Check Differential Cross-Section - Revision history

Vanwdani at 17:43, 20 April 2016

2016-04-20T17:43:28Z

2016-04-20T17:14:25Z

2016-04-20T16:31:47Z

2016-04-20T15:36:09Z

2016-04-05T18:17:40Z

2016-04-05T18:13:35Z

2016-04-05T18:05:08Z

2016-04-05T17:42:47Z

2016-04-05T17:42:15Z

2016-04-05T17:41:18Z

@@ Line 59: / Line 59: @@
 [[File:Extended_DiffXSect_TheoryExperiment.png|frame|center|alt=Moller Differential Cross-Section CM Frame|'''Figure 15:''' The Moller Differential Cross-Section for a 11GeV incident particle vs. detected electrons theta distribution in eg12 detector for a random, uniform phi distribution of a known Moller Differential Cross-Section distribution.]]
-[[File:Temp.png]]
+[[File:WeightedXSECT.png]]
 ----

@@ Line 59: / Line 59: @@
 [[File:Extended_DiffXSect_TheoryExperiment.png|frame|center|alt=Moller Differential Cross-Section CM Frame|'''Figure 15:''' The Moller Differential Cross-Section for a 11GeV incident particle vs. detected electrons theta distribution in eg12 detector for a random, uniform phi distribution of a known Moller Differential Cross-Section distribution.]]
-[[File:Temo.png]]
+[[File:Temp.png]]
 ----

← Older revision		Revision as of 16:31, 20 April 2016
Line 59:		Line 59:
	[[File:Extended_DiffXSect_TheoryExperiment.png\|frame\|center\|alt=Moller Differential Cross-Section CM Frame\|'''Figure 15:''' The Moller Differential Cross-Section for a 11GeV incident particle vs. detected electrons theta distribution in eg12 detector for a random, uniform phi distribution of a known Moller Differential Cross-Section distribution.]]		[[File:Extended_DiffXSect_TheoryExperiment.png\|frame\|center\|alt=Moller Differential Cross-Section CM Frame\|'''Figure 15:''' The Moller Differential Cross-Section for a 11GeV incident particle vs. detected electrons theta distribution in eg12 detector for a random, uniform phi distribution of a known Moller Differential Cross-Section distribution.]]

		+	[[File:Temo.png]]

	----		----

← Older revision		Revision as of 15:36, 20 April 2016
Line 39:		Line 39:


−	This shows a trait of providing around 100 Moller electrons of Energy greater that 500 MeV for about 1 million incident electrons of Energy 11 GeV. Since the boosting of the number of Phi angles leaves around 4431573 Moller electrons with Energy greater than 500 MeV, this would imply around 4e10 incident electrons of Energy 11 GeV.	+	This shows a trait of providing around 100 Moller electrons of Energy greater that 500 MeV for about 1 million incident electrons of Energy 11 GeV.
		+
		+	Since a run of x where the boosting of the number of Phi angles leaves around 4431573 Moller electrons with Energy greater than 500 MeV, this would imply around 4e10 incident electrons of Energy 11 GeV.

	Using the same expression, but this time for 4e10 incident electrons,		Using the same expression, but this time for 4e10 incident electrons,

← Older revision		Revision as of 18:17, 5 April 2016
Line 55:		Line 55:
	Theory->Draw("same");</pre>		Theory->Draw("same");</pre>

		+	[[File:Extended_DiffXSect_TheoryExperiment.png\|frame\|center\|alt=Moller Differential Cross-Section CM Frame\|'''Figure 15:''' The Moller Differential Cross-Section for a 11GeV incident particle vs. detected electrons theta distribution in eg12 detector for a random, uniform phi distribution of a known Moller Differential Cross-Section distribution.]]

−	~~[[File:Extended_DiffXSect_TheoryExperiment.png]]~~

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@@ Line 45: / Line 45: @@
 <center><math>\frac{1}{\rho_{target}\times l_{target} \times 4\times 10^{10}}=8.87\times 10^{-10} barns=.000887 \mu b</math></center>
-Rebining the histogram to account for the unequal weighting of the bins outlined in the table above
+Rebining the histogram to account for the [[Calculations_of_4-momentum_components#Run_for_Necessary_Amount_to_match_Cross_Section|unequal weighting of the bins outlined previously ]].
 <pre>TH1F *Combo=new TH1F("TheoryExperiment","Theoretical and Experimental Differential Cross-Section CM Frame",360,90,180);

← Older revision		Revision as of 18:05, 5 April 2016
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	Since extra Phi angles have been produced obviously a larger number of incident electrons would be needed. Looking at the number Moller events are created for 1E6, 1E7, and 4E8 incident electrons, we can estimate the number of incident electrons needed for the number of extra Phi angles produced.		Since extra Phi angles have been produced obviously a larger number of incident electrons would be needed. Looking at the number Moller events are created for 1E6, 1E7, and 4E8 incident electrons, we can estimate the number of incident electrons needed for the number of extra Phi angles produced.
		+
		+	<pre>wc -l MollerScattering_NH3_4e8incident.dat</pre>
		+
		+	<pre>
		+	awk ' $6 >= 500 ' Just_Scattered_Momentum_4e8.dat>Just_Scattered_Momentum_4e8_500MeV.dat
		+	wc -l Just_Scattered_Momentum_4e8_500MeV.dat</pre>

	{\| border=1		{\| border=1

@@ Line 11: / Line 11: @@
 Since extra Phi angles have been produced obviously a larger number of incident electrons would be needed.  Looking at the number Moller events are created for 1E6, 1E7, and 4E8 incident electrons, we can estimate the number of incident electrons needed for the number of extra Phi angles produced.
-<center>{| border=1
+{| border=1
    |+ Moller Events per Incident Electrons
 |-
@@ Line 29: / Line 29: @@
    | 12444898
    | 48548
-|}</center>
+|}
@@ Line 37: / Line 37: @@
 Using the same expression, but this time for 4e10 incident electrons,
-:::::<math>\frac{1}{\rho_{target}\times l_{target} \times 4\times 10^{10}}=8.87\times 10^{-10} barns=.000887 \mu b</math>
+<center><math>\frac{1}{\rho_{target}\times l_{target} \times 4\times 10^{10}}=8.87\times 10^{-10} barns=.000887 \mu b</math></center>
 Rebining the histogram to account for the unequal weighting of the bins outlined in the table above

@@ Line 7: / Line 7: @@
 If the beam had 4E8 incident electrons, the differential cross-section would be found with,
-:::::<math>\frac{1}{\rho_{target}\times l_{target} \times 4\times 10^9}=8.87\times 10^{-8} barns=.0887 \mu b</math>
+:::::<math>\frac{1}{\rho_{target}\times l_{target} \times 4\times 10^8}=8.87\times 10^{-8} barns=.0887 \mu b</math>
 Since extra Phi angles have been produced obviously a larger number of incident electrons would be needed.  Looking at the number Moller events are created for 1E6, 1E7, and 4E8 incident electrons, we can estimate the number of incident electrons needed for the number of extra Phi angles produced.