Calculating the cross section for thorium-232 depending on the hadron fission class under Incl-Abla cascade interface.
   
    cross section= (the No. of fissions events)/(The number of the incident neutrons/Area)
    
                 = n/(N/A)
                 = n/(N*l/V)    V:volume   l: thickness
                 = n/((N*l)/(m/d)   m:mass d: density
                 = n*m/N*l*d
                 =n*m/100*10*11.72
                 
            the atomic radius of Th-232 = 179.8 pm
           
           
            The number of atoms in 10 cm = 0.1/2 * 179.8*10^-12 =2.79*10^8 atom
                                                            = 4.64*10^-16 mol * 232.04
                                                            = 1.08*10^-13 g
     cross section = n * 1.08*10^-13/100 * 10 * 11.72
                   =  n * 1.8*10^-18   cm^-2
                   = n * 1.8*10^6
                   
                    
       Table for the value of the energy and the value for he cross section for that energy                                                      

E      xsection*10^6
22	9
21	3.6		    
20      27
19      9
18	16.2
17	12.6
16	9
15	18
14	5.4
13	9
12	1.8
11	16.2
10	5.4
9	7.2
8	14.4
7	9
6	5.4
5	1.8
4       1.8
3       5.4
2	3.6
1	1.8