Big Red - Revision history

Oborn at 21:20, 15 May 2009

2009-05-15T21:20:33Z

← Older revision		Revision as of 21:20, 15 May 2009
Line 1:		Line 1:

	== Specs: ==		== Specs: ==

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	The displacement is found as: d=R-Rcos(θ)=mv/eB(1-cos(θ))		The displacement is found as: d=R-Rcos(θ)=mv/eB(1-cos(θ))

	Table: Data for B=0.~~0015~~ T.		Table: Data for B=0.0078 T.
	{\| border="1" cellpadding="2"		{\| border="1" cellpadding="2"
	!width="70"\|Momentum		!width="70"\|Momentum
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	\|P (MeV)\|\|R (m)\|\|θ (radians)\|\|θ (degrees)\|\|d (cm)		\|P (MeV)\|\|R (m)\|\|θ (radians)\|\|θ (degrees)\|\|d (cm)
	\|-		\|-
	\|1\|\|2.~~22376032~~\|\|0.~~12398179~~\|\|7.~~103633471~~\|\|1.~~706936726~~		\|1\|\|0.43\|\|0.70\|\|40.02\|\|10.01
	\|-		\|-
	\|2\|\|4.~~44752065~~\|\|0.~~06187167~~\|\|3.~~544985606~~\|\|0.~~851006969~~		\|2\|\|0.86\|\|0.33\|\|18.76\|\|4.54
	\|-		\|-
	\|3\|\|6.~~67128097~~\|\|0.~~04123315~~\|\|2.~~362485567~~\|\|0.~~567036176~~		\|3\|\|1.28\|\|0.22\|\|12.38\|\|2.98
	\|-		\|-
	\|4\|\|8.~~89504129~~\|\|0.~~03092103~~\|\|1.~~77164444~~\|\|0.~~425198022~~		\|4\|\|1.71\|\|0.16\|\|9.25\|\|2.22
	\|-		\|-
	\|5\|\|11.~~1188016~~\|\|0.~~0247354~~\|\|1.~~417234227~~\|\|0.~~340129141~~		\|5\|\|2.14\|\|0.13\|\|7.39\|\|1.78
	\|-		\|-
	\|6\|\|13.~~3425619~~\|\|0.~~02061219~~\|\|1.~~180991717~~\|\|0.~~283427701~~		\|6\|\|2.57\|\|0.11\|\|6.15\|\|1.48
	\|-		\|-
	\|7\|\|15.~~5663223~~\|\|0.~~01766726~~\|\|1.~~012259595~~\|\|0.~~242931183~~		\|7\|\|2.99\|\|0.09\|\|5.27\|\|1.27
	\|-		\|-
	\|8\|\|17.~~7900826~~\|\|0.~~01545867~~\|\|0.~~885716346~~\|\|0.~~212560897~~		\|8\|\|3.42\|\|0.08\|\|4.61\|\|1.11
	\|-		\|-
	\|9\|\|20.~~0138429~~\|\|0.~~01374092~~\|\|0.~~787296837~~\|\|0.~~18894065~~		\|9\|\|3.85\|\|0.07\|\|4.10\|\|0.98
	\|-		\|-
	\|10\|\|22.~~2376032~~\|\|0.~~01236676~~\|\|0.~~708562916~~\|\|0.~~17004506~~		\|10\|\|4.28\|\|0.06\|\|3.69\|\|0.89
	\|-		\|-
	\|11\|\|24.~~4613636~~\|\|0.~~01124246~~\|\|0.~~644145256~~\|\|0.~~154585392~~		\|11\|\|4.70\|\|0.06\|\|3.35\|\|0.80
	\|-		\|-
	\|12\|\|26.~~6851239~~\|\|0.~~01030555~~\|\|0.~~590464498~~\|\|0.~~141702561~~		\|12\|\|5.13\|\|0.05\|\|3.07\|\|0.74
	\|-		\|-
	\|13\|\|28.~~9088842~~\|\|0.~~00951279~~\|\|0.~~545042725~~\|\|0.~~13080185~~		\|13\|\|5.56\|\|0.05\|\|2.84\|\|0.68
	\|-		\|-
	\|14\|\|31.~~1326445~~\|\|0.~~00883329~~\|\|0.~~50611005~~\|\|0.~~121458483~~		\|14\|\|5.99\|\|0.05\|\|2.63\|\|0.63
	\|-		\|-
	\|15\|\|33.~~3564048~~\|\|0.~~00824439~~\|\|0.~~472368588~~\|\|0.~~113360965~~		\|15\|\|6.41\|\|0.04\|\|2.46\|\|0.59
	\|-		\|-
	\|16\|\|35.~~5801652~~\|\|0.~~0077291~~\|\|0.~~442844944~~\|\|0.~~106275686~~		\|16\|\|6.84\|\|0.04\|\|2.30\|\|0.55
	\|}		\|}

Oborn: /* CALCULATIONS */

2009-05-13T22:46:39Z

CALCULATIONS

← Older revision		Revision as of 22:46, 13 May 2009
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	giving: <math>R=mv/eB</math>		giving: <math>R=mv/eB</math>

	The length of the circular arc is S and the deflection angle is found as: ~~<math>~~sin(θ)=S/R~~</math>~~		The length of the circular arc is S and the deflection angle is found as: sin(θ)=S/R

	For small θ, and large R, the arc length S will be approx L, giving: ~~<math>~~sin(θ)=L/R=LeB/m*v~~</math>~~		For small θ, and large R, the arc length S will be approx L, giving: sin(θ)=L/R=LeB/m*v

	Giving ~~<math>~~θ=sin^(-1)(cBL/p)~~</math>~~		Giving θ=sin^(-1)(cBL/p)

	The displacement is found as: ~~<math>~~d=R-Rcos(θ)=mv/eB(1-cos(θ))~~</math>~~		The displacement is found as: d=R-Rcos(θ)=mv/eB(1-cos(θ))

	Table: Data for B=0.0015 T.		Table: Data for B=0.0015 T.

Oborn: /* CALCULATIONS */

2009-05-13T22:41:26Z

CALCULATIONS

← Older revision		Revision as of 22:41, 13 May 2009
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	Magnetic force: <math>F=evB</math>		Magnetic force: <math>F=evB</math>

	The radius of the arc can be through: <math>(mv^2)/R=evB</math>		The radius of the arc can be through: <math>(mv^2)/R=ev*B</math>

	giving: <math>R=mv/eB</math>		giving: <math>R=mv/eB</math>

Oborn: /* CALCULATIONS */

2009-05-13T22:40:25Z

CALCULATIONS

← Older revision		Revision as of 22:40, 13 May 2009
Line 24:		Line 24:
	Electron moves through the magnetic field B accelerated by force F proportional to the component of velocity perpendicular to the field B and velocity v. Moves with constant kinetic energy and speed due to the fact that the magnetic field never does work on the particle since the always moves perpendicular to the force.		Electron moves through the magnetic field B accelerated by force F proportional to the component of velocity perpendicular to the field B and velocity v. Moves with constant kinetic energy and speed due to the fact that the magnetic field never does work on the particle since the always moves perpendicular to the force.

	Magnetic force: F=evB		Magnetic force: <math>F=evB</math>

	The radius of the arc can be through: <math>(mv^2)/R=evB</math>		The radius of the arc can be through: <math>(mv^2)/R=evB</math>

Oborn: /* CALCULATIONS */

2009-05-13T22:39:31Z

CALCULATIONS

← Older revision		Revision as of 22:39, 13 May 2009
Line 24:		Line 24:
	Electron moves through the magnetic field B accelerated by force F proportional to the component of velocity perpendicular to the field B and velocity v. Moves with constant kinetic energy and speed due to the fact that the magnetic field never does work on the particle since the always moves perpendicular to the force.		Electron moves through the magnetic field B accelerated by force F proportional to the component of velocity perpendicular to the field B and velocity v. Moves with constant kinetic energy and speed due to the fact that the magnetic field never does work on the particle since the always moves perpendicular to the force.

	Magnetic force: F=~~evB~~		Magnetic force: F=evB

	The radius of the arc can be through: <math>(mv^2)/R=~~evB~~</math>		The radius of the arc can be through: <math>(mv^2)/R=evB</math>

	giving: <math>R=mv/eB</math>		giving: <math>R=mv/eB</math>

	The length of the circular arc is S and the deflection angle is found as: <math>sin(~~theta~~)=S/R</math>		The length of the circular arc is S and the deflection angle is found as: <math>sin(θ)=S/R</math>

	For small θ, and large R, the arc length S will be approx L, giving: <math>sin(~~theta~~)=L/R=~~LeB~~/mv</math>		For small θ, and large R, the arc length S will be approx L, giving: <math>sin(θ)=L/R=LeB/m*v</math>
	Giving <math>θ=sin^(-1)⁡〖 (~~cBL~~/p)〗</math>
	The displacement is found as: <math>d=R-~~Rcos~~(~~theta~~)=mv/eB(1-cos(~~theta~~))</math>		Giving <math>θ=sin^(-1)(cBL/p)</math>

			The displacement is found as: <math>d=R-Rcos(θ)=mv/eB(1-cos(θ))</math>

	Table: Data for B=0.0015 T.		Table: Data for B=0.0015 T.

Oborn: /* CALCULATIONS */

2009-05-13T22:35:41Z

CALCULATIONS

← Older revision		Revision as of 22:35, 13 May 2009
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	'''Calculating the Magnetic Field Needed:'''		'''Calculating the Magnetic Field Needed:'''

	Lorentz Force equation: ~~<math>~~F=q(v×B)~~</math>~~		Lorentz Force equation: F=q(v×B)

	Electron moves through the magnetic field B accelerated by force F proportional to the component of velocity perpendicular to the field B and velocity v. Moves with constant kinetic energy and speed due to the fact that the magnetic field never does work on the particle since the always moves perpendicular to the force.		Electron moves through the magnetic field B accelerated by force F proportional to the component of velocity perpendicular to the field B and velocity v. Moves with constant kinetic energy and speed due to the fact that the magnetic field never does work on the particle since the always moves perpendicular to the force.

	Magnetic force: ~~<math>~~F=evB~~</math>~~		Magnetic force: F=evB

	The radius of the arc can be through: <math>(mv^2)/R=evB</math>		The radius of the arc can be through: <math>(mv^2)/R=evB</math>
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	giving: <math>R=mv/eB</math>		giving: <math>R=mv/eB</math>

	The length of the circular arc is S and the deflection angle is found as: <math>~~sinθ~~=S/R</math>		The length of the circular arc is S and the deflection angle is found as: <math>sin(theta)=S/R</math>

	For small θ, and large R, the arc length S will be approx L, giving: <math>~~sinθ~~=L/R=LeB/mv</math>		For small θ, and large R, the arc length S will be approx L, giving: <math>sin(theta)=L/R=LeB/mv</math>
	Giving <math>θ=sin^(-1)⁡〖 (cBL/p)〗</math>		Giving <math>θ=sin^(-1)⁡〖 (cBL/p)〗</math>
	The displacement is found as: <math>d=R-~~Rcosθ~~=mv/eB(1-~~cosθ~~)</math>		The displacement is found as: <math>d=R-Rcos(theta)=mv/eB(1-cos(theta))</math>

	Table: Data for B=0.0015 T.		Table: Data for B=0.0015 T.

Oborn: /* CALCULATIONS */

2009-05-13T22:34:10Z

CALCULATIONS

← Older revision		Revision as of 22:34, 13 May 2009
Line 20:		Line 20:
	'''Calculating the Magnetic Field Needed:'''		'''Calculating the Magnetic Field Needed:'''

	Lorentz Force equation: F=q(v×B)		Lorentz Force equation: <math>F=q(v×B)</math>

	Electron moves through the magnetic field B accelerated by force F proportional to the component of velocity perpendicular to the field B and velocity v. Moves with constant kinetic energy and speed due to the fact that the magnetic field never does work on the particle since the always moves perpendicular to the force.		Electron moves through the magnetic field B accelerated by force F proportional to the component of velocity perpendicular to the field B and velocity v. Moves with constant kinetic energy and speed due to the fact that the magnetic field never does work on the particle since the always moves perpendicular to the force.

	Magnetic force: F=evB		Magnetic force: <math>F=evB</math>

	The radius of the arc can be through: (mv^2)/R=evB		The radius of the arc can be through: <math>(mv^2)/R=evB</math>

	giving R=mv/eB		giving: <math>R=mv/eB</math>
	~~The length of the circular arc is S and the deflection angle is found as sinθ=S~~/R

	For small θ, and large R, the arc length S will be approx L, giving		The length of the circular arc is S and the deflection angle is found as: <math>sinθ=S/R</math>
	sinθ=L/R=LeB/mv
	Giving θ=sin^(-1)⁡〖 (cBL/p)〗		For small θ, and large R, the arc length S will be approx L, giving: <math>sinθ=L/R=LeB/mv</math>
	The displacement is found as: d=R-Rcosθ=mv/eB(1-cosθ)		Giving <math>θ=sin^(-1)⁡〖 (cBL/p)〗</math>
			The displacement is found as: <math>d=R-Rcosθ=mv/eB(1-cosθ)</math>

	Table: Data for B=0.0015 T.		Table: Data for B=0.0015 T.

Oborn: /* CALCULATIONS */

2009-05-13T22:31:54Z

CALCULATIONS

← Older revision		Revision as of 22:31, 13 May 2009
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	!width="70"\|Momentum		!width="70"\|Momentum
	!width="70"\|Radius of Curvature		!width="70"\|Radius of Curvature
	!width="~~140~~"\|Bend Angle		!width="70"\|Bend Angle
			!width="70"\|Bend Angle
	!width="70"\|Displacement @ end of magnet		!width="70"\|Displacement @ end of magnet

Oborn at 22:29, 13 May 2009

2009-05-13T22:29:06Z

← Older revision		Revision as of 22:29, 13 May 2009
Line 1:		Line 1:
	Specs:
			== Specs: ==


	TESLA ENGINEERING: 7 Degree Bend Angle Dipole		TESLA ENGINEERING: 7 Degree Bend Angle Dipole
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	~~----~~

	== CALCULATIONS ==		== CALCULATIONS ==

Oborn: /* CALCULATIONS */

2009-05-13T22:27:25Z

CALCULATIONS

← Older revision		Revision as of 22:27, 13 May 2009
Line 37:		Line 37:
	Table: Data for B=0.0015 T.		Table: Data for B=0.0015 T.
	{\| border="1" cellpadding="2"		{\| border="1" cellpadding="2"
	!width="70"\|~~MOMENTUM~~		!width="70"\|Momentum
	\|-
	!width="70"\|Radius of Curvature		!width="70"\|Radius of Curvature
	!width="70"\|Bend Angle		!width="140"\|Bend Angle
	!width="70"\|Displacement @ end of magnet		!width="70"\|Displacement @ end of magnet

← Older revision		Revision as of 22:41, 13 May 2009
Line 26:		Line 26:
	Magnetic force: <math>F=evB</math>		Magnetic force: <math>F=evB</math>

	The radius of the arc can be through: <math>(mv^2)/R=evB</math>		The radius of the arc can be through: <math>(mv^2)/R=ev*B</math>

	giving: <math>R=mv/eB</math>		giving: <math>R=mv/eB</math>

← Older revision		Revision as of 22:31, 13 May 2009
Line 40:		Line 40:
	!width="70"\|Momentum		!width="70"\|Momentum
	!width="70"\|Radius of Curvature		!width="70"\|Radius of Curvature
	!width="~~140~~"\|Bend Angle		!width="70"\|Bend Angle
			!width="70"\|Bend Angle
	!width="70"\|Displacement @ end of magnet		!width="70"\|Displacement @ end of magnet

← Older revision		Revision as of 22:27, 13 May 2009
Line 37:		Line 37:
	Table: Data for B=0.0015 T.		Table: Data for B=0.0015 T.
	{\| border="1" cellpadding="2"		{\| border="1" cellpadding="2"
	!width="70"\|~~MOMENTUM~~		!width="70"\|Momentum
	\|-
	!width="70"\|Radius of Curvature		!width="70"\|Radius of Curvature
	!width="70"\|Bend Angle		!width="140"\|Bend Angle
	!width="70"\|Displacement @ end of magnet		!width="70"\|Displacement @ end of magnet