ClasSched Forest Ugrad ClassicalMechanics - Revision history

Foretony at 03:33, 7 December 2014

2014-12-07T03:33:20Z

2014-11-19T17:58:14Z

Final Exam Format

2014-11-19T17:55:13Z

Midterm Format

2014-11-10T16:45:12Z

2014-11-10T16:43:14Z

2014-10-31T02:03:56Z

2014-10-31T01:56:03Z

2014-10-31T01:49:29Z

2014-10-31T01:48:18Z

2014-10-31T01:45:30Z

@@ Line 27: / Line 27: @@
 | 12|| Ch 9 || Ch 9 || Ch 9: 9.1, 9.2, 9.4, 9.6
 |-
-| 13|| Ch 10 || Ch 10 ||
+| 13|| Ch 10 || Ch 10 || 10.26, 10.36,
 |-
 | 14 || x || x || x

@@ Line 60: / Line 60: @@
 word problems will require using a Lagrangian to determine the equations of motion
 word problem will involved a Rotating coordinate system or a Rigid Body
-word problem will involve oscillations, air resistance,
+word problem will involve oscillations, air resistance, conservation of E or P
 An Equation sheet is given on the exam and includes

← Older revision		Revision as of 17:55, 19 November 2014
Line 45:		Line 45:

	Word problems are graded with 10 points awarded for the identification of physics principle being used, 10 points for the application of that principle, and 5 points for the correct answer.		Word problems are graded with 10 points awarded for the identification of physics principle being used, 10 points for the application of that principle, and 5 points for the correct answer.
		+
		+	An Equation sheet is given on the exam and includes
		+
		+	#cartesian, polar, and spherical coordinate systems with position, velocity , and acceleration vectors
		+	#List of identities (trigonometric, integrals,…)
		+	#Table with the Moments of Inertia
		+
		+	=Final Exam Format=
		+
		+	4 word problems worth 25 point each and 20 Multiple Choice problems worth 5 points each
		+
		+	Word problems are graded with 10 points awarded for the identification of physics principle being used, 10 points for the application of that principle, and 5 points for the correct answer.
		+
		+	2 word problems will require using a Lagrangian to determine the equations of motion
		+	1 word problem will involved a Rotating coordinate system or a Rigid Body
		+	1 word problem will involve oscillations, air resistance,

	An Equation sheet is given on the exam and includes		An Equation sheet is given on the exam and includes

@@ Line 25: / Line 25: @@
 | 11 || Ch 7 || Ch 7 || Ch 7 :  7.29, 7.37, 7.50, 7.51
 |-
-| 12|| Ch 9 || Ch 9 || Ch 9: 9.6
+| 12|| Ch 9 || Ch 9 || Ch 9: 9.1, 9.2, 9.4, 9.6
 |-
 | 13|| Ch 10 || Ch 10 ||

@@ Line 25: / Line 25: @@
 | 11 || Ch 7 || Ch 7 || Ch 7 :  7.29, 7.37, 7.50, 7.51
 |-
-| 12|| Ch 9 || Ch 9 ||
+| 12|| Ch 9 || Ch 9 || Ch 9: 9.6
 |-
 | 13|| Ch 10 || Ch 10 ||

@@ Line 15: / Line 15: @@
 | 6 || Ch 4 || Ch 4 || Ch 4 :  4.4, 4.8, 4.9, 4.23,
 |-
-| 7 || Ch 4 || Ch 4 || Ch 4 :  4.35, 4.38 (Alister), 4.49, 4.53
+| 7 || Ch 4 || Ch 4 || Ch 4 :  4.35, 4.38 (Alister), 4.49, 4.53;
 |-
-| 8 || Ch 4 || Ch 4 || MidTerm
+| 8 || Ch 5 || Ch 5 || Ch 5 :  5.19, 5.30, 5.44 (Alister), 5.43; Midterm
 |-
-| 9 || Ch 5 || Ch 5 || Ch 5 :  5.19, 5.30, 5.44 (Alister), 5.43
+| 9 || Ch 5 || Ch 6 || Ch 6 :  6.15, 6.22, 6.23, 6.24
 |-
-| 10 || Ch 5 || Ch 6 || Ch 6 :  6.15, 6.22, 6.23, 6.24
+| 10 || Ch 6 || Ch 6 || Ch 7 :  7.8, 7.14, 7.15, 7.17
 |-
-| 11 || Ch 6 || Ch 6 || Ch 7 :  7.8, 7.14, 7.15, 7.17
+| 11 || Ch 7 || Ch 7 || Ch 7 :  7.29, 7.37, 7.50, 7.51
 |-
-| 12 || Ch 7 || Ch 7 || Ch 7 :  7.29, 7.37, 7.50, 7.51
+| 12|| Ch 7 || Ch 7 ||
 |-
-| 13 || Ch 7 || Ch 7 ||
+| 13 || x || x || x
 |-
 | 14 || Ch 7 || Ch 7 || Ch 7 :  7.3