Forest PHYS100 Demos Week5 - Revision history

Foretony: /* Roulette Wheel: */

2014-09-24T14:17:38Z

Roulette Wheel:

Foretony: /* Roulette Wheel: */

2014-09-23T16:28:07Z

Roulette Wheel:

Foretony at 15:31, 23 September 2014

2014-09-23T15:31:56Z

Foretony at 03:00, 22 September 2014

2014-09-22T03:00:25Z

Foretony: Created page with " Forest_PHYS100_Demos"

2014-08-28T11:30:16Z

Created page with " Forest_PHYS100_Demos"

New page

[[Forest_PHYS100_Demos]]

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 =Roulette Wheel:=
 For this demonstration I will ask the students what the minimum angular velocity will be in order to keep the ball in the wheel without falling. The answer is that minimally we will at least need the force of gravity to be equall to the normal force. We can set the normal force equal to mv^2/r where m is the mass of the ball and r is the radius of the loop. We can solve for v and find the angular velocity by dividing v by r. Alternatively you can set mg = m(omega)^2*r and solve for omega.
 [[Forest_PHYS100_Demos]]

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 For this demonstration I will start with an anecdote about a swing set. No matter how hard you try by yourself, you are unable to make the swing fully rotate over the top bar with you on the swing. Why is this? The correct answer is that you don’t have enough of a centripetal acceleration in order to keep the chains tight on the swing, so they go slack. This will mean that the earth’s gravity will take over and you will fall on the top bar. What if you could swing fast enough? What would the motion of the swing look like? You are able to maintain uniform circular motion because the centripetal acceleration towards the center of the circle is greater than the acceleration due to gravity. I will then ask them what would will happen if I swing the platform over my head? The answer is that the wine glass will stay on the platform due to a higher centripetal acceleration than gravity.
 =Roulette Wheel:=
-For this demonstration I will ask the students what the minimum angular velocity will be in order to keep the ball in the wheel without falling. The answer is that minimally we will at least need the force of gravity to be equally to the normal force. We can set the normal force equal to mv^2/r where m is the mass of the ball and r is the radius of the loop. We can solve for v and find the angular velocity by dividing v by r. Alternatively you can set mg = m(omega)^2*r and solve for omega.
+For this demonstration I will ask the students what the minimum angular velocity will be in order to keep the ball in the wheel without falling. The answer is that minimally we will at least need the force of gravity to be equall to the normal force. We can set the normal force equal to mv^2/r where m is the mass of the ball and r is the radius of the loop. We can solve for v and find the angular velocity by dividing v by r. Alternatively you can set mg = m(omega)^2*r and solve for omega.
 [[Forest_PHYS100_Demos]]

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 [[File:TF_PHY100_RetroGrade_anim.gif]]
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← Older revision		Revision as of 03:00, 22 September 2014
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	[[Forest_PHYS100_Demos]]		[[Forest_PHYS100_Demos]]