ground and how far it travels in that time.

← Older revision		Revision as of 04:41, 16 August 2014
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−	1.21,1.24	+	1.21.) A parallelepiped has one corner at the origin O and the three edges that emanate from O defined by vectors<math> \vec a</math> , <math>\vec b</math> , <math>\vec c</math>. Show that the volume of the parallelepiped is <math>\left \| \vec a \cdot \left ( \vec b \times \vec c\right )\right \|</math>
		+
		+	1.24
	1.26)		1.26)

@@ Line 19: / Line 19: @@
 .18.)The three vectors \vec a , \vec b , \vec c are the three sides of the triangle ABC with angles \alpha, \beta, \gamma as shown below. (a) Prove that the area of the triangle is given by any one of the these three expressions:
 : area <math>= \frac{1}{2} \left | \vec{a} \times \vec{b} \right | = \frac{1}{2} \left | \vec{b} \times \vec{c} \right | = \frac{1}{2} \left | \vec{c} \times \vec{a} \right |</math>
 .21,1.24

@@ Line 17: / Line 17: @@
 :<math>\frac{d}{dt} \left ( \vec{r} \times \vec {s} \right ) =   \vec{r} \times \frac{d \vec {s}}{dt} +  \frac{d \vec {r}}{dt}  \times \vec{s} </math>
-.18,1.21,1.24
+.18.)The three vectors \vec a , \vec b , \vec c are the three sides of the triangle ABC with angles \alpha, \beta, \gamma as shown below. (a) Prove that the area of the triangle is given by any one of the these three expressions:
 .26)

@@ Line 15: / Line 15: @@
 .17.) (a) prove that the vector product <math>\vec{r} \times \vec{s}</math> is distributive; that is, that <math>\vec{r} \times \left ( \vec{u} + \vec {s} \right ) = \vec{r} \times  \vec{u} + \vec{r} \times \vec {s}</math>.  (b) prove the product rule
-:<math>\frac{d}{dt} \left ( \vec{r} \times \vec {s} \right ) =   \vec{r} \times \frac{d \vec {s}}{dt} +  \vec{r} \times \frac{d \vec {s}}{dt}</math>
+:<math>\frac{d}{dt} \left ( \vec{r} \times \vec {s} \right ) =   \vec{r} \times \frac{d \vec {s}}{dt} +  \frac{d \vec {r}}{dt}  \times \vec{s} </math>
 .18,1.21,1.24