ArCO2 IonizationPhysics - Revision history

Foretony at 19:07, 21 March 2011

2011-03-21T19:07:03Z

Oborn at 00:02, 10 August 2010

2010-08-10T00:02:21Z

Oborn at 08:50, 20 December 2008

2008-12-20T08:50:56Z

Oborn at 03:33, 19 December 2008

2008-12-19T03:33:37Z

Oborn at 03:30, 19 December 2008

2008-12-19T03:30:45Z

Oborn at 03:22, 19 December 2008

2008-12-19T03:22:01Z

Oborn at 02:51, 19 December 2008

2008-12-19T02:51:50Z

Oborn: New page: $\bar{E}=$ 27 eV = average energy to ionize and electron in an Argon Atom $\bar{N_{PE}} = \frac{E_{\gamma}}{27 eV} =$ average number of photoelectrons produced

2008-12-19T02:33:44Z

New page: <math>\bar{E}=</math> 27 eV = average energy to ionize and electron in an Argon Atom <math>\bar{N_{PE}} = \frac{E_{\gamma}}{27 eV} =</math> average number of photoelectrons produced

New page

<math>\bar{E}=</math> 27 eV = average energy to ionize and electron in an Argon Atom

<math>\bar{N_{PE}} = \frac{E_{\gamma}}{27 eV} =</math> average number of photoelectrons produced

← Older revision		Revision as of 19:07, 21 March 2011
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	A Min Ion Particle traversing Ar gas at 1 atm ionizes 22 atoms/cm Primary and 94-100 Total per cm. The Primary is an ionization from the incident particle, Total includes ionization from secondaries.		A Min Ion Particle traversing Ar gas at 1 atm ionizes 22 atoms/cm Primary and 94-100 Total per cm. The Primary is an ionization from the incident particle, Total includes ionization from secondaries.

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	:You need 3.203 keV to ionize a K-shell electron in Argon. If your incident ionizing particle (photon or electron) has more than that energy then it is possible to excite Argon so it becomes a source of photons (X-rays) during the ionization process. The Ar-Ka (2.958 keV) X-ray is one likely X-ray. If that photon ESCAPEs the detector without causing ionization, then your signal will contain less ionized electrons. The process is such that during the ionizing of multiple Argon atoms by a photon loosing energy to the gas, the photon will excite one Argon atom such that it emits an X-ray which excapes the chamber.		:You need 3.203 keV to ionize a K-shell electron in Argon. If your incident ionizing particle (photon or electron) has more than that energy then it is possible to excite Argon so it becomes a source of photons (X-rays) during the ionization process. The Ar-Ka (2.958 keV) X-ray is one likely X-ray. If that photon ESCAPEs the detector without causing ionization, then your signal will contain less ionized electrons. The process is such that during the ionizing of multiple Argon atoms by a photon loosing energy to the gas, the photon will excite one Argon atom such that it emits an X-ray which excapes the chamber.
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		+	[[File:FirstQweakData_HV3400Volts_ChargeLeavingLastGEMFoil_4-04-09-Datafile_r877.gif]]

← Older revision		Revision as of 00:02, 10 August 2010
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		+
		+	A Min Ion Particle traversing Ar gas at 1 atm ionizes 22 atoms/cm Primary and 94-100 Total per cm. The Primary is an ionization from the incident particle, Total includes ionization from secondaries.
		+
	<math>\bar{E}=</math> 27 eV = average energy to ionize an electron in an Argon Atom		<math>\bar{E}=</math> 27 eV = average energy to ionize an electron in an Argon Atom

← Older revision		Revision as of 08:50, 20 December 2008
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−	<math>\bar{E}=</math> 27 eV = average energy to ionize ~~and~~ electron in an Argon Atom	+	<math>\bar{E}=</math> 27 eV = average energy to ionize an electron in an Argon Atom

	<math>\bar{N_{PE}} = \frac{E_{\gamma}}{27 eV} =</math> average number of photoelectrons produced		<math>\bar{N_{PE}} = \frac{E_{\gamma}}{27 eV} =</math> average number of photoelectrons produced

← Older revision		Revision as of 03:33, 19 December 2008
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	;Argon Escape peak:		;Argon Escape peak:

−	:You need 3.203 keV to ionize a K-shell electron in Argon. If your incident ionizing particle (photon or electron) has more than that energy then it is possible to excite Argon so it becomes a source of photons (X-rays) during the ionization process. The Ar-Ka (2.958 keV) X-ray is one likely X-ray. If that photon ESCAPEs the detector without causing ionization, then your signal will contain less ionized electrons. The process is such that during the ionizing of multiple Argon atoms by a photon loosing energy to the gas, the photon will excite one Argon atom such that it emits ~~and~~ X-ray which excapes the chamber.	+	:You need 3.203 keV to ionize a K-shell electron in Argon. If your incident ionizing particle (photon or electron) has more than that energy then it is possible to excite Argon so it becomes a source of photons (X-rays) during the ionization process. The Ar-Ka (2.958 keV) X-ray is one likely X-ray. If that photon ESCAPEs the detector without causing ionization, then your signal will contain less ionized electrons. The process is such that during the ionizing of multiple Argon atoms by a photon loosing energy to the gas, the photon will excite one Argon atom such that it emits an X-ray which excapes the chamber.

← Older revision		Revision as of 03:30, 19 December 2008
Line 15:		Line 15:
	;Argon Escape peak:		;Argon Escape peak:

−	:You need 3.203 keV to ionize a K-shell electron in Argon. If your incident ionizing particle (photon or electron) has more than that energy then it is possible to excite Argon so it becomes a source of photons (X-rays) during the ionization process. The Ar-Ka (2.958 keV) X-ray is ~~most~~ likely. If that photon ESCAPEs the detector without causing ionization, then your signal will contain less ionized electrons. The process is such that during the ionizing of multiple Argon atoms, the photon will excite one Argon atom	+	:You need 3.203 keV to ionize a K-shell electron in Argon. If your incident ionizing particle (photon or electron) has more than that energy then it is possible to excite Argon so it becomes a source of photons (X-rays) during the ionization process. The Ar-Ka (2.958 keV) X-ray is one likely X-ray. If that photon ESCAPEs the detector without causing ionization, then your signal will contain less ionized electrons. The process is such that during the ionizing of multiple Argon atoms by a photon loosing energy to the gas, the photon will excite one Argon atom such that it emits and X-ray which excapes the chamber.

← Older revision		Revision as of 03:22, 19 December 2008
Line 15:		Line 15:
	;Argon Escape peak:		;Argon Escape peak:

−	:You need 3.2 keV to ionize a K-shell electron in Argon. If your incident ionizing particle (~~Photon~~ or electron) has more than that energy then it is possible to excite Argon so it becomes a source of photons during the ionization process. If that photon ESCAPEs the detector without causing ionization, then your signal will be contain less ionized electrons.	+	:You need 3.203 keV to ionize a K-shell electron in Argon. If your incident ionizing particle (photon or electron) has more than that energy then it is possible to excite Argon so it becomes a source of photons (X-rays) during the ionization process. The Ar-Ka (2.958 keV) X-ray is most likely. If that photon ESCAPEs the detector without causing ionization, then your signal will contain less ionized electrons. The process is such that during the ionizing of multiple Argon atoms, the photon will excite one Argon atom

← Older revision		Revision as of 02:51, 19 December 2008
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−
	<math>\bar{E}=</math> 27 eV = average energy to ionize and electron in an Argon Atom		<math>\bar{E}=</math> 27 eV = average energy to ionize and electron in an Argon Atom

	<math>\bar{N_{PE}} = \frac{E_{\gamma}}{27 eV} =</math> average number of photoelectrons produced		<math>\bar{N_{PE}} = \frac{E_{\gamma}}{27 eV} =</math> average number of photoelectrons produced
		+
		+	Quenching Gas:
		+
		+	1.) reduces the influence of the positive ions creates on the photoelectron signal: The excited Ar+ atoms emit photon in the UV range which are absorbed by the quenching gas
		+
		+	2.)Collisions with the quenching gas will neutralize the Ar+ ions. When the quenched gas, having an electron remove by the Ar+ collision, reaches the cathode and collects an electron, most of the energy goes into dissociation of the Quench gas.
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		+	If the quech gas is CH4 then
		+
		+	CH4+ <math>\Rightarrow</math> H2 + CH2
		+
		+	;Argon Escape peak:
		+
		+	:You need 3.2 keV to ionize a K-shell electron in Argon. If your incident ionizing particle (Photon or electron) has more than that energy then it is possible to excite Argon so it becomes a source of photons during the ionization process. If that photon ESCAPEs the detector without causing ionization, then your signal will be contain less ionized electrons.