Big Red - Revision history

Oborn at 21:20, 15 May 2009

2009-05-15T21:20:33Z

Oborn: /* CALCULATIONS */

2009-05-13T22:46:39Z

CALCULATIONS

Oborn: /* CALCULATIONS */

2009-05-13T22:41:26Z

CALCULATIONS

Oborn: /* CALCULATIONS */

2009-05-13T22:40:25Z

CALCULATIONS

Oborn: /* CALCULATIONS */

2009-05-13T22:39:31Z

CALCULATIONS

Oborn: /* CALCULATIONS */

2009-05-13T22:35:41Z

CALCULATIONS

Oborn: /* CALCULATIONS */

2009-05-13T22:34:10Z

CALCULATIONS

Oborn: /* CALCULATIONS */

2009-05-13T22:31:54Z

CALCULATIONS

Oborn at 22:29, 13 May 2009

2009-05-13T22:29:06Z

Oborn: /* CALCULATIONS */

2009-05-13T22:27:25Z

CALCULATIONS

@@ Line 1: / Line 1: @@
 == Specs: ==
@@ Line 38: / Line 37: @@
 The displacement is found as:	d=R-R*cos(θ)=m*v/e*B*(1-cos(θ))
-Table:  Data for  B=0.0015 T.
+Table:  Data for  B=0.0078 T.
 {| border="1" cellpadding="2"
 !width="70"|Momentum
@@ Line 50: / Line 49: @@
 |P (MeV)||R (m)||θ (radians)||θ (degrees)||d (cm)
 |-
-|1||2.22376032||0.12398179||7.103633471||1.706936726
+|1||0.43||0.70||40.02||10.01
 |-
-|2||4.44752065||0.06187167||3.544985606||0.851006969
+|2||0.86||0.33||18.76||4.54
 |-
-|3||6.67128097||0.04123315||2.362485567||0.567036176
+|3||1.28||0.22||12.38||2.98
 |-
-|4||8.89504129||0.03092103||1.77164444||0.425198022
+|4||1.71||0.16||9.25||2.22
 |-
-|5||11.1188016||0.0247354||1.417234227||0.340129141
+|5||2.14||0.13||7.39||1.78
 |-
-|6||13.3425619||0.02061219||1.180991717||0.283427701
+|6||2.57||0.11||6.15||1.48
 |-
-|7||15.5663223||0.01766726||1.012259595||0.242931183
+|7||2.99||0.09||5.27||1.27
 |-
-|8||17.7900826||0.01545867||0.885716346||0.212560897
+|8||3.42||0.08||4.61||1.11
 |-
-|9||20.0138429||0.01374092||0.787296837||0.18894065
+|9||3.85||0.07||4.10||0.98
 |-
-|10||22.2376032||0.01236676||0.708562916||0.17004506
+|10||4.28||0.06||3.69||0.89
 |-
-|11||24.4613636||0.01124246||0.644145256||0.154585392
+|11||4.70||0.06||3.35||0.80
 |-
-|12||26.6851239||0.01030555||0.590464498||0.141702561
+|12||5.13||0.05||3.07||0.74
 |-
-|13||28.9088842||0.00951279||0.545042725||0.13080185
+|13||5.56||0.05||2.84||0.68
 |-
-|14||31.1326445||0.00883329||0.50611005||0.121458483
+|14||5.99||0.05||2.63||0.63
 |-
-|15||33.3564048||0.00824439||0.472368588||0.113360965
+|15||6.41||0.04||2.46||0.59
 |-
-|16||35.5801652||0.0077291||0.442844944||0.106275686
+|16||6.84||0.04||2.30||0.55
 |}

@@ Line 30: / Line 30: @@
 giving: 		<math>R=m*v/e*B</math>
-The length of the circular arc is  S and the deflection angle is found as:	 <math>sin(θ)=S/R</math>
+The length of the circular arc is  S and the deflection angle is found as:	 sin(θ)=S/R
-For small  θ, and large R, the arc length  S will be approx L, giving:		<math>sin(θ)=L/R=L*e*B/m*v</math>
+For small  θ, and large R, the arc length  S will be approx L, giving:		sin(θ)=L/R=L*e*B/m*v
-Giving    <math>θ=sin^(-1)(c*B*L/p)</math>
+Giving    θ=sin^(-1)(c*B*L/p)
-The displacement is found as:	<math>d=R-R*cos(θ)=m*v/e*B*(1-cos(θ))</math>
+The displacement is found as:	d=R-R*cos(θ)=m*v/e*B*(1-cos(θ))
 Table:  Data for  B=0.0015 T.

@@ Line 26: / Line 26: @@
 Magnetic force:		<math>F=e*v*B</math>
-The radius of the arc can be through:		<math>(mv^2)/R=e*v*B</math>
+The radius of the arc can be through:		<math>(m*v^2)/R=e*v*B</math>
 giving: 		<math>R=m*v/e*B</math>

@@ Line 24: / Line 24: @@
 Electron moves through the magnetic field B accelerated by force F proportional to the component of velocity perpendicular to the field B and velocity   v.  Moves with constant kinetic energy and speed due to the fact that the magnetic field never does work on the particle since the always moves perpendicular to the force.
-Magnetic force:		F=e*v*B
+Magnetic force:		<math>F=e*v*B</math>
 The radius of the arc can be through:		<math>(mv^2)/R=e*v*B</math>

@@ Line 24: / Line 24: @@
 Electron moves through the magnetic field B accelerated by force F proportional to the component of velocity perpendicular to the field B and velocity   v.  Moves with constant kinetic energy and speed due to the fact that the magnetic field never does work on the particle since the always moves perpendicular to the force.
-Magnetic force:		F=evB
+Magnetic force:		F=e*v*B
-The radius of the arc can be through:		<math>(mv^2)/R=evB</math>
+The radius of the arc can be through:		<math>(mv^2)/R=e*v*B</math>
-giving: 		<math>R=mv/eB</math>
+giving: 		<math>R=m*v/e*B</math>
-The length of the circular arc is  S and the deflection angle is found as:	 <math>sin(theta)=S/R</math>
+The length of the circular arc is  S and the deflection angle is found as:	 <math>sin(θ)=S/R</math>
-For small  θ, and large R, the arc length  S will be approx L, giving:		<math>sin(theta)=L/R=LeB/mv</math>
+For small  θ, and large R, the arc length  S will be approx L, giving:		<math>sin(θ)=L/R=L*e*B/m*v</math>
-Giving    <math>θ=sin^(-1)⁡〖 (cBL/p)〗</math>
-The displacement is found as:	<math>d=R-Rcos(theta)=mv/eB(1-cos(theta))</math>
+Giving    <math>θ=sin^(-1)(c*B*L/p)</math>
 Table:  Data for  B=0.0015 T.

@@ Line 20: / Line 20: @@
 '''Calculating the Magnetic Field Needed:'''
-Lorentz Force equation:		F=q(v×B)
+Lorentz Force equation:		<math>F=q(v×B)</math>
 Electron moves through the magnetic field B accelerated by force F proportional to the component of velocity perpendicular to the field B and velocity   v.  Moves with constant kinetic energy and speed due to the fact that the magnetic field never does work on the particle since the always moves perpendicular to the force.
-Magnetic force:		F=evB
+Magnetic force:		<math>F=evB</math>
-The radius of the arc can be through:		(mv^2)/R=evB
+The radius of the arc can be through:		<math>(mv^2)/R=evB</math>
-giving 		R=mv/eB
+giving: 		<math>R=mv/eB</math>
-For small  θ, and large R, the arc length  S will be approx L, giving
+The length of the circular arc is  S and the deflection angle is found as:	 <math>sinθ=S/R</math>
-			sinθ=L/R=LeB/mv
-Giving    θ=sin^(-1)⁡〖 (cBL/p)〗
+For small  θ, and large R, the arc length  S will be approx L, giving:		<math>sinθ=L/R=LeB/mv</math>
-The displacement is found as:	d=R-Rcosθ=mv/eB(1-cosθ)
+Giving    <math>θ=sin^(-1)⁡〖 (cBL/p)〗</math>
 Table:  Data for  B=0.0015 T.

@@ Line 40: / Line 40: @@
 !width="70"|Momentum
 !width="70"|Radius of Curvature
-!width="140"|Bend Angle
+!width="70"|Bend Angle
 !width="70"|Displacement @ end of magnet

@@ Line 1: / Line 1: @@
 Specs:
 TESLA ENGINEERING:  7 Degree Bend Angle Dipole
@@ Line 14: / Line 16: @@
 == CALCULATIONS ==