Determining wire-theta correspondence - Revision history

Vanwdani at 20:12, 15 May 2018

2018-05-15T20:12:29Z

2017-05-24T16:44:13Z

5.1.1 Determine a Wire-Theta Correspondence

2017-05-23T16:28:14Z

5.1.1 Determine a Wire-Theta Correspondence

2017-05-23T16:22:55Z

5.1.1 Determine a Wire-Theta Correspondence

2017-05-22T19:39:36Z

5.1.1 Determine a Wire-Theta Correspondence

2017-05-22T19:31:27Z

5.1.1 Determine a Wire-Theta Correspondence

2017-05-22T19:29:53Z

5.1.1 Determine a Wire-Theta Correspondence

2017-05-22T19:22:54Z

5.1.1 Determine a Wire-Theta Correspondence

2017-05-22T19:19:18Z

5.1.1 Determine a Wire-Theta Correspondence

2017-05-22T19:10:13Z

5.1.1 Determine a Wire-Theta Correspondence

@@ Line 1: / Line 1: @@
-<center><math>\textbf{\underline{Navigation}}</math>
+<center><math>\underline{\textbf{Navigation}}</math>
 [[VanWasshenova_Thesis#Determining_wire-theta_correspondence|<math>\vartriangleleft </math>]]
@@ Line 247: / Line 247: @@
-<center><math>\textbf{\underline{Navigation}}</math>
+<center><math>\underline{\textbf{Navigation}}</math>
 [[VanWasshenova_Thesis#Determining_wire-theta_correspondence|<math>\vartriangleleft </math>]]

← Older revision		Revision as of 16:44, 24 May 2017
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−	<center><math>\Rightarrow n = \frac{-959.~~189~~}{\tan{ \theta}+2.14437}+430.189</math></center>	+	<center><math>\Rightarrow n = \frac{-959.637}{\tan{ \theta}+2.14437}+430.189</math></center>

@@ Line 160: / Line 160: @@
 {| class="wikitable" align="center"
-| style="background: gray"      | <math>19.914\ cm+2.3078\ cm = 22.2218\ cm\ \hat{x}\equiv x_1</math>
+| style="background: gray"      | <math>19.9014\ cm+2.3078\ cm = 22.2092\ cm\ \hat{x}\equiv x_1</math>
 |}
@@ Line 201: / Line 201: @@
-<center><math>x_0 \equiv x_1 - \Delta x \equiv 22.2218\ cm\ - 1.212\ cm=21.0098\ cm</math></center>
+<center><math>x_0 \equiv x_1 - \Delta x \equiv 22.2092\ cm\ - 1.212\ cm=20.9972\ cm</math></center>
@@ Line 232: / Line 232: @@
-<center><math>x(n)=21.0098+1.212\ n</math></center>
+<center><math>x(n)=20.9972+1.212\ n</math></center>
@@ Line 238: / Line 238: @@
-<center><math>\tan{\theta}=\frac{21.0098+n1.212}{243.1431-n0.5652}\Rightarrow \tan{ \theta}=\frac{-959.637}{n - 430.189} - 2.14437 \Rightarrow 430.637 - n = \frac{959.637}{\tan{ \theta}+2.14437}</math></center>
+<center><math>\tan{\theta}=\frac{20.9972+n1.212}{243.1431-n0.5652}\Rightarrow \tan{ \theta}=\frac{-959.637}{n - 430.189} - 2.14437 \Rightarrow 430.637 - n = \frac{959.637}{\tan{ \theta}+2.14437}</math></center>

@@ Line 226: / Line 226: @@
-<center><math>\theta(wire\ 1)=\arctan\ .09155=5.2311^{\circ}</math></center>
+<center><math>\theta_{wire\ 1}=\arctan\ .09155=5.2311^{\circ}</math></center>
+<center><math>x(n)=21.0098+1.212\ n</math></center>
@@ Line 243: / Line 238: @@
-<center><math>\tan{\theta}=\frac{20.9972+n1.212}{243.1431-n0.5652}\Rightarrow \tan{ \theta}=\frac{-959.637}{n - 430.189} - 2.14437 \Rightarrow 430.637 - n = \frac{959.637}{\tan{ \theta}+2.14437}</math></center>
+<center><math>\tan{\theta}=\frac{21.0098+n1.212}{243.1431-n0.5652}\Rightarrow \tan{ \theta}=\frac{-959.637}{n - 430.189} - 2.14437 \Rightarrow 430.637 - n = \frac{959.637}{\tan{ \theta}+2.14437}</math></center>

@@ Line 192: / Line 192: @@
-<center><math>x \equiv x_1 + \Delta x</math></center>
+<center><math>x_2 \equiv x_1 + \Delta x</math></center>
-<center><math>z \equiv z_1 + \Delta z</math></center>
+<center><math>z_2 \equiv z_1 + \Delta z</math></center>
@@ Line 201: / Line 201: @@
-<center><math>x_0 \equiv x_1 - \Delta x</math></center>
+<center><math>x_0 \equiv x_1 - \Delta x \equiv 22.2218\ cm\ - 1.212\ cm=21.0098\ cm</math></center>
-<center><math>z_0 \equiv z_1 - \Delta z</math></center>
+<center><math>z_0 \equiv z_1 - \Delta z \equiv 242.5779\ cm\ +0.5652\ cm=243.1431\ cm</math></center>

← Older revision	Revision as of 19:29, 22 May 2017
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	+	With respect to the target, this location becomes
	+
	+	{\| class="wikitable" align="center"
	+	\| style="background: gray" \| <math>19.914\ cm+2.3078\ cm = 22.2218\ cm\ \hat{x}</math>
	+	\|}
	+
	+
	+
	+
	+
	+
	+
	+	{\| class="wikitable" align="center"
	+	\| style="background: gray" \| <math>242.376cm\ +.2019\ cm =242.5779\ cm\ \hat{z}</math>
	+	\|}

← Older revision		Revision as of 19:22, 22 May 2017
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	Making a right triangle, with the x' component as the hypotenuse, we find the x and z components		Making a right triangle, with the x' component as the hypotenuse, we find the x and z components

		+	{\| class="wikitable" align="center"
		+	\| style="background: gray" \| <math>21.9587cm\ sin\ 65^{\circ}=19.914cm\ \hat{x}</math>
		+	\|}

−	~~<center><math>21.9587cm\ sin\ 65^{\circ}=19.914cm\ \hat{x}</math>{{Font color\|\|yellow\|to 1st guard wire}}</center>~~


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−	<center><math>251.6562cm-9.2802cm=242.376cm\ \hat{z}</math>~~{{Font color~~\|~~\|yellow\|to 1st guard wire~~}~~}</center>~~	+	{\| class="wikitable" align="center"
		+	\| style="background: gray" \| <math>251.6562cm-9.2802cm=242.376cm\ \hat{z}</math>
		+	\|}
		+

← Older revision		Revision as of 19:19, 22 May 2017
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−	<center><math>21.9587cm\ sin\ 65^{\circ}=19.914cm\ \hat{x}</math></center>	+	<center><math>21.9587cm\ sin\ 65^{\circ}=19.914cm\ \hat{x}</math>{{Font color\|\|yellow\|to 1st guard wire}}</center>


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−	<center><math>251.6562cm-9.2802cm=242.376cm\ \hat{z}</math></center>	+	<center><math>251.6562cm-9.2802cm=242.376cm\ \hat{z}</math>{{Font color\|\|yellow\|to 1st guard wire}}</center>

← Older revision		Revision as of 19:10, 22 May 2017
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	Using the fact that the outer sides of an equalateral hexagon are equal in length, we can find that the distance from the first guard wire, in the first guard wire plane, to the first sense wire, in the first sense wire plane, is		Using the fact that the outer sides of an equalateral hexagon are equal in length, we can find that the distance from the first guard wire, in the first guard wire plane, to the first sense wire, in the first sense wire plane, is

−	<center><math>~~distance~~=3(2D)</math></center>	+	<center><math>r_{WRT\ 1st\ guard\ wire}=3(2D)=2.3166\ cm</math></center>